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Chapter 1: Problem 39

Deceleration is sometimes measured in \(g\) 's or multiples of the standard acceleration of gravity. Determine the force, in newtons, that an automobile passenger whose mass is \(68 \mathrm{~kg}\) experiences if the deceleration in a head-on crash is \(50 \mathrm{~g}\).

Short Answer

Expert verified
The force experienced by the passenger is \( -33320 \mathrm{~N}\). The negative sign indicates the direction of the force, which is opposite to the initial velocity of the automobile.

Step by step solution

01

Identify given quantities

The mass \(m\) is given as \(68 \mathrm{~kg}\) and the deceleration \(a\) is given as \(50g\). This 'g' stands for the gravitational acceleration, which is approximately \(9.8 \mathrm{~m/s虏}\). Therefore, the deceleration is actually \(50 * 9.8 \mathrm{~m/s虏}\). Remember that since it's deceleration, it's negative.
02

Use the formula to calculate the force

We use the formula \(F=ma\). Substituting the given values into the formula, we have \(F = 68 \mathrm{~kg} * -50 * 9.8 \mathrm{~m/s虏}\).
03

Calculate the force

Multiply the mass and acceleration to get the force. Remember it will be a negative number since it's deceleration (opposite force).

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