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A \(2.50 \mathrm{~kg}\) beverage can is thrown directly downward from a height of \(4.00 \mathrm{~m}\), with an initial speed of \(3.00 \mathrm{~m} / \mathrm{s}\). The air drag on the can is negligible. What is the kinetic energy of the can (a) as it reaches the ground at the end of its fall and (b) when it is halfway to the ground? What are (c) the kinetic energy of the can and (d) the gravitational potential energy of the can-Earth system \(0.200 \mathrm{~s}\) before the can reaches the ground? For the latter, take the reference point \(y=0\) to be at the ground.

Short Answer

Expert verified
Kinetic energy at impact: 112.9 J; halfway: 62.5 J; 0.200 s before impact: 104.6 J; Potential energy 0.200 s before impact: 18.0 J.

Step by step solution

01

Understanding the given information

We have a beverage can with a mass of \(2.50 \text{ kg}\) initially thrown downwards from a height of \(4.00 \text{ m}\), at a speed of \(3.00 \text{ m/s}\). We need to find the kinetic energies at different points during its fall, assuming no air resistance. We'll also find the gravitational potential energy at a specific time before hitting the ground.
02

Calculating Final Velocity Using Kinematics

Use the kinematic equation to find the final velocity \(v_f\) at the ground:\[v_f^2 = v_i^2 + 2a y\]where \(v_i = 3.00 \text{ m/s}\) is the initial speed, \(a = 9.81 \text{ m/s}^2\) is the acceleration due to gravity, and \(y = 4.00 \text{ m}\) is the distance of fall. Substitute the known values:\[v_f^2 = (3.00)^2 + 2 \times 9.81 \times 4.00\]Calculate \(v_f\).
03

Finding the Final Kinetic Energy

The kinetic energy \(K\) as it reaches the ground is given by:\[K = \frac{1}{2} m v_f^2\]Use the final velocity from Step 2 to calculate the kinetic energy.
04

Calculating Velocity at Halfway Point

At halfway down, the can has fallen \(2.00 \text{ m}\). Using the kinematic equation:\[v^2 = v_i^2 + 2a y\]where \(y = 2.00 \text{ m}\). Substitute and compute \(v\).
05

Finding Kinetic Energy at Halfway

With the velocity from Step 4, compute the kinetic energy halfway down using the formula:\[K = \frac{1}{2} m v^2\]
06

Calculating Time for Final 0.200s

Determine \(t\) when the can is 0.200 s away from hitting the ground by first calculating total time of fall using:\[y = v_i t + \frac{1}{2} a t^2\]Solve for \(t\) and then find the velocity \(v\) at \(t - 0.200\) seconds.
07

Velocity at 0.200s Before Impact

Now find the velocity using:\[v = v_i + at\]where \(t\) is calculated from the time remaining before impact.
08

Kinetic Energy 0.200s Before Impact

Calculate the kinetic energy with the velocity found in Step 7:\[K = \frac{1}{2} m v^2\]
09

Gravitational Potential Energy Before Impact

Calculate the height \(h\) at \(t - 0.200\) using the equation from Step 6 and find gravitational potential energy (PE):\[PE = mgh\]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Gravitational Potential Energy
Gravitational potential energy (GPE) is an essential concept in physics that describes the energy stored in an object due to its position relative to the ground. In physics problems, this energy depends on three main factors: mass, gravity, and height.
To calculate the gravitational potential energy of our beverage can, we'll use the formula:
  • \(PE = mgh\)
    Where \(m\) is the mass of the can, \(g\) is the acceleration due to gravity (9.81 m/s²), and \(h\) is the height above the ground.
For instance, when the can is initially released from a height of 4.00 meters, you can substitute the values to find the potential energy at that point, giving us a sense of how high it is in potential terms compared to when it reaches the ground.
As the can falls, this energy gets converted to kinetic energy until reaching zero when it hits the ground. Understanding this conversion helps explain the motion of falling objects in terms of energy perspectives.
Kinematics
Kinematics is the study of motion without considering the forces causing it. When analyzing the descending can, we primarily focus on its velocity and acceleration.
Using kinematic equations allows us to predict various aspects of its motion, such as velocity at different points of fall. The kinematics involved here use the equation:
  • \(v_f^2 = v_i^2 + 2a y\)
    This equation calculates the final velocity of the can right before hitting the ground, where \(v_i\) is the initial speed, \(a\) is the acceleration due to gravity, and \(y\) is the falling height.
Another critical formula used calculates time and height during its descent:
  • \(y = v_i t + \frac{1}{2} a t^2\)
    This helps to estimate how long it takes for the can to reach the halfway point or at specific times before ground impact.
Understanding these equations provides the necessary tools to predict motions accurately, crucial in solving real-world problems.
Energy Conservation
The principle of energy conservation is fundamental to understanding physics problems involving motion. This principle asserts that energy cannot be created or destroyed but only transformed. In the context of our free-falling can, total energy at any point is the sum of kinetic and potential energy.
Initially, when the can is at rest, its energy is entirely potential. As it begins to fall, this energy constantly transforms into kinetic energy, increasing the can's velocity.
As the can reaches the ground, nearly all the initial potential energy converts into kinetic energy, maximizing its speed. Throughout the fall, however, the total energy—the sum of both kinetic and potential—remains constant, assuming no air resistance.
Understanding this allows us to utilize energy principles rather than solely relying on kinematic equations, providing alternative solutions in different contexts.
Free Fall
Free fall refers to the motion of objects falling unimpeded solely under the influence of gravity. Here, air resistance is negligible, simplifying calculations. The can's motion exemplifies free fall, with gravity being the only force acting on it.
In free-fall conditions, the object experiences constant acceleration due to gravity, often valued as \(9.81 \, \text{m/s}^2\). This constant defines the rate at which the velocity of a freely falling object increases.
Given that the can is thrown downward, it already has an initial velocity of \(3.00 \, \text{m/s}\). This initial speed means it gains additional velocity on top of this initial value as gravity acts on it.
Understanding free-fall motion provides foundational knowledge for analyzing various real-life physics problems, including those involving safety features like seat belts or evaluating the efficiency of sports or engineering design.

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