91Ó°ÊÓ

Energy gap of diamond,$E_g=5.50 eV$

The valence and the conduction band are separated by an energy gap. When the electron jumps from the conduction band to the valence band, a photon is released and the energy of the photon is equal to the energy gap between those two bands.

Formula for the wavelength of the released photon is given as-

$\mathit{E}\mathbf{=}\frac{\mathbf{h}\mathbf{c}}{\mathbf{λ}}$

Here, c is the speed of light in vacuum, E is the energy of the photon, $\mathit{λ}$ is the wavelength of photon and his the plank’s constant.

Using the concept and the given energy gap in equation (i), we can get the value of the maximum wavelength required for the excitation as follows:

$$\begin{gathered} {\mathrm{λ}}_{max}=\frac{hc}{E_g} \\ =\frac{\left(6.626×{10}^{-34}J.s\right)\left(3×{10}^{-8}m/s\right)}{\left(5.5eV\right)\left(1.6×{10}^{-19}J/eV\right)} \\ =2.26×{10}^{-7}m \\ =226\mathrm{nm} \end{gathered}$$

Hence, the wavelength of the photo is 226 nm.

Comparing with the electromagnetic spectrum, we can see that the wavelength $\mathrm{λ}=226\mathrm{nm}$lies in the ultraviolet region.

Hence, the region of the spectrum is ultraviolet region.