/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q37P An electric motor has an effecti... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

An electric motor has an effective resistance of 32.0Ωand an inductive reactance of45.0Ωwhen working under load. The rms voltage across the alternating source is420V.Calculate the rms current.

Short Answer

Expert verified

The rms current value is 7.61A.

Step by step solution

01

The given data

  1. Effective resistance R=32.0Ω
  2. Inductive reactanceXL=45.0Ω
  3. RMS value of voltageεrms=420V
02

Understanding the concept of RMS value

The RMS value of current means the square root of mean of square of value of current. The resistance offered in the path of current by the inductor is known as inductive reactance.

The rms current of a circuit,

Irms=εrmsZ ...(i)

The impedance of theLRcircuit for the driving frequencyÓ¬d

Z=R2+XL2 ...(ii)

03

Calculation of the rms current

The impedance value of the circuit can be given using equation (ii) as follows:

Z=R2+XL2

Now, substituting the above value in equation (i), we can get the value of rms current for the given data as follows:

Irms=εrmsR2+XL2=420V45Ω2+32Ω2=7.61A

Hence, the value of the current is localid="1662764908957" 7.61A.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

An alternating emf source with a variable frequency fd is connected in series with a80.0Ωresistor and an 40.0mHinductor. The emf amplitude is6.0V. (a) Draw a phasor diagram for phasor VR(the potential across the resistor) and phasor VL(the potential across the inductor). (b) At what driving frequency fddo the two phasors have the same length? At that driving frequency, what are (c) the phase angle in degrees, (d) the angular speed at which the phasors rotate, and (e) the current amplitude?

An RLC circuit such as that of Fig. 31-7 hasR=5.0Ω,C=20.0μ¹ó,L=1.0H, andεm=30.0V. (a) At what angular frequencyÓ¬dwill the current amplitude have its maximum value, as in the resonance curves of Fig. 31-16? (b) What is this maximum value? At what (c) lower angular frequencyÓ¬d1and (d) higher angular frequencyÓ¬d2will the current amplitude be half this maximum value? (e) For the resonance curve for this circuit, what is the fractional half-width(Ó¬d2-Ó¬d1)/Ó¬?

The values of the phase constant ϕ for four sinusoidally driven series RLC circuits are (1) ϕ=-15°, (2) ϕ=+35°, (3) ϕ=π3rad, and (4) ϕ=-π6rad. (a) In which is the load primarily capacitive? (b) In which does the current lag the alternating emf?

A series circuit containing inductance L1 and capacitance C1 oscillates at angular frequency Ó¬. A second series circuit, containing inductance L2 and capacitance C2, oscillates at the same angular frequency. In terms of Ó¬, what is the angular frequency of oscillation of a series circuit containing all four of these elements? Neglect resistance. (Hint:Use the formulas for equivalent capacitance and equivalent inductance.)

An alternating source with a variable frequency, an inductor with inductance L, and a resistor with resistance Rare connected in series. Figure gives the impedance Zof the circuit versus the driving angular frequency Ó¬d, with the horizontal axis scale set by (Ó¬d)s=1600rad/s. The figure also gives the reactance XLfor the inductor versus Ó¬d. (a) What isR? (b) What isL?

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.