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Question: In Fig. 33-64, a light ray in air is incident on a flat layer of material 2 that has an index of refraction n2=1.5 . Beneath material 2is material 3 with an index of refraction n3.The ray is incident on the air鈥搈aterial 2 interface at the Brewster angle for that interface. The ray of light refracted into material 3happens to be incident on the material 2-material 3 interface at the Brewster angle for that interface. What is the value of n3 ?

Short Answer

Expert verified

The value of n3is 1.

Step by step solution

01

Given

The refractive index of the material 2 is n2=1.5

The refractive index of the first medium i.e. air isn1=1

02

Understanding the concept

By using the formula of Brewster鈥檚 angle and as the figure say that the layers are parallel so that the refraction regarding the first is the same as the angle of incidence regarding the second surface.

Formula:

Brewster鈥檚 angle

B=tann2n1

03

Step 3: Calculate the value of n3.

Since the layers are parallel, the angle of refraction of the first surface is the same as the angle of incidence of the second surface. Thus,

2=1c=90-

Brewster鈥檚 angle is given by

B=tan-1n2n11=tan-11.51=56.31

Therefore,

2=90-56.31o=33.69

We can apply Brewster鈥檚 law to both refractions. Therefore,

n2n1n3n2=迟补苍胃12迟补苍胃23n3n1=迟补苍胃1迟补苍胃2n31=tan56.31tan33.69n3=1

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