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In Figure, the magnetic flux through the loop increases according to the relation B=6.0t2+7.0t, whereBis in milli-Weber and t is in seconds. (a) What is the magnitude of the emf induced in the loop when t = 2.0 s? (b) Is the direction of the current through R to the right or left?

Short Answer

Expert verified

a. The magnitude of the emf induced in the loop is 31 mV.

b. The direction of the current through R is left.

Step by step solution

01

Given

Magnetic flux through the loop is =6.0t2+7.0t

02

Determining the concept

By using Faraday鈥檚 law and Lenz鈥檚 law, find the emf induced and the direction of the current.

Faraday'slaw of electromagnetic induction states, Whenever a conductor is placed in a varying magnetic field, an electromotive force is induced in it.

Lenz's law states that the current induced in a circuit due to a change in a magnetic field is directed to oppose the change in flux and to exert a mechanical force that opposes the motion.

Formulae are as follows:

=-ddt

Where,dis magnetic flux, 饾渶 is emf, dt is time.

03

(a) Determining the magnitude of the emf induced in the loop when t = 2.0 s

It is given that the changing flux through the loop is=6.0t2+7.0t. Hence, the emf induced in the loop can be calculated as,

Faraday鈥檚 law is,

=-ddt=-ddt6.0t2+7.0t=-26.0t+7.0

At t = 2 s

=-26.02+7.0=-31mV

Hence, the magnitude of the emf induced in the loop is 31 mV.

04

(b) Determining the direction of the current through R

According to Lenz鈥檚 law, the current i induced in a loop has the direction such that the current鈥檚 magnetic field B opposes the change in the magnetic field inducing the current i.

Here, the magnetic field increases in the direction out of the page. Thus, the current through the resistance in the left direction will produce the magnetic field on the page.

Hence, the direction of the current must be left.

Therefore, by using the concept of Len鈥檚 law and Faraday鈥檚 law, the emf induced and direction of current can be determined.

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