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What are (a) the charge and (b) the charge density on the surface of a conducting sphere of radius 0.15 mwhose potential is 200 V(with V = 0at infinity)?

Short Answer

Expert verified
  1. The charge is q=3.3×10-9C.
  2. The charge density on the surface of a conducting sphere is σ=1.2×10-8C/m2.

Step by step solution

01

Given data:

  • Radius of the conducting sphere, R=0.15m
  • Potential of the conducting sphere,V=200V
02

Understanding the concept:

Using the equation of potential energy and surface charge density, you find charge on the sphere and surface charge density respectively.

V=kqR ….. (1)

Here, V is the potential, q is the charge, R is the radius, k is the Coulomb’s constant having the value

of 8.99×109N·m2/C2.

03

(a) Calculate the charge on the surface of a conducting sphere

The charge on the sphere is define by rearrange equation (1) for the charge as below.

q=VRk=200V0.15m8.99×109N·m2/C2=3.3×10-9C

Hence, the charge is 3.3×10-9C.

04

(b) Calculate the charge density on the surface of a conducting sphere:

The (uniform) surface charge density (charge divided by the area of the sphere) is,

σ=q4πR2=3.3×10-9C4×3.140.15m2=1.2×10-8C/m2

Hence, the charge density on the surface of a conducting sphere is 1.2×10-8C/m2.

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