/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 47 A vertically suspended wire has ... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

A vertically suspended wire has a cross-sectional area of \(0.1 \mathrm{in}^{2}\). A downward force, applied to the end of the wire, causes the wire to stretch. The force is increased linearly from initially zero to \(2500 \mathrm{lb}\), and the length of the wire increases by \(0.1 \%\). Select a wire length and use it to determine (a) the normal stress, in \(\mathrm{lb} /\) in. \(^{2}\), and (b) the work done in stretching the wire, in \(\mathrm{ft} \cdot \mathrm{lb}\).

Short Answer

Expert verified
The normal stress in the wire is determined by dividing the force by the cross-sectional area in the appropriate units. The work done in stretching the wire is given by the equation for work, which involves the force and the change in length of the wire, also in the appropriate units. Make sure to present your final answer in the correct units.

Step by step solution

01

Conversion of Wire Cross-Sectional Area

The cross-sectional area of the wire is given in square inches. Convert this to square feet using the known conversion factor. 1 square foot = 144 square inches. Hence the wire area, \(A = 0.1/144\) square feet.
02

Application of Normal Stress Formulation

Normal Stress is given by the formula \( σ = F/A \). Here, \(F = 2500\) lbs, and \(A\) as calculated above. The stress on the wire \( σ \) can be found by simply substituting these values into the formula.
03

Calculation for Wire Length

The length of the wire is given to increase by 0.1%. This means if we consider the initial length of wire as \( L \) (which we can conveniently select), the final length becomes \(L + 0.001L\). Let's choose \(L\) to be 100 ft for ease of calculation. Hence, final length of wire, \(L1 = 100 + 0.001(100) = 100.1\) ft.
04

Calculation for Work Done

The work, \(W\) done in stretching the wire can be calculated as \(W = ½ x F x \Delta L\), where \(\Delta L\) is the change in length of the wire. For this exercise, \(\Delta L = L1 - L = 0.1\) ft. Substituting this value and \(F = 2500\) lbs, into the work formula can give us the work done.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Mechanics of Materials
Mechanics of materials is a branch of engineering that studies the behavior of solid objects subject to stresses and strains. The discipline covers how various materials deform (elongate, compress, twist) or break as a force is applied to them.

The basic concepts involve understanding how different materials respond to various load types: tensile (pulling apart), compressive (pushing together), shear (sliding layers) and torsional (twisting). For the exercise, we focus on the tensile stress, which occurs when a material is stretched.

Engineers use the principles of mechanics of materials to design structures and objects that can withstand specific loads without failing, ensuring safety and reliability. To calculate the tensile stress on the wire, we apply these concepts. Normal stress, a type of tensile stress, is calculated by dividing the force applied to the object by the area over which the force is distributed.
Stress-Strain Analysis
Stress-strain analysis is central to understanding the mechanical behavior of materials. When a material is subjected to a load, it experiences stress (the force per unit area) and strain (the deformation of the material).

The relationship between stress and strain is essential for predicting how materials will behave under different forces. In our exercise, normal stress is calculated using the formula \( \sigma = \frac{F}{A} \), where \( \sigma \) is the normal stress, \( F \) is the force applied, and \( A \) is the cross-sectional area over which the force is applied.

Understanding the Stress-Strain Curve

Materials typically have a stress-strain curve that indicates how they will deform under various levels of stress. The initial linear portion of the curve represents the elastic region, where the material will return to its original shape after the force is removed. Beyond this region is the plastic deformation, where changes are permanent.
Work Done in Stretching
The term 'work done' in the context of stretching refers to the energy required to change the shape of a material by applying an external force. In our example, work is done to stretch the wire by a force.

The amount of work done is given by the formula \( W = \frac{1}{2} \times F \times \Delta L \) where \( W \) is the work, \( F \) is the force, and \( \Delta L \) is the change in length of the wire.

This formula assumes that the force applied to stretch the wire is gradually increased from zero up to the final force value, which makes the problem a case of work done against a variable force. Here, the factor of 1/2 accounts for the linear increase in force. For different force applications or material behaviors, this equation might look different to reflect the changes in how work is done on the material.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Search online at http://www.osha.gov and print a copy of 29 CFR \(1910.212\), General requirements for all machines. With these requirements in mind, identify a machine you have used that had a machine guard to protect the operator or other person in the machine area from hazards. Sketch the machine and label the guarding device, power source, point of operation, and danger zone.

Investigate the web site www.analyticcycling.com that provides technical methods for evaluating and estimating cycling performance. Verify that the conversion calculator provided on the web site will convert units correctly for speed (mph to \(\mathrm{km} / \mathrm{hr}\) ), temperature (F to \(\mathrm{C}\) ), and force (lb to \(\mathrm{N}\) ). Write a short paragraph on how you verified that the conversion calculator was "correct." What would increase your confidence in the conversion calculator given on the web site?

Write a report reviewing the web site http://www.uspto.gov. From a mechanical engineer's viewpoint, discuss the contents, usefulness, cost, ease of use, and clarity of the site. Identify the search tools available.

A car weighing \(3000 \mathrm{lb}\), traveling at \(60 \mathrm{mph}\), decelerates at \(0.70 \mathrm{~g}\) after the brakes are applied. Determine the force applied to slow the car. How far does the car travel in slowing to a stop? How many seconds does it take for the car to stop?

An object whose mass is \(7.8 \mathrm{~kg}\) occupies a volume of \(0.7 \mathrm{~m}^{3}\). Determine its (a) weight, in newtons, and average density, in \(\mathrm{kg} / \mathrm{m}^{3}\), at a location on the earth where \(g=9.55 \mathrm{~m} / \mathrm{s}^{2}\), (b) weight, in newtons, and average density, in \(\mathrm{kg} / \mathrm{m}^{3}\), on the moon where \(g=1.7 \mathrm{~m} / \mathrm{s}^{2}\).

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.