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Chapter 30: Q45P (page 899)

At a given instant the current and self-induced emf in an inductor are directed as indicated in Figure. (a) Is the current increasing or decreasing? (b) The induced emf is 17 V, and the rate of change of the current is 25 KA/s; find the inductance.

Short Answer

Expert verified
  1. Rate of change of the current,

didt=25.0kA/s=25脳103A/s

b. Induced emf, o,=17.0 V

Step by step solution

01

Understanding the concept

We can use Faraday鈥檚 law of electromagnetic induction and the definition of inductance to find the inductance of the coil.

Formula:

o,=-d蠒Bdt

蠒B=Li

02

(a) Find out if the is current increasing or decreasing 

At a given instant self-induced emf and current are directed towards the right of the page

So, the inductor will oppose the change in current, therefore current will be decreasing.

03

(b) Calculate the inductance

We have,

o,=-d蠒Bdt=-ddtLi=-Ldidt

Now taking the magnitude of above equation we get

L=o,didtL=17.025脳103L=0.68脳10-3H=6.8脳10-4H

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