Q51P The saturation magnetization Mm... [FREE SOLUTION]

91影视

Chapter 32: Q51P (page 970)

The saturation magnetization $M_{\max}$ of the ferromagnetic metal nickel is $4.70 脳 10^{5} A / m$ . Calculate the magnetic dipole moment of a single nickel atom. (The density of nickel is $8.90 g / {cm}^{3}$ , and its molar mass is $58.71 g / mol$ .)

Short Answer

Expert verified

Magnetic dipole moment of a single nickel atom is, $渭_{B} = 5.15 脳 10^{- 24} A m^{2}$ .

Step by step solution

Listing the given quantities

Saturation magnetization $M_{\max} = 4.70 脳 10^{5} A / m$

Density of nickel is $蚁 = 8.90 g / {cm}^{3}$

Molar mass of nickel is $58.71 g / mole$

Understanding the concepts of magnetic dipole moment

We use the concept of magnetic dipole moment. Using the equations, we findthenumber of atoms per unit volume, and then we can findthemagnetic dipole moment.

Formulae:

$渭_{B} = \frac{M_{\max}}{n}$

$n = \frac{{蚁N}_{A}}{M}$

Calculations of the magnetic dipole moment of a single nickel atom

We find the number of atoms per unit volume.

Using equation

$\begin{matrix} n = \frac{{蚁N}_{A}}{M} \\ = \frac{(8.90) (6.023 脳 10^{23})}{58.71} \\ = 9.126 脳 10^{22} \frac{atoms}{{cm}^{3}} \end{matrix}$

We can convert it in $atoms / m^{3}$ .We can write

$\begin{matrix} n = 9.126 脳 10^{22} \frac{atoms}{{cm}^{3}} 脳 {(\frac{1 cm}{10^{- 2} m})}^{3} \\ = 9.126 脳 10^{22} \frac{atoms}{{cm}^{3}} 脳 1 \frac{{cm}^{3}}{10^{- 6} m^{3}} \\ = 9.126 脳 10^{28} \frac{atoms}{m^{3}} \end{matrix}$

Substituting this value in magnetic dipole moment,

$\begin{matrix} 渭_{B} = \frac{M_{\max}}{n} \\ = \frac{4.70 脳 10^{5}}{9.126 脳 10^{28}} \\ = 5.15 脳 10^{- 24} A m^{2} \end{matrix}$

Magnetic dipole moment of a single nickel atom is, $渭_{B} = 5.15 脳 10^{- 24} A m^{2}$ .

Unlock Step-by-Step Solutions & Ace Your Exams!

Full Textbook Solutions
Get detailed explanations and key concepts
Unlimited Al creation
Al flashcards, explanations, exams and more...
Ads-free access
To over 500 millions flashcards
Money-back guarantee
We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

91影视

The saturation magnetization $M_{\max}$ of the ferromagnetic metal nickel is $4.70 脳 10^{5} A / m$ . Calculate the magnetic dipole moment of a single nickel atom. (The density of nickel is $8.90 g / {cm}^{3}$ , and its molar mass is $58.71 g / mol$ .)

Short Answer

Step by step solution

Listing the given quantities

Understanding the concepts of magnetic dipole moment

Calculations of the magnetic dipole moment of a single nickel atom

One App. One Place for Learning.

Most popular questions from this chapter

Recommended explanations on Physics Textbooks

Geometrical and Physical Optics

Force

Classical Mechanics

Rotational Dynamics

Dynamics

Electric Charge Field and Potential

Study anywhere. Anytime. Across all devices.

91影视

The saturation magnetization Mmax of the ferromagnetic metal nickel is4.70脳105A/m . Calculate the magnetic dipole moment of a single nickel atom. (The density of nickel is8.90g/cm3, and its molar mass is58.71g/mol .)

Short Answer

Step by step solution

Listing the given quantities

Understanding the concepts of magnetic dipole moment

Calculations of the magnetic dipole moment of a single nickel atom

One App. One Place for Learning.

Most popular questions from this chapter

Recommended explanations on Physics Textbooks

Geometrical and Physical Optics

Force

Classical Mechanics

Rotational Dynamics

Dynamics

Electric Charge Field and Potential

Study anywhere. Anytime. Across all devices.

The saturation magnetization $M_{\max}$ of the ferromagnetic metal nickel is $4.70 脳 10^{5} A / m$ . Calculate the magnetic dipole moment of a single nickel atom. (The density of nickel is $8.90 g / {cm}^{3}$ , and its molar mass is $58.71 g / mol$ .)