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It is common practice to recover waste heat from an oilor gas-fired furnace by using the exhaust gases to preheat the combustion air. A device commonly used for this purpose consists of a concentric pipe arrangement for which the exhaust gases are passed through the inner pipe, while the cooler combustion air flows through an annular passage around the pipe. Consider conditions for which there is a uniform heat transfer rate per unit length, \(q_{i}^{\prime}=1.25 \times 10^{5} \mathrm{~W} / \mathrm{m}\), from the exhaust gases to the pipe inner surface, while air flows through the annular passage at a rate of \(\dot{m}_{a}=2.1 \mathrm{~kg} / \mathrm{s}\). The thin- walled inner pipe is of diameter \(D_{i}=2 \mathrm{~m}\), while the outer pipe, which is well insulated from the surroundings, is of diameter \(D_{o}=2.05 \mathrm{~m}\). The air properties may be taken to be \(c_{p}=1030 \mathrm{~J} / \mathrm{kg} \cdot \mathrm{K}, \mu=270 \times 10^{-7} \mathrm{~N} \cdot \mathrm{s} / \mathrm{m}^{2}, k=0.041\) \(\mathrm{W} / \mathrm{m} \cdot \mathrm{K}\), and \(P r=0.68\). (a) If air enters at \(T_{a, 1}=300 \mathrm{~K}\) and \(L=7 \mathrm{~m}\), what is the air outlet temperature \(T_{a, 2}\) ? (b) If the airflow is fully developed throughout the annular region, what is the temperature of the inner pipe at the inlet \(\left(T_{s, i, 1}\right)\) and outlet \(\left(T_{s, i, 2}\right)\) sections of the device? What is the outer surface temperature \(T_{s, \theta, 1}\) at the inlet?

Short Answer

Expert verified
To find the air outlet temperature, we first calculate the total heat transfer rate and the temperature increase, and then we add this temperature increase to the initial air temperature. Next, we determine the temperature of the inner pipe at the inlet and outlet using the heat transfer rate and the air properties. Finally, we find the outer surface temperature at the inlet using the temperature distribution for fully developed flow in the annular passage. Following this procedure, we obtain the air outlet temperature \(T_{a,2}\), the temperature of the inner pipe at the inlet \(T_{s,i,1}\) and outlet \(T_{s,i,2}\), and the outer surface temperature at the inlet \(T_{s,θ,1}\).

Step by step solution

01

Find the air outlet temperature (Ta2)

Using the heat transfer rate per unit length and the air mass flow rate, we can find the temperature increase in the air across the length of the pipe. Then, we add this temperature increase to the initial air temperature to find the air outlet temperature. Calculate the total heat transfer rate from the exhaust gases to the annular air passage: \(Q = q_{i}^{\prime} \times L\) Now we need to find the temperature increase (∆T) using the mass flow rate, specific heat capacity, and the heat transfer rate: \(\Delta T = \frac{Q}{\dot{m}_{a} \times c_{p}}\) Finally, calculate the air outlet temperature Ta2 using the initial air temperature (Ta1) and the temperature increase: \(T_{a,2} = T_{a,1} + \Delta T\)
02

Determine the temperature of the inner pipe at the inlet (Ts,i,1) and outlet (Ts,i,2)

We can find the temperature of the inner pipe at the inlet and outlet by using the heat transfer rate and the air properties. Use the given uniform heat transfer rate per unit length to find the total heat transfer rate at the inlet and outlet sections: \(q_{i,1}^{\prime} = q_{i,2}^{\prime} = q_{i}^{\prime}\) Then, determine the convection heat transfer coefficient (h) at the inlet and outlet using Nusselt number and thermal conductivity (k) : \(h_{1} = h_{2} = \frac{q_{i,1}^{\prime}}{T_{s,i,1} - T_{a,1}} = \frac{q_{i,2}^{\prime}}{T_{s,i,2} - T_{a,2}}\) Now, we have two equations with two unknowns, Ts,i,1 and Ts,i,2. Solve for both temperatures using these equations.
03

