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The coefficient of static friction between Teflon and scrambled eggs is about \(0.04\). What is the smallest angle from the horizontal that will cause the eggs to slide across the bottom of a Teflon-coated skillet?

Short Answer

Expert verified
The smallest angle is approximately \(2.29^\circ\).

Step by step solution

01

Understand the problem

We need to find the smallest angle from the horizontal that will cause scrambled eggs to start sliding on a Teflon-coated skillet. This angle depends on the coefficient of static friction between the two surfaces.
02

Identify the formula

The smallest angle \( \theta \) that causes an object to begin to slide on an inclined plane is determined by the equation:\[ \tan \theta = \mu_s \]where \( \mu_s \) is the coefficient of static friction.
03

Plug values into the formula

Substitute the coefficient of static friction \( \mu_s = 0.04 \) into the equation:\[ \tan \theta = 0.04 \]
04

Solve for the angle

To find \( \theta \), take the arctangent of both sides:\[ \theta = \arctan(0.04) \]Compute this using a calculator:\[ \theta \approx 2.29^\circ \]
05

Conclusion

The smallest angle from the horizontal that will cause the eggs to slide is approximately \(2.29^\circ\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Static Friction
Static friction is the force that keeps an object at rest when it is placed on a surface. This frictional force must be overcome for the object to begin moving. It is characterized by the coefficient of static friction, denoted as \( \mu_s \). The greater the coefficient, the more force is required to initiate movement. For example:
  • If you place a book on a table, and gently push it, static friction resists the initial movement of the book.
  • Once the push overcomes the static friction, the book begins to slide, and kinetic friction takes over.
In the context of our exercise, the static friction between Teflon and scrambled eggs is low (\( \mu_s = 0.04 \)), meaning very little force is needed for movement to occur. As the skillet tilts, at a certain angle, the component of gravitational force that acts parallel to the surface will exceed the static frictional force, causing the eggs to slide.
Angle of Inclination
The angle of inclination is the angle formed between the horizontal and the inclined surface or plane. When it comes to friction, this angle can determine the point at which an object placed on the incline will begin to slide. For small angles, the static frictional force prevents sliding.
As the angle increases, so does the gravitational force component acting down the plane, which challenges the static friction.
  • Consider a flat table surface — it has a 0° angle of inclination.
  • When you start tilting the table, you increase this angle.
When the angle is just right, the gravitational force component parallel to the incline matches or exceeds the maximum static frictional force. This is the threshold where the object starts to move, and is found using the formula \( \tan \theta = \mu_s \). For scrambled eggs in our scenario, this smallest angle needed for movement is \( 2.29^\circ \).
Coefficient of Friction
The coefficient of friction is a dimensionless number that characterizes the frictional force between two surfaces. There are two types: static (\( \mu_s \)) and kinetic (\( \mu_k \)). In our exercise, we focus on static friction.
The magnitude of the static coefficient indicates how easily one object starts moving over another. A small coefficient means less resistance to commence movement, as seen with Teflon's smooth surface and scrambled eggs slid.
  • If \( \mu_s \) is high, like rubber on asphalt, more force is needed.
  • If \( \mu_s \) is low, such as Teflon's case, less effort is required.
Understanding these concepts aids in predicting and explaining the motion of objects on a variety of surfaces. In many practical applications, such as designing non-stick cookware or the shoes we wear, knowing the right coefficient of friction can make all the difference.

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Most popular questions from this chapter

A bedroom bureau with a mass of \(45 \mathrm{~kg}\), including drawers and clothing, rests on the floor. (a) If the coefficient of static friction between the bureau and the floor is \(0.45\), what is the magnitude of the minimum horizontal force that a person must apply to start the bureau moving? (b) If the drawers and clothing, with \(17 \mathrm{~kg}\) mass, are removed before the bureau is pushed, what is the new minimum magnitude?

A block slides with constant velocity down an inclined plane that has slope angle \(\theta\). The block is then projected up the same plane with an initial speed \(v_{0}\). (a) How far up the plane will it move before coming to rest? (b) After the block comes to rest, will it slide down the plane again? Give an argument to back your answer.

A warehouse worker exerts a constant horizontal force of magnitude \(85 \mathrm{~N}\) on a \(40 \mathrm{~kg}\) box that is initially at rest on the horizontal floor of the warehouse. When the box has moved a distance of \(1.4 \mathrm{~m}\), its speed is \(1.0 \mathrm{~m} / \mathrm{s}\). What is the coefficient of kinetic friction between the box and the floor?

A bicyclist travels in a circle of radius \(25.0 \mathrm{~m}\) at a constant speed of \(9.00 \mathrm{~m} / \mathrm{s}\). The bicycle-rider mass is \(85.0 \mathrm{~kg} .\) Calculate the magnitudes of (a) the force of friction on the bicycle from the road and (b) the net force on the bicycle from the road.

A student wants to determine the coefficients of static friction and kinetic friction between a box and a plank. She places the box on the plank and gradually raises one end of the plank. When the angle of inclination with the horizontal reaches \(30^{\circ}\), the box starts to slip, and it then slides \(2.5 \mathrm{~m}\) down the plank in \(4.0 \mathrm{~s}\) at constant acceleration. What are (a) the coefficient of static friction and (b) the coefficient of kinetic friction between the box and the plank?

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