/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q19P At a certain time, a particle ha... [FREE SOLUTION] | 91影视

91影视

Log out

Learning Materials

Features

Discover

Chapter 2: Q19P (page 33)

At a certain time, a particle had a speed of18m/sin positive x direction, and 2.4 slater, its speed was 30 m/s in the opposite direction. What is the average acceleration of particle during this 2.4 sinterval?

Short Answer

Expert verified

Average acceleration of particle during 2.4s is -20m/s2

Step by step solution

01

Given

vi=+18m/svf=-3.0m/s

t1=0s, (instance at which we started observing the particle) and

t2=2.4s

02

To understanding the concept

The problem deals with the average acceleration which refers to the rate at which the velocity changes. Average acceleration can be found using the formula for the average acceleration and given data.

Formula:

The average acceleration is given by,

aavg=鈭�V鈭�t

03

the average acceleration of particle during this 2.4 s interval

Using average acceleration equation we get,

aavg=鈭�V鈭�t=vft2-viti2.4-0=-20m/s2

Average acceleration calculated is-20m/s2 and the magnitude is 20m/s2.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

The 1992 world speed record for a bicycle (human powered vehicle) was set by Chris Huber. His time through the measured 200 m stretch was a sizzling 6.509 sec , at which he commented 鈥淐ogito ergo zoom!鈥� (I think, therefore I go fast). In 2001, Sam Whittingham beat Huber鈥檚 record by 19.0 km/h. What was Whittingham鈥檚 time through the 200 m?

(a) If the position of a particle is given byx=20t-5t2, where x is in m and t in secwhen, if ever, the particle鈥檚 velocity is zero? (b) When is its acceleration a zero? (c) For what time range (positive or negative) is a negative? (d) Positive? (e) Graph x(t), v(t) and a(t).

In 1889, at Jubbulpore, India, a tug-of-war was finally won after role="math" localid="1654754892705" 2h41min, with the winning team displacing the center of the rope 3.7m. In centimeters per minute, what was the magnitude of the average velocity of that center point during the contest?

Question:A car moves uphill at 40 km/hand then back downhill at 60 km/h. What is the average speed for the round trip?

A hot rod can accelerate from 0to60km/hin5.4s.(a) What is its average acceleration, in m/s2, during this time? (b) How far will it travel during the, assuming its acceleration is constant? (c) From rest, how much time would it require to go a distance of 0.25 kmif its acceleration could be maintained at the value in (a)?
See all solutions

Recommended explanations on Physics Textbooks

Physical Quantities And Units

Read Explanation

Circular Motion and Gravitation

Read Explanation

Conservation of Energy and Momentum

Read Explanation

Medical Physics

Read Explanation

Linear Momentum

Read Explanation

Magnetism and Electromagnetic Induction

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.