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In a single-slit diffraction experiment, the top and bottom rays through the slit arrive at a certain point on the viewing screen with a path length difference of 4.0 wavelengths. In a phasor representation like those in Fig 36-7, how many overlapping circles does the chain of phasors make?

Short Answer

Expert verified

4 overlapping circles are made.

Step by step solution

01

The given data

Given that in a single-slit diffraction experiment, the top and bottom rays through the slit arrive at a certain point on the viewing screen with a path length difference of 4.0 wavelengths.

02

Concept and Formula used

The dark fringes can be located with the general equation

asinθ=mλfor m=1, 2, 3,...

a is path length difference of slit , andλ is wavelength.

03

Take path length difference to be 4λ

Using the above equation, path length difference is4λ

So role="math" localid="1663147887994" asinθ=4λ

Here, role="math" localid="1663147935739" m=4

This is a point of minimum.

A complete circle for each minima will appear.

Thus, chain of phasors will make 4 overlapping circles.

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