Find the outer surface temperature at the inlet (Ts,θ,1)

To find the outer surface temperature at the inlet, we need to use the temperature distribution for fully developed flow in the annular passage. The temperature distribution for fully developed flow in an annular passage is given by: \(T(r) = T_{s,i,1} + k \left(\frac{1}{r} - \frac{1}{r_{o}}\right)\left(\frac{T_{s,i,1} - T_{a,1}}{h}\right)\) By substituting the values of inner pipe temperature at the inlet Ts,i,1, and air inlet temperature Ta1, we can find the temperature at the outer surface (r = ro) of the annular passage, Ts,θ,1.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Concentric Pipe Arrangement
The concentric pipe arrangement is a common setup in heat exchanger design. Imagine two pipes, one inside the other. The inner pipe carries a fluid, such as exhaust gases, and the outer pipe carries a different fluid, like combustion air. In this setup, heat is transferred from one fluid to the other.
This type of arrangement is particularly useful when you want to recover waste heat. For example, hot exhaust gases can preheat cooler air flowing through the outer pipe. This makes fuel combustion more efficient.
  • Inner Pipe: Carries the hot fluid.
  • Outer Pipe: Carries the cooler fluid.
  • Annular Space: The gap between the pipes where the cooler fluid flows.
The concentric arrangement ensures maximum surface area contact between the hot and cooler fluids. This contact enhances the overall heat transfer efficiency.
Heat Transfer Rate
The heat transfer rate indicates how much heat energy is being transferred over time. In heat exchangers, this is a critical factor to ensure efficiency. In the exercise, the heat transfer rate per unit length was given as \( q_{i}^{\prime} = 1.25 \times 10^{5} \mathrm{~W/m} \).
This value tells us how much heat is transferred from the exhaust gases to the air flowing through the annular space.
  • Calculation of Total Heat Transfer: To find the total heat transferred, multiply the heat transfer rate per unit length by the total pipe length \( L \). This gives the total heat energy that flows from the exhaust gases to the air.
  • Importance: The heat transfer rate determines how effective the heat exchanger is in transferring energy.
Understanding this helps in designing systems that are energy-efficient and meet the desired heating or cooling requirements.
Thermal Conductivity
Thermal conductivity \( k \) measures a material's ability to conduct heat. It is a crucial property in heat exchanger design as it influences heat transfer efficiency. In this scenario, the thermal conductivity of the air was \( k = 0.041 \, \mathrm{W/m \cdot K} \).
Higher thermal conductivity means better heat conduction. Materials such as metals often have high thermal conductivity, making them excellent for heat exchangers.
  • Influence on Heat Exchanger: A higher \( k \) value ensures more effective heat transfer across materials, enhancing system performance.
  • Role in Calculations: Thermal conductivity is used in conjunction with the Nusselt number and the convection heat transfer coefficient to evaluate overall heat transfer.
Understanding thermal conductivity helps engineers choose appropriate materials for different parts of the heat exchanger to optimize performance.
Nusselt Number
The Nusselt number \( Nu \) is a dimensionless quantity that provides insight into the convection heat transfer occurring in a fluid. It relates the convective to conductive heat transfer across a boundary.
For heat exchangers, the Nusselt number helps determine the efficiency of heat transfer from one fluid to another. In general, a high Nusselt number indicates efficient convection compared to conduction.
  • Importance in Heat Exchangers: The Nusselt number is used to calculate the convection heat transfer coefficient \( h \), which in turn defines how well heat is transferred between the pipe surface and the fluid.
  • Relation to Thermal Conductivity \( k \): The Nusselt number is derived from the formula \( Nu = \frac{hL}{k} \), where \( h \) is the heat transfer coefficient and \( L \) is the characteristic length.
Understanding and calculating the Nusselt number is key to improving heat exchanger design, ensuring optimal thermal performance.

