/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q13P One hundred turns of (insulated)... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

One hundred turns of (insulated) copper wire are wrapped around a wooden cylindrical core of cross-sectional area 1.20×10-3m2. The two ends of the wire are connected to a resistor. The total resistance in the circuit is13.0Ω. If an externally applied uniform longitudinal magnetic field in the core changes from 1.60 Tin one direction to1.60 T in the opposite direction, how much charge flows through a point in the circuit during the change?

Short Answer

Expert verified

The charge flowing through a point in the circuit during the change in magnetic field is, q(t)=2.95×10-2C

Step by step solution

01

Step 1: Given

  1. Cross-sectional area,A=1.20×10-3m2
  2. Resistance, R=13.0Ω
  3. Magnetic field at core, B (0) = 1.60 T
  4. Magnetic field at other end in opposite direction, B (t) = (-1.60 T)
02

Determining the concept

The magnetic flux φBthrough area Ain a magnetic field is given by Faraday’s law of induction. If the magnetic fieldB→is perpendicular to the area A, thensubstitute the given values in the formula to find the charge.

Faraday'slaw of electromagnetic inductionstates, Whenever a conductor is placed in a varying magnetic field, an electromotive force is induced in it.

Formulae are as follows:

emf=-N.dφdt

Where,dΦ is magnetic flux, N is number of turns, dt is time.

03

Determining the charge flowing through a point in the circuit during the change in magnetic field

According to Faraday’s law,

emf=-N.dφdt

From Ohm’s law, emf = i.R and i = dq/dt

∴i.R=-N.dφdt

dqdt=-N.dφdt

Integrating this with respect to time,

qt0t=-Nφt0t

To calculate the charge flowing through the point,

qt=NRφB0-φBt

According to Faraday’s law, if the magnetic field B→is perpendicular to the area A, then,

φB=BA

Therefore,

qt=NARB0-Btqt=100×1.20×10-3m213.0Ω16.0T--1.60Tqt=100×0.0923×10-3m2×3.20qt=2.95×10-2C

Hence, the charge flowing through a point in the circuit during the change in magnetic field is,q(t)=2.95×10-2C

Therefore, the charge flow through a point in the circuit during the change in the magnetic field can be found by using Faraday’s law.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

How long would it take, following the removal of the battery, for the potential difference across the resistor in an RL circuit (with L = 2.00H, R = 3.00) to decay to 10.0% of its initial value?

The current in an RL circuit drops from1.0 A to 10 mA in the first second following removal of the battery from the circuit. If L is10 H, find the resistance R in the circuit.

Figure (a) shows a circuit consisting of an ideal battery with emf ε=6.00mV, a resistance R, and a small wire loop of area 500cm2. For the time interval t = 10 s to t = 20 s, an external magnetic field is set up throughout the loop. The field is uniform, its direction is into the page in Figure (a), and the field magnitude is given by B = at, where B is in Tesla, a is a constant, and t is in seconds. Figure (b) gives the current i in the circuit before, during, and after the external field is set up. The vertical axis scale is set byis=2.0mA. Find the constant a in the equation for the field magnitude.

Two coils are at fixed locations. When coil 1 has no current and the current in coil 2 increases at the rate 15.0 A/s, the emf in coil 1 is 25.0 mV. (a) What is their mutual inductance? (b) When coil 2 has no current and coil 1 has a current of 3.60A, what is the flux linkage in coil 2?

Figure 30-74 shows a uniform magnetic field confined to a cylindrical volume of radius R. The magnitude of is decreasing at a constant rate of 10m Ts. In unit-vector notation, what is the initial acceleration of an electron released at (a) point a (radial distance r=0.05m ), (b) point b (r =0 ), and (c) point c (r =0.05m)?

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.