/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q7P The electric field in a region o... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

The electric field in a region of space has the components Ey = Ez = 0and Ex = (4.00N/C)x. Point Ais on the yaxis at y = 3.00m, and point Bis on the xaxis at x = 4.00m. What is the potential difference VB - VA?

Short Answer

Expert verified

The potential difference is, -32.0V.

Step by step solution

01

Given

The electric field in a region of space has the components Ey = Ez = 0 and Ex = (4.00N/C)x.

02

Understanding the concept

Using the equation of potential difference V = E.d, we can find the potential difference between two points.

03

Calculate the potential difference VB - VA

We connect A to the origin with a line along the y axis, along which there is no change of potential (Equation: ∫E.ds=0). Then, we connect the origin to B with a line along the x-axis, along which the change in potential is

∆V=-∫0x=4E.ds

Substitute all the value in the above equation.

∆V=-4.00∫04xdx=-4.00x2204VB-VA=-4.00422VB-VA=-32.0V

Hence the potential difference is, -32.0V.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Question: In Fig. 24-53, seven charged particles are fixed in place to form a square with an edge length of 4.0 cm. How much work must we do to bring a particle of charge +6Einitially at rest from an infinite distance to the center of the square?

Question: A plastic disk of radius R = 64.0 cmis charged on one side with a uniform surface charge densityσ=7.73fC/m2, and then three quadrants of the disk are removed. The remaining quadrant is shown in Fig. 24-50.With V =0at infinity, what is the potential due to the remaining quadrant at point P, which is on the central axis of the original disk at distance D = 25.9 cmfrom the original center?

In Fig. 24-71, a metal sphere with charge±ç=5.00μ°äand radius r=3.00cm is concentric with a larger metal sphere with charge ²Ï=15.0μ°ä and radius R=6.00cm .

(a) What is the potential difference between the spheres? If we connect the spheres with a wire, what then is the charge on

(b) the smaller sphere and

(c) the larger sphere?

Question: The smiling face of Fig. 24-49 consists of three items:

1.A thin rod of charge-3.0μCthat forms a full circle of radius;

2.a second thin rod of charge2.0μCthat forms a circular arc of radius 4.0cm, subtending an angle of 900about the center of the full circle;

3.An electric dipole with a dipolemoment that is perpendicular to aradial line and has a magnitude of1.28×10-21C.m.What is the net electric potential atthe center?

A long, solid, conducting cylinder has a radius of 2.0 cm. The electric field at the surface of the cylinder is160N/C, directed radially outward. Let A, B, and Cbe points that are10cm, 2.0 cm, and5.0 cm, respectively, from the central axis of the cylinder. What are (a) the magnitude of the electric field at Cand the electric potential differences (b)VB-VCand (c)VA-VB?

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.