91影视

a) The separation between the mirrors of the laser, $\mathrm{L}=8\mathrm{cm}=8脳{10}^7\mathrm{nm}$

b) Each wavelength has an integral number n of half wavelengths in the length L=8 cm

c) The wavelength of the laser, $\mathrm{位}=533\mathrm{nm}$

A standing wave is a combination of two waves moving in opposite directions, each with the same amplitude and frequency.

Using the concept of standing waves, get the differential equation of the wave equation. This determines the differential of lambda which is the separation between the lambda by substituting the standing wave equation and the given data to it.

Formula:

The standing waves equation of a body is,

$\mathrm{苍位}=2\mathrm{L}$ 鈥�.. (1)

Now to obtain the separation between the wavelengths, first differentiate the equation (1) that is the nth harmonic of the standing wave of wavelength $位$in the cavity of width L , such as:

role="math" localid="1661499710483" $$\begin{gathered} \mathrm{n}鈭�\mathrm{位}+\mathrm{位}鈭�\mathrm{n}=0 \\ 鈭�\mathrm{位}=\frac{\mathrm{位}鈭�\mathrm{n}}{\mathrm{n}} \\ =\frac{\mathrm{位}}{\mathrm{n}}\left(\mathrm{separation}\mathrm{between}\mathrm{any}\mathrm{two}\mathrm{harmonics},鈭�\mathrm{n}=1\right) \\ =\frac{{\mathrm{位}}^2}{2\mathrm{L}}\left(\mathrm{from}\mathrm{equation}\left(1\right)\right) \end{gathered}$$

Substitute known values in the above equation.

$$\begin{gathered} 鈭�\mathrm{位}=\frac{{\left(533\mathrm{nm}\right)}^2}{2\left(8脳{10}^7\mathrm{nm}\right)} \\ =1.8脳{10}^{-12}\mathrm{m} \\ =1.8\mathrm{pm} \end{gathered}$$

Hence, the value of the separation is 1.8 pm .