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Chapter 24: Q6P (page 710)

When an electron moves from A to B along an electric field line in Fig. 24-34, the electric field does 3.94 x 10-19 Jof work on it. What are the electric potential differences (a) VB - VA, (b) VC - VA, and (c) VC - VB?

Short Answer

Expert verified
  1. The electric potential difference is VB - VA = 2.46 V.
  2. The electric potential difference is VC - VA = 2.46 V.
  3. The electric potential difference is VC - VB = 0.

Step by step solution

01

Given data:

The electric field energy is 3.94 x 10-19 J.

02

Understanding the concept:

Using the equation of potential energy, you can find the electric potential difference.

鈭�U=e鈭�V

Here, 鈭�U is the change in potential energy, e is the electric charge having a value 1.60 x 10-19 C, and 鈭�Vis the electric potential difference.

03

(a) Calculate VB - VA :

The electric potential difference between A and B is define as below.

VB-VA=鈭�Uq=-W-e=-3.94脳10-19J-1.60脳10-19C=2.46V

04

(b) Calculate VC - VA:

The electric potential difference between A and C is define as below.

VC-VA=VB-VA=2.46V

05

(c) Calculate VC - VB :

Since C and B are on the same equipotential line, the potential difference between C and B is,

VC - VB = 0

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Most popular questions from this chapter

Two isolated, concentric, conducting spherical shells have radiiR1=+0.500mandR2=1.00m , uniform chargesq1=+2.00渭颁 andq2=+1.00渭颁 , and negligible thicknesses. What is the magnitude of the electric field E at radial distance (a)r=4.00m , (b)r=0.700m , and (c)r=0.200m ? With V=0at infinity, what is V at (d)localid="1663936396588" r=4.00m , (e)localid="1663936405423" r=1.00m , (f) localid="1663936413104" r=0.700m, (g)localid="1663936424825" r=0.500m , (h)localid="1663936434140" r=0.200m , and (i)localid="1663936441939" r=0? ( j) Sketch localid="1663936449400" E(r)and localid="1663936460268" V(r) .

A nonconducting sphere has radius R = 2.31 cmand uniformly distributed charge q = +3.50 fC. Take the electric potential at the sphere鈥檚 center to be V = 0 . What is Vat radial distance (a) r = 1.45 cmand (b) r = R. (Hint: See Module 23-6.)

Question: In Fig. 24-41a, a particle of elementary charge +eis initially at coordinate z = 20 nmon the dipole axis (here a zaxis) through an electric dipole, on the positive side of the dipole. (The origin of zis at the center of the dipole.) The particle is then moved along a circular path around the dipole center until it is at coordinate z = -20 nm, on the negative side of the dipole axis. Figure 24-41bgives the work done by the force moving the particle versus the angle u that locates the particle relative to the positive direction of the z-axis. The scale of the vertical axis is set byWas=4.0脳10-30J.What is the magnitude of the dipole moment?

A charge q is distributed uniformly throughout a spherical volume of radius R. Let V=0at infinity.What are

(a) V at radial distancer<R and

(b) the potential difference between points atr=R and the point at r=0?

Question: The smiling face of Fig. 24-49 consists of three items:

1.A thin rod of charge-3.0渭Cthat forms a full circle of radius;

2.a second thin rod of charge2.0渭Cthat forms a circular arc of radius 4.0cm, subtending an angle of 900about the center of the full circle;

3.An electric dipole with a dipolemoment that is perpendicular to aradial line and has a magnitude of1.28脳10-21C.m.What is the net electric potential atthe center?
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