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Chapter 28: Q 8P (page 829)

Question: An electric field of1.50kV/mand a perpendicular magnetic field of 0.400Tact on a moving electron to produce no net force. What is the electron鈥檚 speed?

Short Answer

Expert verified

The electron鈥檚 speed is |v|=3.75x103m/s.

Step by step solution

01

Given

蠒=90.0鈭�E=1.50kVm=1.50x103V/mB=0.400TF=0

02

Determining the concept

Find the velocity of an electron by inserting the given values in the formula for electromagnetic force.

Formulae are as follow:

F=eE+evBsin蠒

Where, F is force, v is velocity, E is electric field, B is magnetic field, e is charge of particle.

03

Determining the speed of electron

The electromagnetic force experienced by an electron is,

F=eE+evBsin蠒

Inserting given values,

0=-1.6脳10-19脳1.50脳103+-1.6脳10-19脳v脳0.400脳sin90鈭�0=-1.6脳10-19脳1.50脳103-1.6脳10-19脳v脳0.400脳sin90鈭�v=1.50脳1030.400v=3.75脳103m/s

Hence, the electron鈥檚 speed is v=3.75脳103m/s.

Therefore, the velocity of an electron can be determined by inserting the given values in the formula for electromagnetic force.

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Most popular questions from this chapter

A 13.0g wire of length L = 62.0 cm is suspended by a pair of flexible leads in a uniform magnetic field of magnitude 0.440T (Fig. 28-41). What are the (a) magnitude and (b) direction (left or right) of the current required to remove the tension in the supporting leads?

Figure 28-25 shows the path of a particle through six regions of uniform magnetic field, where the path is either a half-circle or a quarter-circle. Upon leaving the last region, the particle travels between two charged, parallel plates and is deflected toward the plate of higher potential. What is the direction of the magnetic field in each of the six regions?

A proton, a deuteron (q=+e, m=2.0u), and an alpha particle (q=+2e, m=4.0u) are accelerated through the same potential difference and then enter the same region of uniform magnetic field, moving perpendicular to . What is the ratio of (a) the proton鈥檚 kinetic energy Kp to the alpha particle鈥檚 kinetic energy Ka and (b) the deuteron鈥檚 kinetic energy Kd to Ka? If the radius of the proton鈥檚 circular path is 10cm, what is the radius of (c) the deuteron鈥檚 path and (d) the alpha particle鈥檚 path

Question: In Fig. 28-57, the two ends of a U-shaped wire of mass m=10.0gand length L=20.0cmare immersed in mercury (which is a conductor).The wire is in a uniform field of magnitude B=0.100T. A switch (unshown) is rapidly closed and then reopened, sending a pulse of current through the wire, which causes the wire to jump upward. If jump height h=3.00m, how much charge was in the pulse? Assume that the duration of the pulse is much less than the time of flight. Consider the definition of impulse (Eq. 9-30) and its relationship with momentum (Eq. 9-31). Also consider the relationship between charge and current (Eq. 26-2).

A particular type of fundamental particle decays by transforming into an electron e鈭�and a positron e+. Suppose the decaying particle is at rest in a uniform magnetic field of magnitude3.53mT and the e鈭� and e+move away from the decay point in paths lying in a plane perpendicular to B鈫� . How long after the decay do the e鈭� and e+collide?
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