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Chapter 35: Q5P (page 1074)

How much faster, in meters per second, does light travel in sapphire than in diamond? See Table 33-1.

Short Answer

Expert verified

The difference in speed is 4.55脳107ms.

Step by step solution

01

Definition of refractive index.

The refractive index of any medium signifies the bending ability of light in that perticular medium. Hence, the medium is more refractive, and the bending of the light in that medium will also be more.

02

Determine of change in speed of the light with the change of the medium.

From the table 33-1, we get the refractive index of diamond and sapphire as:

The refractive index of diamond isnd=2.42

The refractive index of sapphire isns=1.77

The formulae for calculating the change in velocity 螖vwith the change in the medium are:

螖v=vs-vd=c1ns-1nd

Here, vsis the speed of light in the sapphire medium and vdthe speed of light in the diamond medium.

C is the speed of light in the vaccum.

Therefore,

螖v=3脳10811.77-12.42=4.55脳107ms

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Most popular questions from this chapter

Figure 35-40 shows two isotropic point sources of light (S1and S2) that emit in phase at wavelength 400 nm and at the same amplitude. A detection point P is shown on an x-axis that extends through source S1. The phase difference 蠒between the light arriving at point P from the two sources is to be measured as P is moved along the x axis from x=0 out to x=+鈭�.The results out to xs=10脳10-7m are given in Fig. 35-41. On the way out to +鈭� , what is the greatest value of x at which the light arriving at from S1is exactly out of phase with the light arriving at P from S2?

In a double-slit experiment, the distance between slits is5.0mm and the slits are 1.0m from the screen. Two interference patterns can be seen on the screen: one due to light of wavelength 480nm, and the other due to light of wavelength 600nm. What is the separation on the screen between the third-order (m=3) bright fringes of the two interference patterns?

In Fig. 35-40, two isotropic point sources of light (S1 and S2) are separated by distance 2.70渭malong a y axis and emit in phase at wavelength 900 nm and at the same amplitude. A light detector is located at point P at coordinate xPon the x axis. What is the greatest value of xP at which the detected light is minimum due to destructive interference?

If the distance between the first and tenth minima of a double-slit pattern is 18.0 mm and the slits are separated by 0.150 mm with the screen 50.0 cm from the slits, what is the wavelength of the light used?

In the two-slit experiment of Fig.35-10, let angle 胃be 20.00C, the slit separation be 4.24渭m, and the wavelength be 位=500nm. (a) What multiple of 位gives the phase difference between the waves of rays r1and r2when they arrive at point Pon the distant screen? (b) What is the phase difference in radians? (c) Determine where in the interference pattern point P lies by giving the maximum or minimum on which it lies, or the maximum and minimum between which it lies?
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