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Suppose that Young’s experiment is performed with blue-green light of wavelength 500 nm. The slits are 1.20 mm apart, and the viewing screen is 5.40 m from the slits. How far apart are the bright fringes near the center of the interference pattern?

Short Answer

Expert verified

The bright fringes near the center of the interference pattern are apart of 2.25 mm.

Step by step solution

01

Write the given data from the question

Blue-green light Wavelength, λ=500nm.

The slit separation, d=1.20mm.

The screen distance from the slit, D=5.4m.

02

Determine the formulas to calculate how far apart the bright fringes near the center of the interference pattern

The condition for the maxima in Young’s experiment is given as follows.

dsinθ=mλ …… (1)

Here, d is the distance between the slits, λis the wavelength, mis the order, andθis the angular separation.

03

Calculate how far apart the bright fringes near the center of the interference pattern

The maximum vertical distance from the center of the pattern is given by,

tanθ≈sinθ=ymD

Substitute ymDfor sinθinto equation (1).

dymD=mλym=mλDd

Substitute 1 for m, 54 m for D, 500 nm for λand 1.20mmfor d into above equation.

ym=1×500×10-9×5.41.2×10-3=27×10-71.2×10-3=22.5×10-4m=2.25mm.

Hence the bright fringes near the center of interference pattern are apart of 2.25 mm.

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Most popular questions from this chapter

Suppose that the two waves in Fig. 35-4 have a wavelength λ=500nmin air. What multiple of λgives their phase difference when they emerge if (a) n1=1.50, n2=16and L=8.50μm; (b) n1=1.62, n2=1.72, and L=8.50μm; and (c) n1=1.59, n2=1.79, and L=3.25μm? (d) Suppose that in each of these three situations, the waves arrive at a common point (with the same amplitude) after emerging. Rank the situations according to the brightness the waves produce at the common point.

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