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91Ó°ÊÓ

Two identical batteries of emf ε=12.0Vand internal resistance r=0.200Ωare to be connected to an external resistanceR , either in parallel (Figure a) or in series (Figure b). (a) If ,R=2.00r whatis the current in the external resistance in the parallel arrangement? (b) If R=2.00r,what is the current iin the external resistance in the series arrangements? (c) For which arrangement isigreater? (d) IfR=r/2.00 , what is in the external resistance in the parallel? (e) If R=r/2.00, what is i in the external resistance in the series arrangements? (f) For which arrangement is i greater now?

Short Answer

Expert verified

(a) The value of current i in parallel arrangement for R=2.00r is 24.0A.

(b) The value of current i in series arrangement for R=2.00r is 30.0A.

(c) The current i is greater in series arrangement.

(d) The value of current i in parallel arrangement for R=r2.0 is 60A.

(e) The value of current i in series arrangement for R=r2.0 is 48.0A.

(f) The current i is greater in parallel arrangement.

Step by step solution

01

Given data:

The emf voltage,ε=12.0V

The internal resistance,r=0.200Ω

02

Understanding the concept:

From the given information, if you apply the loop rule,you can find the current in the circuit. Using this, you can find the current across the external resistance in various arrangements.

Formula:

Current in block is define by,

i=VR

03

Find the current across the external resistor:

For parallel combination,according to the junction rule, the current in R is2i .

Apply the loop rule for the given circuit.

ε−ir−2iR=0i=εr+2R

And for the series combination,

ε−2ir−iR=0i=ε2r+R

The current across external resistance is.ir=2i

04

(a) Calculate the current I in the external resistance in the parallel arrangement if R=2.00r:

Value of current iin parallel arrangement forR=2.00r.

ir=2(εr+2R)=2(12.0)[0.200+2(0.400)]=24.01.000=24.0A

Hence, the value of current in parallel arrangement forR=2.00r is24.0A .

05

(b) Calculate the current   in the external resistance in the series arrangements if  :R=2.00r 

The value of current in series arrangement forR=2.00ris,

ir=2(ε2r+R)=2(12.0)[2(0.200)+0.400]=24.00.800=30.0A

Hence, the value of current iin series arrangement forR=2.00ris30.0A.

06

(c) Figure out for which arrangement isi   greater:

From the above results, it is clear that the current is greater in series combination.

07

(d) Calculatei  in the external resistance in the parallel if R=r/2.00 : 

The value of current iin series arrangement forR=r2.0.

ir=2(εr+2R)=2(12.0)[0.200+2(0.100)]=24.00.400=60A

Hence, the value of current i in parallel arrangement forR=r2.0 is 60A.

08

(e) Calculatei  in the external resistance in the series arrangements ifR=r/2.00  :

Value of current iin series arrangement forR=r2.0.

ir=2(ε2r+R)=2(12.0)[2(0.200)+0.100]=24.00.500=48.0A

Hence, the value of current iin series arrangement forR=r2.0is48.0A.

09

(f) Figure out for which arrangement is  i greater now:

From the above results, it is clear that the current is greater in parallel combination.

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