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Most popular questions from this chapter

Fluid enters a thin-walled tube of \(5-\mathrm{mm}\) diameter and \(2-\mathrm{m}\) length with a flow rate of \(0.04 \mathrm{~kg} / \mathrm{s}\) and a temperature of \(T_{m, i}=85^{\circ} \mathrm{C}\). The tube surface is maintained at a temperature of \(T_{s}=25^{\circ} \mathrm{C}\), and for this operating condition, the outlet temperature is \(T_{m, o}=31.1^{\circ} \mathrm{C}\). What is the outlet temperature if the flow rate is doubled? Fully developed, turbulent flow may be assumed to exist in both cases, and the fluid properties may be assumed to be independent of temperature.

Water at \(290 \mathrm{~K}\) and \(0.2 \mathrm{~kg} / \mathrm{s}\) flows through a Teflon tube \((k=0.35 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K})\) of inner and outer radii equal to 10 and \(13 \mathrm{~mm}\), respectively. A thin electrical heating tape wrapped around the outer surface of the tube delivers a uniform surface heat flux of \(2000 \mathrm{~W} / \mathrm{m}^{2}\), while a convection coefficient of \(25 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}\) is maintained on the outer surface of the tape by ambient air at \(300 \mathrm{~K}\). What is the fraction of the power dissipated by the tape, which is transferred to the water? What is the outer surface temperature of the Teflon tube?

Water at \(\dot{m}=0.02 \mathrm{~kg} / \mathrm{s}\) and \(T_{m, i}=20^{\circ} \mathrm{C}\) enters an annular region formed by an inner tube of diameter \(D_{i}=25 \mathrm{~mm}\) and an outer tube of diameter \(D_{o}=100 \mathrm{~mm}\). Saturated steam flows through the inner tube, maintaining its surface at a uniform temperature of \(T_{s, i}=100^{\circ} \mathrm{C}\), while the outer surface of the outer tube is well insulated. If fully developed conditions may be assumed throughout the annulus, how long must the system be to provide an outlet water temperature of \(75^{\circ} \mathrm{C}\) ? What is the heat flux from the inner tube at the outlet?

Many of the solid surfaces for which values of the thermal and momentum accommodation coefficients have been measured are quite different from those used in micro- and nanodevices. Plot the Nusselt number \(N u_{D}\) associated with fully developed laminar flow with constant surface heat flux versus tube diameter for \(1 \mu \mathrm{m} \leq D \leq 1 \mathrm{~mm}\) and (i) \(\alpha_{s}=1, \alpha_{p}=1\), (ii) \(\alpha_{t}=0.1, \alpha_{p}=0.1\), (iii) \(\alpha_{t}=1, \alpha_{p}=0.1\), and (iv) \(\alpha_{t}=0.1, \alpha_{p}=1\). For tubes of what diameter do the accommodation coefficients begin to influence convection heat transfer? For which combination of \(\alpha_{t}\) and \(\alpha_{p}\) does the Nusselt number exhibit the least sensitivity to changes in the diameter of the tube? Which combination results in Nusselt numbers greater than the conventional fully developed laminar value for constant heat flux conditions, \(N u_{D}=4.36\) ? Which combination is associated with the smallest Nusselt numbers? What can you say about the ability to predict convection heat transfer coefficients in a small-scale device if the accommodation coefficients are not known for material from which the device is fabricated? Use properties of air at atmospheric pressure and \(T=300 \mathrm{~K}\).

Consider a concentric tube annulus for which the inner and outer diameters are 25 and \(50 \mathrm{~mm}\). Water enters the annular region at \(0.04 \mathrm{~kg} / \mathrm{s}\) and \(25^{\circ} \mathrm{C}\). If the inner tube wall is heated electrically at a rate (per unit length) of \(q^{\prime}=4000 \mathrm{~W} / \mathrm{m}\), while the outer tube wall is insulated, how long must the tubes be for the water to achieve an outlet temperature of \(85^{\circ} \mathrm{C}\) ? What is the inner tube surface temperature at the outlet, where fully developed conditions may be assumed?

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