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What is the bulk modulus of oxygen if \(32.0 \mathrm{~g}\) of oxygen occupies \(22.4 \mathrm{~L}\) and the speed of sound in the oxygen is \(317 \mathrm{~m} / \mathrm{s}\) ?

Short Answer

Expert verified
The bulk modulus of oxygen is 143741.4 N/m².

Step by step solution

01

Understanding the Bulk Modulus Formula

The bulk modulus (B) is a measure of a substance's resistance to uniform compression and is given by the formula: \[ B = ho v^2 \] where \( \rho \) is the density of the substance, and \( v \) is the speed of sound in the substance.
02

Calculating the Density of Oxygen

First, calculate the density (\( \rho \)) of the oxygen gas. Density is defined as mass divided by volume. Given that \(32.0 \text{ g} \) of oxygen occupies \(22.4 \text{ L} \), the density of oxygen is: \[ \rho = \frac{32.0 \text{ g}}{22.4 \text{ L}} = 1.4286 \text{ g/L} \].
03

Converting Density to SI Units

Convert the density from g/L to kg/m³ for consistency with other SI units. Knowing that \(1 \text{ g/L} = 1 \text{ kg/m}^3\), the density of oxygen is: \( \rho = 1.4286 \text{ kg/m}^3. \)
04

Substituting Values into the Formula

Now, substitute the values into the bulk modulus formula. The speed of sound in oxygen is given as \( v = 317 \text{ m/s} \), and the density of oxygen is \( \rho = 1.4286 \text{ kg/m}^3 \). Thus, the bulk modulus is: \[ B = 1.4286 \times (317)^2 \].
05

Calculating the Bulk Modulus

Compute the numerical value for the bulk modulus: \[ B = 1.4286 \times 317 \times 317 = 143741.4 \text{ N/m}^2 \].

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Density of Gases
Gases have a characteristic property known as density, which tells us how much mass is contained in a given volume. It is calculated using the formula \[ \text{Density (} \rho \text{)} = \frac{\text{mass}}{\text{volume}} \]where mass is usually in grams (g) and volume in liters (L). This calculation shows how tightly packed the molecules in a gas are. For example, in the case of oxygen in our exercise, we have 32.0 g of the gas occupying 22.4 L.
  • This leads to a density of \( \rho = \frac{32.0}{22.4} \) g/L.
For calculations in physics, density is often converted to standard international (SI) units, like kg/m³. Knowing the conversion is straightforward:
  • 1 g/L is equivalent to 1 kg/m³.
This makes computations easier, especially when linked with other SI units in formulas, such as the bulk modulus.
Speed of Sound
The speed of sound in a medium, like a gas, reflects how quickly sound waves pass through it. This speed is a crucial parameter in determining the medium's bulk modulus. The speed of sound relies on variables such as the medium's density and its elastic properties.
  • In the case of oxygen, the speed of sound is given as 317 m/s.
The formula that ties speed of sound \( v \) with density \( \rho \) in determining the bulk modulus \( B \) is:\[ B = \rho v^2 \]This equation shows that as the speed of sound increases, so does the bulk modulus. In simple terms, a higher speed of sound indicates a stiffer medium that resists compression more.
Uniform Compression
Uniform compression describes how a substance reacts evenly to applied pressure or compression across all directions. It is a core concept in understanding the bulk modulus, which quantifies this reaction. In our exercise, the bulk modulus calculation shows how resistant oxygen is to being uniformly compressed. When we know both the density and the speed of sound in the gas, the bulk modulus provides insight into this resistance.
  • A large bulk modulus value indicates high resistance to compression.
So, the bulk modulus \( B \) calculated, such as 143741.4 N/m² for oxygen here, translates to the gas's strong resistance to being compressed uniformly throughout its volume. This numerical value is crucial for various applications, including understanding sound propagation and acoustic properties through gases.

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Most popular questions from this chapter

Approximately a third of people with normal hearing have ears that continuously emit a low-intensity sound outward through the ear canal. A person with such spontaneous otoacoustic emission is rarely aware of the sound, except perhaps in a noisefree environment, but occasionally the emission is loud enough to be heard by someone else nearby. In one observation, the sound wave had a frequency of \(1665 \mathrm{~Hz}\) and a pressure amplitude of \(1.13 \times 10^{-3} \mathrm{~Pa}\). What were (a) the displacement amplitude and (b) the intensity of the wave emitted by the ear?

A violin string \(15.0 \mathrm{~cm}\) long and fixed at both ends oscillates in its \(n=1\) mode. The speed of waves on the string is \(250 \mathrm{~m} / \mathrm{s}\), and the speed of sound in air is \(348 \mathrm{~m} / \mathrm{s}\). What are the (a) frequency and (b) wavelength of the emitted sound wave?

A sound wave in a fluid medium is reflected at a barrier so that a standing wave is formed. The distance between nodes is \(3.8 \mathrm{~cm}\), and the speed of propagation is \(1500 \mathrm{~m} / \mathrm{s}\). Find the frequency of the sound wave.

Two identical piano wires have a fundamental frequency of \(600 \mathrm{~Hz}\) when kept under the same tension. What fractional increase in the tension of one wire will lead to the occurrence of \(6.0\) beats/s when both wires oscillate simultaneously?

Two trains are traveling toward each other at \(30.5 \mathrm{~m} / \mathrm{s}\) relative to the ground. One train is blowing a whistle at \(500 \mathrm{~Hz}\). (a) What frequency is heard on the other train in still air? (b) What frequency is heard on the other train if the wind is blowing at \(30.5 \mathrm{~m} / \mathrm{s}\) toward the whistle and away from the listener? (c) What frequency is heard if the wind direction is reversed?

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