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Figure 41-1ashows 14 atoms that represent the unit cell of copper. However, because each of these atoms is shared with one or more adjoining unit cells, only a fraction of each atom belongs to the unit cell shown. What is the number of atoms per unit cell for copper? (To answer, count up the fractional atoms belonging to a single unit cell.)

Short Answer

Expert verified

The number of atoms per unit cell is 4.

Step by step solution

01

The given data

The unit cell of the copper shows the representation of 14 atoms.

02

Understanding the concept of lattice structure of copper

A lattice structure is a three-dimension open structure that is made up of more than one repeating unit cell of an atom. The cells define the connectivity of the constituent atoms in the unit cell structure. They can be of mainly four types of lattice structures: FCC, BCC, HCP, and simple cubic. Now, here the given unit cell of copper has an FCC structure. The total number of atoms per unit cell is calculated by calculating the atoms’ contributions that are placed at the corners and face constituting the structure.

03

Calculation of the number of atoms per unit cell

As the lattice structure copper consisting of 14 electrons is an FCC structure, thus the contribution to the structure is only from the face and corner atoms.

The contribution of each corner atom per unit cell of copper is 18. So, the total contribution by 8 corner atoms is 1.

The contribution of each face atom per unit cell of copper is 12. Thus, the contribution of 6 face atoms per unit cell of copper is 3.

Now, the total contribution of the FCC lattice in the copper unit cell is given by:

18×8+12×6=4

Hence, the number of atoms per unit cell of copper is 4.

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Most popular questions from this chapter

Use Eq. 41-9 to verify 7.0eV as copper’s Fermi energy.

The Fermi energy for silver is5.5eV. At T=0°C, what are the probabilities that states with the following energies are occupied: (a)4.4eV, (b)5.4eV, (c)5.5eV, (d)5.6eV, and (e)6.4eV? (f) At what temperature is the probability 0.16 that a state with energy E = 5.6eV is occupied?

The compound gallium arsenide is a commonly used semiconductor, has an energy gap Egof1.43eV. Its crystal structure is like that of silicon, except that half the silicon atoms are replaced by gallium atoms and half by arsenic atoms. Draw a flattened-out sketch of the gallium arsenide lattice, following the pattern of Fig. 41-10a.What is the net charge of the (a) gallium and (b) arsenic ion core? (c) How many electrons per bond are there? (Hint:Consult the periodic table in Appendix G.)

(a) Show that the density of states at the Fermi energy is given by

N(EF)=4(31/3)(π2/3)(mn1/3)h2=(4.11×1018m-2eV-1)n1/3

in which nis the number density of conduction electrons.

(b) Calculate N(EF)for copper, which is a monovalent metal with molar mass 63.54g/mol and density 8.96g/cm3.

Verify your calculation with the curve of Fig. 41-6, recalling that EF=7.0eV=for copper.

An isolated atom of germanium has 32 electrons, arranged in subshells according to this scheme:1s22s22p63s23p63d104s24p2 This element has the same crystal structure as silicon and, like silicon, is a semiconductor. Which of these electrons form the valence band of crystalline germanium?

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