91Ó°ÊÓ

Three infinite non-conducting sheets with uniform positive charge densities$\mathrm{σ},2\mathrm{σ}$ and $3\mathrm{σ}$are arranged parallel.

Here, e can arbitrarily arrange the sheets such that we can get the given values of the electric fields between the regions of the non-conducting sheets.

Formula:

The electric field for an infinite non-conducting sheet,

$\mathrm{E}=\frac{\mathrm{σ}}{2{\mathrm{Î\mu }}_0}$ ….. (i)

As the charge densities are positive for all the sheets, thus, the any point at the extreme ends of the arrangements will add up due to repulsion and thus, there will be no minimum value of zero electric field $\left(\mathrm{E}=0\right)$ or $\mathrm{E}=\frac{2\mathrm{σ}}{{\mathrm{Î\mu }}_0}$ at either end.

At region I, the net electric field at any point in this region can be given using equation (i) as follows:

(For condition of repulsion of similar charges field is towards left for charge densities $+\mathrm{σ},+2\mathrm{σ}$ and the field is towards right for $+3\mathrm{σ}$).

$\begin{array}{c}{\mathrm{E}}_{\mathrm{I}}=\frac{+3\mathrm{σ}}{{\mathrm{Î\mu }}_0}−\frac{+\mathrm{σ}}{{\mathrm{Î\mu }}_0}−\frac{+2\mathrm{σ}}{{\mathrm{Î\mu }}_0}\\ =0\end{array}$

At region II, the net electric field at any point in this region can be given using equation (i) as follows:

(For condition of repulsion of similar charges field is towards left for charge densities$+2\mathrm{σ}$ and the field is towards right for role="math" localid="1661872288885" $+\mathrm{σ},+3\mathrm{σ}$).

$\begin{array}{c}{\mathrm{E}}_{\mathrm{II}}=\frac{+3\mathrm{σ}}{{\mathrm{Î\mu }}_0}+\frac{+\mathrm{σ}}{{\mathrm{Î\mu }}_0}−\frac{+2\mathrm{σ}}{{\mathrm{Î\mu }}_0}\\ =\frac{+2\mathrm{σ}}{{\mathrm{Î\mu }}_0}\end{array}$

Hence, the order of the sheets is $\text{Sheet3,sheet1,sheet2}$.