/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q9Q Figure 24-26 shows four pairs of... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Figure 24-26 shows four pairs of charged particles with identical separations. (a) Rank the pairs according to their electric potential energy (that is, the energy of the two-particle system), greatest (most positive) first. (b) For each pair, if the separation between the particles is increased, does the potential energy of the pair increase or decrease?


Short Answer

Expert verified

Answer:

  1. The rank of the pairs according to their electric potential energy is U3=U4>U1=U2.

2. For each pair, is the separation is increased, the potential energy of the pair decreases

Step by step solution

01

The given data

Figure 24-26 showing four pairs of charged particles with identical separation is given.

02

Understanding the concept of electric potential energy

The electric potential energy of a system of charged particles is equal to the work needed to assemble the system with the particles initially at rest and infinitely distant from each other. Thus, the potential energy of a system depends on the distance value inversely and the product of charges directly.

Formula:

The electric potential energy of the system of particlesU=kq1q2/r, (i)

03

a) Calculation of the rank of pairs according to electric potential energy

Let the identical separation between them be.

Now, using equation (i) for all the four arrangements, the potential energies of the arrangements can be calculated as:


Hence, the required rank of energy is U4=U4>U1=U2.

04

b) Calculation of the potential energy when separation is increased

From equation (i), it can be clearly seen that the separation increase between the particles result in the decreasing of the potential energy of the system of charges.

Hence, the potential energy decreases.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A hollow metal sphere has a potential of +400Vwith respect to ground (defined to be atV=0 ) and a charge of 5.0×10−9C. Find the electric potential at the centre of the sphere.

A graph of the x component of the electric field as a function of x in a region of space is shown in Fig. 24-35. The scale of the vertical axis is set by Exs = 20.0 N/C. The y and z components of the electric field are zero in this region. If the electric potential at the origin is 10 V, (a) what is the electric potential at x = 2.0 m, (b) what is the greatest positive value of the electric potential for points on the x axis for which 0≤x≤6.0m, and (c) for what value of x is the electric potential zero?

Figure 24-30 shows a system of three charged particles. If you move the particle of chargefrom point Ato point D, are the following quantities positive, negative, or zero: (a) the change in the electric potential energy of the three particle system, (b) the work done by the net electric force on the particle you moved (that is, the net force due to the other two particles), and (c) the work done by your force? (d) What are the answers to (a) through (c) if, instead, the particle is moved from Bto C?

Question: In Fig. 24-48, what is the net electric potential at the origin due to the circular arc of charge Q1=+7.21pCand the two particles of chargesQ2=4.00Q1andQ3=-2.00Q1? The arc’s center of curvature is at the origin and its radius R is 2. 00 m; the angle indicated isθ=20.0°.

A particle of charge qis fixed at point P, and a second particle of mass mand the same charge qis initially held a distance r1 from P. The second particle is then released. Determine its speed when it is a distance from P. Let±ç=3.1μ°ä,³¾=20μ²µ,°ù1=0.90mm,r2=2.5mm.

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.