91影视

$m=6\text{g}$

$$\begin{gathered} v=4\raisebox{1ex}{$\text{km}$}\!\left/ \!\raisebox{-1ex}{$\text{s}$}\right. \\ \stackrel{鈫�}{B}=5.0\hat{i}\text{mT} \\ 胃={37}^{\text{o}} \\ \stackrel{鈫�}{F}=0.48\hat{k}\text{N} \end{gathered}$$

The influence of a magnetic field produced by one charge on another is what is known as the magnetic force between two moving charges.

By using the relation between the magnetic force , velocity of particle and magnetic field applied, we can find the charge on the particle.

Formula:

$\stackrel{鈫�}{F}=q\stackrel{鈫�}{v}脳\stackrel{鈫�}{B}$

By using equation 28-2, we can see that the force is along positive$\hat{k}$. But the magnetic field in positive $\hat{i}.$So the particle velocity is along positive y axis. Hence, the particle is negative. Now examining the magnitude by using the 28-3, we find

$\stackrel{鈫�}{|F}\left|=\left|q\right|v\right|\stackrel{鈫�}{B}|sin蠒$

By substituting the value, we can get

$0.48鈥�\text{N}=\left|q\right|\left(4000鈥�\text{m/s}\right)\left(0.0050鈥�\text{T}\right)\text{sin}37掳$

$\left|q\right|=0.04\text{C}$

But from the discussion, we can conclude that this charge is negative.

$q=-0.04\text{C}$