/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q7P In Figure, the magnetic flux thr... [FREE SOLUTION] | 91影视

91影视

In Figure, the magnetic flux through the loop increases according to the relation B=6.0t2+7.0t, whereBis in milli-Weber and t is in seconds. (a) What is the magnitude of the emf induced in the loop when t = 2.0 s? (b) Is the direction of the current through R to the right or left?

Short Answer

Expert verified

a. The magnitude of the emf induced in the loop is 31 mV.

b. The direction of the current through R is left.

Step by step solution

01

Given

Magnetic flux through the loop is =6.0t2+7.0t

02

Determining the concept

By using Faraday鈥檚 law and Lenz鈥檚 law, find the emf induced and the direction of the current.

Faraday'slaw of electromagnetic induction states, Whenever a conductor is placed in a varying magnetic field, an electromotive force is induced in it.

Lenz's law states that the current induced in a circuit due to a change in a magnetic field is directed to oppose the change in flux and to exert a mechanical force that opposes the motion.

Formulae are as follows:

=-ddt

Where,dis magnetic flux, 饾渶 is emf, dt is time.

03

(a) Determining the magnitude of the emf induced in the loop when t = 2.0 s

It is given that the changing flux through the loop is=6.0t2+7.0t. Hence, the emf induced in the loop can be calculated as,

Faraday鈥檚 law is,

=-ddt=-ddt6.0t2+7.0t=-26.0t+7.0

At t = 2 s

=-26.02+7.0=-31mV

Hence, the magnitude of the emf induced in the loop is 31 mV.

04

(b) Determining the direction of the current through R

According to Lenz鈥檚 law, the current i induced in a loop has the direction such that the current鈥檚 magnetic field B opposes the change in the magnetic field inducing the current i.

Here, the magnetic field increases in the direction out of the page. Thus, the current through the resistance in the left direction will produce the magnetic field on the page.

Hence, the direction of the current must be left.

Therefore, by using the concept of Len鈥檚 law and Faraday鈥檚 law, the emf induced and direction of current can be determined.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A wire is bent into three circular segments, each of radius r=10 cm, as shown in Figure. Each segment is a quadrant of a circle, ab lying in the xy plane, bc lying in the yz plane, and ca lying in the zx plane. (a) If a uniform magnetic fieldBpoints in the positive x direction, what is the magnitude of the emf developed in the wire when B increases at the rate of 3.0 mT/s? (b) What is the direction of the current in segment bc?

The inductance of a closely packed coil of 400 turnsis 8.0 mH. Calculate the magnetic flux through the coil when the current is 5.0 mA.

The current i through a 4.6 Hinductor varies with time t as shown by the graph of Figure, where the vertical axis scale is set by is=8.0A and the horizontal axis scale is set by ts=6.0ms . The inductor has a resistance of12.(a) Find the magnitude of the induced emf during time intervals 0 to 2 ms. (b) Find the magnitude of the induced emf during time intervals 2 ms to 5 ms. (c) Find the magnitude of the induced emf during time intervals 5 ms to 6 ms. (Ignore the behavior at the ends of the intervals.)

In Fig. 30-26, a wire loop has been bent so that it has three segments: segment bc(a quarter-circle), ac(a square corner), and ab(straight). Here are three choices for a magnetic field through the loop:

(1)B1=3i^+7j^-5tk^,(2)B2=5ti^-4j^-15k^,(3)B3=2i^-5tj^-12k^,

where Bis in milliteslas and tis in seconds. Without written calculation, rank the choices according to (a) the work done per unit charge in setting up the induced current and (b) that induced current, greatest first. (c) For each choice, what is the direction of the induced current in the figure?

In the circuit of Fig. 30-76, R1=20k,R2=20,L=50mHand the ideal battery has =40V. Switch S has been open for a long time when it is closed at time t=0. Just after the switch is closed, what are (a) the current ibatthrough the battery and (b) the rate dibatdt? At t=3.0s, what are (c) ibatand (d) dibatdt? A long time later, what are (e) ibatand (f) dibatdt?

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.