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A uniform charge of 16.0μCis on a thin circular ring lying in xy plane and centered on the origin. The ring’s radius is3.00cm. If point A is at the origin and point B is on the z-axis at z=4.00cm, what isVB-VA?

Short Answer

Expert verified

The value of VB-VAis -1.92MV.

Step by step solution

01

Step 1: Given data:

The uniform charge,q=+16.0μC,

The radius of the circle,R=0.03m

The vertical distance, AB=Z=0.04 m.

02

Determining the concept:

Potential at a point due to a charge q is given as,

V=14πε0qr

Here, is the distance of the point from the charge,q is the electric charge, and14πε0is the Coulomb constanthaving a value 9×10N.m2/C2.

03

Determining the VB-VA:

Due to the ring, the electric potential atAis,

VA=14πεo·qR

=9.0×109N.m2/C2×16.0×10-6C0.03m

=4800×103V

=4.8 MV

Again, due to the ring, the electric potential at Bis,

VB=14πεo·qR2+Z2
VB=9.0×109N.m2/C2×16×10-6C0.032+0.042m

=9.0×109N.m2/C2×16×10-6C0.05 m

=2,880×103V=2.88MV

Now,

VB-VA=2.88MV-4.8MV=-1.92MV

.

Hence, potential at VB-VAis -1.92MV.

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