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In Fig. 5-61, a tin of antioxidants (m1=1.0kg)on a friction less inclined surface is connected to a tin of corned beef(m2=2.0kg).The pulley is mass less and friction less. An upward force of magnitudeF=6.0Nacts on the corned beef tin, which has a downward acceleration of5.5m/s2. What are (a) the tension in the connecting cord and (b) angle β?

Short Answer

Expert verified
a)The tension in the connecting rod is T=2.6N

b)Angle is β=17∘

Step by step solution

01

Given information

Given that,

m1=1.0kg

role="math" localid="1655520757224" m2=2.0kg

role="math" localid="1655520811170" F=6.0N

a=5.5m/s2

02

Determining the concept

The problem is based on Newton’s second law of motion which states that the rate of change of momentum of a body is equal in both magnitude and direction of the force acting on it.

Formula:

According to the Newton’s second law of motion,

Fnet=∑Ma

03

(a) Determining the tension in the connecting rod

Free Body diagram

T+m1gsinβ=m1a

m2g-F-T=m2a(2×9.8)-6-T=2×5.5

By solving for above equation,

T=2.6N

Hence, the tension in the connecting rod isT=2.6N

04

(b) Determining the angle

Now, plugging this value in equation 1,

2.6+1×9.8×sinβ=1×5.5β=17∘

Hence, an angle isβ=17∘

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