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When monochromatic light is incident on a slit 22.0 μm wide, the first diffraction minimum lies at 1.80° from the direction of the incident light. What is the wavelength?

Short Answer

Expert verified

The wavelength is 691 nm.

Step by step solution

01

Describe the diffraction by a single slit results in maxima

The expression to calculate the wavelength is given by,

mλ=dsinθλ=dsinθm ….. (1)

Here, λis the wavelength, dis separation, and θis angle.

02

Determine the wavelength

Substitute 22×10-3mfor d, 1.80°for θ,and 1 for min equation (1).

λ=22×10-3msin1.80°1=6.91×10-7m=691×10-9m=691nm

Therefore, the wavelength is 691 nm.

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Most popular questions from this chapter

The wings of tiger beetles (Fig. 36-41) are coloured by interference due to thin cuticle-like layers. In addition, these layers are arranged in patches that are 60μm across and produce different colours. The colour you see is a pointillistic mixture of thin-film interference colours that varies with perspective. Approximately what viewing distance from a wing puts you at the limit of resolving the different coloured patches according to Rayleigh’s criterion? Use 550nm as the wavelength of light and 3.00nm as the diameter of your pupil.

In two-slit interference, if the slit separation is14μmand the slit widths are each 2.0μm, (a) how many two-slit maxima are in the central peak of the diffraction envelope and (b) how many are in either of the first side peak of the diffraction envelope?

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The distance between the first and fifth minima of a single slit diffraction pattern is 0.35mmwith the screen 40cmaway from the slit, when light of wavelength role="math" localid="1663070418419" 550nmis used. (a) Find the slit width. (b) Calculate the angle role="math" localid="1663070538179" θ of the first diffraction minimum.

For a certain diffraction grating, the ratio λ/aof wavelength to ruling spacing is1/3.5. Without written calculation or the use of a calculator, determine which of the orders beyond the zeroth order appear in the diffraction pattern.

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