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The capacitor in Fig. 25-25 has a capacitance of25μ¹ó and is initially uncharged. The battery provides a potential difference of 120 VAfter switchis closed, how much charge will pass through it?

Short Answer

Expert verified

Charge passing through the battery isq=3.0×10-3C

Step by step solution

01

Given

The capacitance of the capacitor isC=25μ¹ó10-6F1μ¹ó=2.5×105F.

The potential difference is V = 120 V.

02

Determining the concept

Using equation 25-1, find the amount of charge that passes through the battery.

Formulae are as follows:


C=qV

Where C is capacitance, V is the potential difference, and q is the charge on the particle.

03

(a) Determining the charge passing through the battery

From equation 25-1 we know that,

q = CV

The charge passing through the battery is,

q=2.5×10-5F(120V)=3.0×10-3C

Hence, the charge passing through the battery is3.0×10-3C

Therefore, by using the formula for capacitance find the charge passing through the battery.

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