/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q13Q Figure 40-21 shows partial energ... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Figure 40-21 shows partial energy-level diagrams for the helium and neon atoms that are involved in the operation of a helium–neon laser. It is said that a helium atom in stateE3 can collide with a neon atom in its ground state and raise the neon atom to state E2. The energy of helium state E3(20.61eV)is close to, but not exactly equal to, the energy of neon state role="math" localid="1661494292758" E2(20.66eV). How can the energy transfer take place if these energies are not exactly equal?

Short Answer

Expert verified

The energy transfer takes place due to the excitation caused by the current in the helium atoms by collisions (not the more massive neon atoms).

Step by step solution

01

The given data

  1. Figure 40-21 show partial energy-level diagrams for the helium and neon atoms that are involved in the operation of the helium-neon laser is given.
  2. The energy of the helium state E3(20.61eV)is very close to the energy of the neon state E3(20.66eV).
02

Understanding the concept of laser action

Due to the laser action, there occurs a potential difference that gives rise to the current passing through the helium-neon gas mixture serving—through collisions between helium atoms and electrons of the current—to raise many helium atoms to state E3, which is metastable with a mean life of 1 microsec. (The neon atoms are too massive to be excited by collisions with the (low-mass) electrons.)

03

Calculation of the reason for energy transfer

According to the given data and concept, when a metastableE3 helium atom and a ground stateE0 neon atom collide, the excitation energy of the helium atom is often transferred to the neon atom, which then moves to the state E2. In this manner, neon level E2(with a mean life of 170 ns) can become more heavily populated than neon levelrole="math" localid="1661494432656" E1 (which, with a mean life of only 10 ns, is almost empty).

This population inversion is relatively easy to set up because (1) initially, there are essentially no neon atoms in the state E1, and (2) the long mean life of helium levelE3 means that there is always a good chance that collisions will excite neon atoms to their level,E2 and (3) once those neon atoms undergo stimulated emission and fall to their E1level, they almost immediately fall down to their ground state (via intermediate levels not shown) and are then ready to be re-excited by collisions.

Hence, the energy transfer occurs even if the energy levels of helium and neon are not the same.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Ruby lasers are at a wavelength of 694 nm. A certain ruby crystal has Cr ions (which are the atoms that lase). The lasing transition is between the first excited state and the ground state, and the output is a light pulse lasting 2.00μ²õ. As the pulse begins, 60.0% of the Cr ions are in the first excited state and the rest are in the ground state. What is the average power emitted during the pulse? (Hint:Don’t just ignore the ground-state ions.)

A 20 keV electron is brought to rest by colliding twice with target nuclei as in Fig. 40-14. (Assume the nuclei remain stationary.) The wavelength associated with the photon emitted in the second collision is 130 pm greater than that associated with the photon emitted in the first collision. (a) What is the kinetic energy of the electron after the first collision? What are (b) the wavelength λ1and (c) the energy E1associated with the first photon? What are (d) λ2and (e) E2associated with the second photon?

For Problem 20, what multiple of h2/8mL2gives the energy of (a) the first excited state, (b) the second excited state, and (c) the third excited state of the system of seven electrons? (d) Construct an energy-level diagram for the lowest four energy levels.

Excited sodium atoms emit two closely spaced spectrum lines called the sodium doublet(Fig. 40-27) with wavelengths 588.995 nm and 589.592 nm. (a) What is the difference in energy between the two upper energy levels (n = 3, I = 1)? (b) This energy difference occurs because the electron’s spin magnetic moment can be oriented either parallel or anti-parallel to the internal magnetic field associated with the electron’s orbital motion. Use your result in (a) to find the magnitude of this internal magnetic field.

Consider an atom with two closely spaced excited states A and B. If the atom jumps to ground state from A or from B, it emits a wavelength of 500 nm or 510 nm, respectively. What is the energy difference between states A and B?

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.