Q 73P 聽In Fig. 5-61, a tin of antioxi... [FREE SOLUTION]

Chapter 5: Q 73P (page 122)

In Fig. 5-61, a tin of antioxidants $(m_{1} = 1.0 k g)$ on a friction less inclined surface is connected to a tin of corned beef $(m_{2} = 2.0 k g)$ .The pulley is mass less and friction less. An upward force of magnitude $F = 6.0 N$ acts on the corned beef tin, which has a downward acceleration of $5.5 m / s^{2}$ . What are (a) the tension in the connecting cord and (b) angle $尾$ ?

Short Answer

Expert verified

a)The tension in the connecting rod is

T = 2.6 N

b)Angle is $尾 = 17^{鈭�}$

Step by step solution

Given information

Given that,

$m_{1} = 1.0 k g$

role="math" localid="1655520757224" $m_{2} = 2.0 k g$

role="math" localid="1655520811170" $F = 6.0 N$

$a = 5.5 m / s^{2}$

Determining the concept

The problem is based on Newton鈥檚 second law of motion which states that the rate of change of momentum of a body is equal in both magnitude and direction of the force acting on it.

Formula:

According to the Newton鈥檚 second law of motion,

$F_{n e t} = {鈭�}_{}^{} M a$

(a) Determining the tension in the connecting rod

Free Body diagram

$T + m_{1} g \sin (尾) = m_{1} a$

$m_{2} g - F - T = m_{2} a (2 脳 9.8) - 6 - T = 2 脳 5.5$

By solving for above equation,

$T = 2.6 N$

Hence, the tension in the connecting rod is $T = 2.6 N$

(b) Determining the angle

Now, plugging this value in equation 1,

$2.6 + 1 脳 9.8 脳 \sin (尾) = 1 脳 5.5 尾 = 17^{鈭�}$

Hence, an angle is $尾 = 17^{鈭�}$

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Short Answer

Step by step solution

Given information

Determining the concept

(a) Determining the tension in the connecting rod

(b) Determining the angle

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