/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q3P For an electron, apply the relat... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

For an electron, apply the relationship between the de Broglie wavelength and the kinetic energy.

Short Answer

Expert verified

The relationship between the de Broglie wavelength and the kinetic energyis

λ=h2mk

Step by step solution

01

Understanding de Broglie wavelength:

Wavelength in physics may be defined as the distance of one crest to another crest of a wave. Now according to Louis de Broglie, every particle follows wave nature.

02

Relationship between de Broglie's wavelength and Momentum:

An electron has a wavelength λ, and the wavelength depends on its momentum p; hence you can write,

λ=hp ….. (1)

Here, h is called the Plancks constant, and λis called the de Broglie's wavelength.

03

Relationship between Momentum and Kinetic Energy of the electron.

We know that as a body's kinetic energy K increases, it results in the rise of momentum p. Therefore, the kinetic energy of an electron directly depends on Momentum, Hence,

k=p22mp2=2mkp=2mk

….. (2)

Here, m is the mass of the electron.

04

Relationship between de Broglie's wavelength and Kinetic Energy of the electron.

By putting the value of equation (2) in equation (1), you get

λ=h2mk

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Calculate the probability that the electron in the hydrogen atom, in its ground state, will be found between spherical shells whose radii are a and 2a , where a is the Bohr radius?

one-dimensional infinite well of length 200 pm contains an electron in its third excited state. We position an electron detector probe of width 2.00 pm so that it is centred on a point of maximum probability density. (a) What is the probability of detection by the probe? (b) If we insert the probe as described 1000 times, how many times should we expect the electron to materialize on the end of the probe (and thus be detected)?

What is the probability that in the ground state of hydrogen atom , the electron will be found at a radius greater than the Bohr radius?

Consider a conduction electron in a cubical crystal of a conducting material. Such an electron is free to move throughout the volume of the crystal but cannot escape to the outside. It is trapped in a three-dimensional infinite well. The electron can move in three dimensions so that its total energy is given by

E=h28L2m(n12+n22+n32)

in whichare positive integer values. Calculate the energies of the lowest five distinct states for a conduction electron moving in a cubical crystal of edge length L=0.25μm.

Schrodinger’s equation for states of the hydrogen atom for which the orbital quantum number l is zero is

1r2ddr(r2dψdr)+8ττ2mr2[E-Ur]ψ=0

Verify that Eq. 39-39, which describes the ground state of the hydrogen atom, is a solution of this equation?

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.