/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q17P In Figure, R= 14.0Ω, C= 6.20... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

In Figure, R=14.0Ω,C=6.20μ¹ó,and L=54.0mH, and the ideal battery has emf ε=34.0V. The switch is kept at a for a long time and then thrown to position b.

(a)What is the frequency? (b)What is the current amplitude of the resulting oscillations?

Short Answer

Expert verified
  1. The frequency is 275Hz.
  2. The current amplitude of the resulting oscillation is 0.365A.

Step by step solution

01

The given data

  1. Resistance attached in the circuit R=14Ω,
  2. Inductance of the inductor, role="math" localid="1663075735599" L=54.0mHor54×10-3H
  3. Capacitance of a capacitor,C=6.20μ¹óor6.20×10-6F
  4. The emf voltage, ε=34.0V
02

Understanding the concept of the mechanism of the LC circuit

When a switch is kept at a point the capacitor is charged. After that, the switch is thrown to position b; then the circuit is an LC circuit. From that, we can calculate the angular frequency and frequency. Now capacitor is charged up to maximum voltage, and we can calculate the maximum charge on the capacitor. From that, we can calculate the current amplitude by taking the relation between the current and charge and angular frequency.

Formulae:

The angular frequency of an LC oscillation, Ó¬=1LC(i)

The charge of the capacitor, Q=CV(ii)

The current amplitude of the LC circuit, i=Ó¬Q(iii)

The frequency of an oscillation,f=Ó¬2Ï€(iv)

03

a) Calculation of the frequency

When the switch is thrown to position b, the circuit is an LC circuit. The frequency of the oscillation can be given using equation (i) in equation (iv) as follows:

f=12πLC=12π54×10-36.20×10-6=275Hz

Hence, the value of the frequency is 275Hz.

04

b) Calculation of the current amplitude of the resulting oscillation

After that, the switch is thrown to the point b so that the capacitor is chargedV=34.0V.Now, the maximum charge on the capacitor can be calculated using equation (ii) as follows:

Q=6.20×10-6×34.0=2.11×10-4C

So now, the current amplitude can be calculated using equation (iv) in equation (iii) as follows:

i=2πfQ=2π×275×2.11×10-4=0.365A

Hence, the value of the current amplitude is 0.365A.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

In Fig. 31-33, a generator with an adjustable frequency of oscillation is connected to resistance R=100Ω, inductances L1=1.70mH and L2=2.30mH, and capacitances C1=4.00μ¹ó, C2=4.00μ¹ó , and C3=3.50μ¹ó . (a) What is the resonant frequency of the circuit? (Hint: See Problem 47 in Chapter 30.) What happens to the resonant frequency if (b) Ris increased, (c) L1is increased, and (d) C3 is removed from the circuit?

A charged capacitor and an inductor are connected at time t=0. In terms of the period T of the resulting oscillations, what is the first later time at which the following reach a maximum: (a)UB, (b) the magnetic flux through the inductor, (c) di/dt
, and (d) the EMF of the inductor?

In a series oscillating RLC circuit,R=16.0Ω,C=31.2μF,L=9.20mH, and sinvdtwith εm=45.0Vand Ӭd=3000rad/s. For timet=0.442msfind (a) the ratePgat which energy is being supplied by the generator, (b) the ratePCat which the energy in the capacitor is changing, (c) the ratePLat which the energy in the inductor is changing, and (d) the ratePRat which energy is being dissipated in the resistor. (e) Is the sum ofPC,PL ,PRand Pggreater than, less than, or equal to ?

An oscillating LCcircuit has current amplitude of 7.50mA, potential amplitude of250mV, and a capacitance of220nF. (a) What is the period of oscillation? (b) What is the maximum energy stored in the capacitor? (c) What is the maximum energy stored in the inductor? (d) What is the maximum rate at which the current changes? (e) What is the maximum rate at which the inductor gains energy?

An RLC circuit such as that of Fig. 31-7 hasR=5.0Ω,C=20.0μ¹ó,L=1.0H, andεm=30.0V. (a) At what angular frequencyÓ¬dwill the current amplitude have its maximum value, as in the resonance curves of Fig. 31-16? (b) What is this maximum value? At what (c) lower angular frequencyÓ¬d1and (d) higher angular frequencyÓ¬d2will the current amplitude be half this maximum value? (e) For the resonance curve for this circuit, what is the fractional half-width(Ó¬d2-Ó¬d1)/Ó¬?

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.