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In Fig. 33-55, a 2.00″¾long vertical pole extends from the bottom of a swimming pool to a point 50.0cmabove the water. Sunlight is incident at angle θ=55.0°. What is the length of the shadow of the pole on the level bottom of the pool?

Short Answer

Expert verified

The length of the shadow of the pole on the level bottom of the pool is 1.07″¾

Step by step solution

01

Given

Angle of incidence θ=550

l1=0.50″¾l2=1.50″¾

02

Understanding the concept

We can use Snell’s law to find the angle of refraction. Then using the geometry of the figure, we can find the length of the shadow of the pole on the level bottom of the pool.

Formula:

n1sinθ1=n2sinθ2

03

Calculate the length of the shadow of the pole on the level bottom of the pool

Ray diagram for the given problem:

According to Snell’s law,

n1sinθ1=n2sinθ2

But, here

θ1=90−θ=900−550=350

θ2=sin−1n1sin θ1n2θ2=sin−1(1.0)sin 3501.33θ2=25.550

Now, from the figure,

x=l1tan θ1x=(0.50 m)tan 350x=0.35″¾

And,

L=l2tan θ2L=(1.50″¾)tan 25.550L=0.717~0.72″¾

Therefore, the total length of the shadow is

x+L=0.35″¾+0.72″¾x+L=1.07″¾

Therefore, the length of the shadow of the pole on the level bottom of the pool is 1.07″¾

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