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During an Olympic bobsled run, the Jamaican team makes a turn of radius \(7.6 \mathrm{~m}\) at a speed of \(96.6 \mathrm{~km} / \mathrm{h}\). What is their acceleration in terms of \(g\) ?

Short Answer

Expert verified
The acceleration is approximately \(9.65\,g\).

Step by step solution

01

Convert Speed to Meters per Second

First, let's convert the bobsled team's speed from kilometers per hour to meters per second. The formula for conversion is: \[ \text{speed in m/s} = \text{speed in km/h} \times \frac{1000}{3600} \]Substitute the given speed:\[ 96.6 \text{ km/h} \times \frac{1000}{3600} = 26.83 \text{ m/s} \]
02

Calculate Centripetal Acceleration

Next, use the formula for centripetal acceleration \( a_{c} \), which is given by:\[ a_{c} = \frac{v^2}{r} \]where \( v \) is the velocity in m/s and \( r \) is the radius of the turn.Substituting the known values:\[ a_{c} = \frac{(26.83 \; \text{m/s})^2}{7.6 \; \text{m}} = 94.74 \; \text{m/s}^2 \]
03

Convert Acceleration to g

Finally, we express the acceleration in terms of \( g \) by dividing the centripetal acceleration by the acceleration due to gravity \( g = 9.81 \text{ m/s}^2 \):\[ a_{g} = \frac{94.74 \; \text{m/s}^2}{9.81 \; \text{m/s}^2} \approx 9.65 \; g \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Physics
Physics is fascinating because it helps us understand how the world works. It's the science of matter, energy, and their interactions.

When we talk about centripetal acceleration in physics, we're dealing with forces that keep objects moving in a circular path. Even if the speed of the object remains constant, its direction changes continuously, which means it's accelerating. This is a critical aspect of motion, ensuring that we grasp how forces act on bodies in motion.
  • Forces are vector quantities, meaning they have both magnitude and direction.
  • Centripetal force, which causes centripetal acceleration, always points towards the center of the circle.
  • The source of centripetal force can vary: it might be tension, gravity, friction, or another force.
Understanding these concepts forms the foundation of many technological advances and everyday applications. From designing roller coasters to studying celestial bodies, physics plays an integral role in unraveling the mysteries of circular motion.
Kinematics
Kinematics is all about motion. It examines how objects move without worrying about the forces that cause the movement. This makes it an essential part of understanding circular motion as it focuses on velocity and acceleration.

In this context:
  • Velocity is the speed of an object in a particular direction.
  • Acceleration measures how quickly the velocity changes.
  • Centripetal acceleration quantifies the change in direction of an object moving in a circle.
Using kinematic equations, you can convert units, such as from kilometers per hour to meters per second, to make calculations more manageable. This conversion enables you to use standard formulas, like that for centripetal acceleration, to explore how objects travel along curved paths.

Studying kinematics allows us to predict future movement of objects by understanding their current motion patterns.
Circular Motion
Circular motion is a type of movement where an object travels along a curvy path. There's a lot happening when something moves in a circle, such as a bobsled whizzing around a track.

Here's what takes place:
  • An object in circular motion has a constant speed but its direction changes continuously.
  • Centripetal acceleration is necessary to maintain this movement, keeping the object on its curved path.
  • The formula for centripetal acceleration is crucial: \( a_{c} = \frac{v^2}{r} \).
Converting this acceleration into terms of gravitational forces, or g’s, helps us grasp how intense these forces can feel.

If you've ever felt like you're being pushed outwards on a merry-go-round, that's the force acting against the centripetal motion. Learning about circular motion isn't just about equations; it's about what those equations mean in real-life scenarios, making physics both practical and exciting.

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Most popular questions from this chapter

You testify as an expert witness in a case involving an accident in which car \(A\) slid into the rear of car \(B\), which was stopped at a red light along a road headed down a hill (Fig. \(6-25\) ). You find that the slope of the hill is \(\theta=12.0^{\circ}\), that the cars were separated by distance \(d=24.0 \mathrm{~m}\) when the driver of car \(A\) put the car into a slide (it lacked any automatic anti-brake-lock system), and that the speed of car \(A\) at the onset of braking was \(v_{0}=18.0 \mathrm{~m} / \mathrm{s}\). With what speed did car \(A\) hit car \(B\) if the coefficient of kinetic friction was (a) \(0.60\) (dry road surface) and (b) \(0.10\) (road surface covered with wet leaves)?

A slide-loving pig slides down a certain \(35^{\circ}\) slide in twice the time it would take to slide down a frictionless \(35^{\circ}\) slide. What is the coefficient of kinetic friction between the pig and the slide?

ao A \(2.5 \mathrm{~kg}\) block is initially at rest on a horizontal surface. A horizontal force \(\vec{F}\) of magnitude \(6.0 \mathrm{~N}\) and a vertical force \(\vec{P}\) are then applied to the block (Fig. \(6-17\) ). The coefficients of friction for the block and surface are \(\mu_{s}=0.40\) and \(\mu_{k}=0.25 .\) Determine the magnitude of the frictional force acting on the block if the magnitude of \(\vec{P}\) is (a) \(8.0 \mathrm{~N}\),(b) \(10 \mathrm{~N}\), and \((\mathrm{c}) 12 \mathrm{~N}\)

A certain string can withstand a maximum tension of \(40 \mathrm{~N}\) without breaking. A child ties a \(0.37 \mathrm{~kg}\) stone to one end and, holding the other end, whirls the stone in a vertical circle of radius \(0.91\) \(\mathrm{m}\), slowly increasing the speed until the string breaks. (a) Where is the stone on its path when the string breaks? (b) What is the speed of the stone as the string breaks?

The coefficient of static friction between Teflon and scrambled eggs is about \(0.04\). What is the smallest angle from the horizontal that will cause the eggs to slide across the bottom of a Teflon-coated skillet?

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