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Sound waves with frequency 3000Hzand speed 343m/sdiffract through the rectangular opening of a speaker cabinet and into a large auditorium of length d=100m. The opening, which has a horizontal width of 30.0cm, faces a wall 100maway (Fig.36-36). Along that wall, how far from the central axis will a listener be at the first diffraction minimum and thus have difficulty hearing the sound? (Neglect reflections.)

Short Answer

Expert verified

The distance between first order minima and central minima is41.2m.

Step by step solution

01

Identification of given data

The frequency of the sound wave is f=3000Hz

The speed of the sound wave is v=343m/s

The length of auditorium is D=100m.

The width of opening is d=30cm.

The order of first minima is m=1.

02

Concept used

The diffraction is the phenomenon in which the light bends on the edges of the slit and pattern of light is formed on a screen

03

Determination of wavelength of sound wave

The wavelength of sound wave is given as:

v=f

Substitute all the values in equation.

343m/s=3000Hz=0.1143m

04

Determination of distance of first diffraction minima from central diffraction minima

The distance between first order minima and central minima is given as:

w=Dd2-1

Substitute all the values in equation.

w=100m30cm1m100cm0.1143m2-1w=41.2m

Therefore, the distance between first order minima and central minima is 41.2m.

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