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At time t= 0, a 2.0kgparticle has the position vectorr=4.0mi^-2.0mj^relative to the origin. Its velocity is given byv=-6.0t2m/si^fort0in seconds. About the origin, (a) What are the particle鈥檚 angular momentumL?(b)What are the torque acting on the particle, both in unit-vector notation and fort>0? (c) About the point-2.0m,-3.0m,0,what areL?(d) About the pointwhat are for t0?

Short Answer

Expert verified
  1. The body鈥檚 rotational inertia about the rotational axis through its center of mass isI=12mR2.
  2. The body could be a solid cylinder.

Step by step solution

01

Step 1: Given

Body of radius isR ,

Mass isM

Speed of the body isrole="math" localid="1663218026097" v .

02

Determining the concept

Using the formula for mechanical energy conservation, find the body鈥檚 rotational inertia about the rotational axis through its center of mass. According to conservation of energy, energy can neither be created, nor be destroyed.

Formulae are as follow:

K=12mvcom2

K=12I2

U=Mgh

where,is angular frequency, g is an acceleration due to gravity, h is height, Iis moment of inertia, m, M are masses,vcomis velocity of centre of mass, U is potential energy and K is kinetic energy.

03

(a) Determining the body’s rotational inertia about the rotational axis through its center of mass

Now,

Ki=Uf

12mvcom2+12I2=Mgh

12mv2+12IvR2=mg3V24g

I=12mR2

Hence,the body鈥檚 rotational inertia about the rotational axis through its center of mass is I=12mR2.

04

(b) Determining the shape of the body

From rotational inertia, it can be seen that the body could be a solid cylinder.

Hence,the body could be a solid cylinder.

Therefore, using the conservation of energy, the rotational inertia of the given object can be found. It can be checked that which object has the same formula for the rotational inertia and it can be decided the type of object.

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