/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Qn 1 Question: To suck lemonade of de... [FREE SOLUTION] | 91影视

91影视

Log out

Learning Materials

Features

Discover

Chapter 14: Qn 1 (page 408)

Question: To suck lemonade of density 1000 kg/m3up a straw to a maximum height of 4.0 cm, what minimum gauge pressure (in atmospheres) must you produce in your lungs?

Short Answer

Expert verified

Answer :

Gauge pressure produced in the lungs in atmospheric unit is -3.9脳10-3atm

Step by step solution

01

The given data 

Maximum height,h=4cmor0.04m

Density of lemonade, p=1000kg/m3

Acceleration due to gravity,g=9.8m/s2

02

Understanding the concept of pressure 

To find gauge pressure in theatm, we can use the formula for pressure in terms of density, acceleration due to gravity, and height. Using the conversion factor, we can convert the pressure into atmosphericpressure.

Formula:

Pressure applied on a body, p=pgh (i)

03

Calculation of gauge pressure in atm 

The pressure produced in the lungs in SI unit using equation (i) can be given as follows:

p=-1000kg/m3脳0.04m脳9.8m/s2=-392pa=-392pa脳1atm1.01脳105pa(atm=1.01脳105pa)=-3.9脳10-3atm

So, the pressure value is-3.9脳10-3atm

Negative sign indicates that the pressure inside the lung is less than the outside pressure.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Figure 14-22 shows a tank filled with water. Five horizontal floors and ceilings are indicated; all have the same area and are located at distances L, 2L, 3Lorbelow the top of the tank. Rank them according to the force on them due to the water, greatest first.

A simple open U-tube contains mercury. When 11.2cmof water is poured into the right arm of the tube, how high above its initial level does the mercury rise in the left arm?

A 8.60kgsphere of radius 6.22cmis at a depth of 2.22kmin seawater that has an average density of 1025kg/m3.What are the (a) gauge pressure, (b) total pressure, and (c) corresponding total force compressing the sphere鈥檚 surface? What are (d) the magnitude of the buoyant force on the sphere and (e) the magnitude of the sphere鈥檚 acceleration if it is free to move? Take atmospheric pressure to be 1.01脳105Pa.

In Fig. 14-39a, a rectangular block is gradually pushed face-down into a liquid. The block has height d; on the bottom and top the face area is A=5.67cm2. Figure 14-39b gives the apparent weight Wappof the block as a function of the depth h of its lower face. The scale on the vertical axis is set by Ws=0.20N. What is the density of the liquid?

A block of wood has a mass of 3.67 kgand a density of 600kg/m3. It is to be loaded with lead ( 1.14脳10-4kg/m3) so that it will float in water with 0.900of its volume submerged. (a)What mass of lead is needed if the lead is attached to the top of the wood? (b)What mass of lead is needed if the lead is attached to the bottom of the wood?
See all solutions

Recommended explanations on Physics Textbooks

Astrophysics

Read Explanation

Oscillations

Read Explanation

Linear Momentum

Read Explanation

Fundamentals of Physics

Read Explanation

Space Physics

Read Explanation

Fluids

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.