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A constant horizontal force moves a \(50 \mathrm{~kg}\) trunk \(6.0 \mathrm{~m}\) up a \(30^{\circ}\) incline at constant speed. The coefficient of kinetic friction is \(0.20\). What are (a) the work done by the applied force and (b) the increase in the thermal energy of the trunk and incline?

Short Answer

Expert verified
(a) Work done by the applied force is approximately 736 J. (b) Increase in thermal energy is 509 J.

Step by step solution

01

Identify Given Values

Before solving the problem, let's write down the given values:- Mass of the trunk, \( m = 50 \text{ kg} \)- Distance moved, \( d = 6.0 \text{ m} \)- Incline angle, \( \theta = 30^{\circ} \)- Coefficient of kinetic friction, \( \mu_k = 0.20 \)The movement is at a constant speed, so the net work is zero. We will use these values to find the work done by the applied force and the increase in thermal energy.
02

Analyze Forces Acting on the Trunk

The main forces acting on the trunk are:- Gravitational force, \( mg \) where \( g = 9.8 \text{ m/s}^2 \)- Normal force, perpendicular to the incline surface.- Frictional force, \( f_k = \mu_k \cdot N \), opposing the direction of motion.- Applied force, \( F_a \), parallel to the incline.
03

Calculate Gravitational Force Component

The component of gravitational force acting down the incline is given by:\[ mg \sin(\theta) = 50 \times 9.8 \times \sin(30^{\circ}) \]Calculate this value to find the component of gravity parallel to the incline.
04

Calculate Normal Force

Normal force \( N \) is calculated as:\[ N = mg \cos(\theta) = 50 \times 9.8 \times \cos(30^{\circ}) \]This value helps in calculating the frictional force.
05

Calculate Frictional Force

Using the normal force, calculate the frictional force:\[ f_k = \mu_k \cdot N = 0.20 \times (50 \times 9.8 \times \cos(30^{\circ})) \]
06

Calculate Applied Force

Since the trunk moves at constant speed, the net force is zero, meaning:\[ F_a = f_k + mg \sin(\theta) \]Calculate \( F_a \) using the results from Step 3 and Step 5.
07

Calculate Work Done by Applied Force

The work done by the applied force is given by:\[ W = F_a \cdot d \]Substitute the value of \( F_a \) calculated in Step 6 and \( d = 6.0 \text{ m} \) to find the work done.
08

Calculate Increase in Thermal Energy

The increase in thermal energy due to friction is equal to the work done against friction:\[ \Delta E_{th} = f_k \cdot d \]Use the frictional force calculated in Step 5 and \( d = 6.0 \text{ m} \) to find \( \Delta E_{th} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Kinetic Friction
Kinetic friction is a force that opposes the relative sliding motion between two surfaces that are in contact. When an object moves across a surface, like a trunk on an inclined plane, kinetic friction works against the motion. It is given by the formula:\[ f_k = \mu_k \cdot N \]where \( f_k \) is the kinetic friction force, \( \mu_k \) is the coefficient of kinetic friction, and \( N \) is the normal force. The coefficient of kinetic friction is a dimensionless number that represents the frictional characteristics between the two surfaces. A higher value indicates more friction.
  • In this problem, the coefficient \( \mu_k = 0.20 \) suggests there is a moderate amount of friction.
  • The frictional force acts in the opposite direction of the applied force, making the trunk harder to move.
Understanding kinetic friction is critical to analyzing work and energy in physics because it affects the efficiency of moving objects.
Inclined Plane
An inclined plane is a flat surface tilted at an angle to the horizontal. It makes lifting objects easier by distributing the force needed over a greater distance. In this exercise, the incline has a 30-degree angle, which alters the gravitational force on the trunk.
  • The gravitational force has two components on an incline: one parallel to the plane that pulls the object down, and one perpendicular that pushes the object into the plane.
  • The parallel component is given by \( mg \sin(\theta) \), and it affects the net force calculation.
  • The perpendicular component, \( mg \cos(\theta) \), is used to find the normal force.
Understanding how inclines affect forces is crucial for solving related physics problems.
Gravitational Force
Gravitational force is the attractive force that the Earth exerts on objects, pulling them towards its center. For this trunk on an incline, gravity is split into components that play different roles in the problem.
  • The force parallel to the incline, \( mg \sin(\theta) \), tends to slide the trunk downward, countered by the applied force.
  • The perpendicular component, \( mg \cos(\theta) \), affects how strongly the trunk presses against the inclined surface, impacting the normal and frictional forces.
By breaking gravity into these components, it becomes easier to understand and solve the dynamics of objects on inclines.
Thermal Energy
Thermal energy is the energy that results from the motion of particles within a substance. In physics problems, thermal energy often increases when kinetic friction is at work.
  • When the trunk moves up the incline at constant speed, the kinetic friction converts some mechanical energy into thermal energy.
  • The increase in thermal energy can be calculated using the work done by kinetic friction: \( \Delta E_{th} = f_k \cdot d \).
This conversion is why objects in motion can warm up, and understanding this energy transfer is key in physics, especially when dealing with energy conservation or efficiency calculations.
Applied Force
Applied force is a force that acts on an object by another force or object. In this scenario, it is the force exerted on the trunk to move it up the incline at a constant speed.
  • Since the speed is constant, applied force must balance both the frictional force and the gravitational component parallel to the incline.
  • This is expressed as: \( F_a = f_k + mg \sin(\theta) \), where \( F_a \) is the applied force.
Knowing how to calculate and apply forces is essential for solving real-world physics problems, especially those involving movement along different planes.

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