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The two headlights of an approaching automobile are 1.4m apart. At what (a) angular separation and (b) maximum distance will the eye resolve them? Assume that the pupil diameter is 5.0mm, and use a wavelength of 550nm for the light. Also assume that diffraction effects alone limit the resolution so that Rayleigh’s criterion can be applied.

Short Answer

Expert verified

(a) The angular separation is 1.34×10-4rad .

(b) The maximum distance at which the eye will resolve the headlights is10.43 km

Step by step solution

01

Given data

Distance between two head lightsD=1.4m

Diameter of the pupil d=5.0mm

Wavelength of light λ=550 nm

02

Definition and concept of Rayleigh criterion

The Rayleigh criteria specify the minimal distance between two light sources that must exist in order to resolve them into separate objects.

The angular separation is defined by,

θR=1.22λd ...(i)

Here, d is the pupil diameter.

The maximum distance at which the eye will resolve is:

L=Dd1.22λ ...(ii)

Where D is the distance between the two headlights

The arrangement of separation D between two head lights their angular separation and the viewing distance L .

03

(a) Determine the angular separation

Distance between two head lightsD=1.4m

Diameter of the pupil d=5.0mm

d=5.0mm=5.0mm1m103mm=5.0×10-3m

Wavelength of the lightλ=550nm

role="math" localid="1663024691134" d=550nm10-9m1nm=550×10-9m

The angular separation between the headlights as shown in the above figure is given by an equation (i)

θR=1.22λd=1.22550×10-9m5×10--3m=1.34×10-4rad

Therefore, the angular separation is1.34×10-4rad

04

(b) Determine the maximum distance at which the eye will resolve the headlights

From equation (ii), the maximum distance at which the eye can resolve the head lights as separate is

L =Dd1.22λ=1.4m5×10-3m1.22550×10-9m=10.43×103m=10.43×103m1km103m=10.43km

Therefore, the maximum distance at which the eye will resolve the headlights is10.43 km .

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