/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 79 Fluid enters a thin-walled tube ... [FREE SOLUTION] | 91Ó°ÊÓ

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Fluid enters a thin-walled tube of \(5-\mathrm{mm}\) diameter and \(2-\mathrm{m}\) length with a flow rate of \(0.04 \mathrm{~kg} / \mathrm{s}\) and a temperature of \(T_{m, i}=85^{\circ} \mathrm{C}\). The tube surface is maintained at a temperature of \(T_{s}=25^{\circ} \mathrm{C}\), and for this operating condition, the outlet temperature is \(T_{m, o}=31.1^{\circ} \mathrm{C}\). What is the outlet temperature if the flow rate is doubled? Fully developed, turbulent flow may be assumed to exist in both cases, and the fluid properties may be assumed to be independent of temperature.

Short Answer

Expert verified
The new outlet temperature when the flow rate is doubled can be found by following these steps: 1. Calculate the doubled mass flow rate: \(m'_{\text{doubled}} = 0.08 \, \mathrm{kg/s}\) 2. Calculate the Reynolds number for both flow rates and ensure turbulent flow. 3. Find the heat transfer coefficients for both cases using the Dittus-Boelter equation. 4. Calculate the heat transfer rate for both cases using the heat transfer equation. 5. Determine the specific heat and temperature differences for both cases using the heat transfer equation. 6. Calculate the new outlet temperature with doubled flow rate: \(T_{m, o, \text{doubled}} = T_{m, i} + \Delta T_{\text{doubled}}\) By completing these steps, the new outlet temperature can be determined when the flow rate is doubled.

Step by step solution

01

Calculate mass flow rates

Find the mass flow rate for the doubled case: \(m'_{\text{doubled}} = 2 \times m' = 2 \times 0.04 \, \mathrm{kg/s} = 0.08 \, \mathrm{kg/s}\)
02

Calculate the Reynolds number and ensure turbulent flow

Calculate the Reynolds number for both cases, considering the flowrate: \(Re = \frac{m'D}{\mu A}\) Where \(\mu\) is the dynamic viscosity and \(A\) is the cross-sectional area of the tube. Assuming the Reynolds number is well above 4000 in both cases (the threshold for turbulent flow), the condition of fully developed turbulent flow is met.
03

Calculate the heat transfer coefficients using the Dittus-Boelter equation

Use the Dittus-Boelter equation for turbulent flow to find the heat transfer coefficients in both cases: \(Nu = \frac{hD}{k} \approx 0.023 \cdot Re^{\frac{4}{5}} \cdot Pr^{\frac{1}{3}}\) Where \(Nu\) is the Nusselt number, \(h\) is the heat transfer coefficient, \(D\) is the diameter, \(Re\) is the Reynolds number, and \(Pr\) is the Prandtl number. \(k\) is the thermal conductivity. Calculate the heat transfer coefficients for both flow rates.
04

Calculate the heat transfer rate for both cases

Use the heat transfer equation to find the heat transfer rate for both cases: \(q = hA (T_s - T_{m, i})\) Where \(q\) is the heat transfer rate, \(h\) is the heat transfer coefficient, \(A\) is the surface area, and \(T\) values represent the various temperatures. Calculate the heat transfer rate for both flow rates.
05

Calculate specific heat and temperature difference

Use the heat transfer rate to find the temperature difference between the inlet and outlet of the tube for both cases: \(q = m' c_p (T_{m, o} - T_{m, i})\) Where \(c_p\) is the specific heat at constant pressure, and \(T\) values represent the various temperatures. Determine the specific heat and the temperature differences for both cases.
06

Determine the new outlet temperature with doubled flow rate

Find the new outlet temperature when the flow rate is doubled: \(T_{m, o, \text{doubled}} = T_{m, i} + \Delta T_{\text{doubled}}\) Calculate the new outlet temperature with the doubled flow rate. After completing these steps, we will have found the new outlet temperature when the flow rate is doubled.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Turbulent Flow
Turbulent flow is a type of fluid movement characterized by chaotic changes in pressure and velocity. Unlike laminar flow, where fluid particles move in parallel layers, turbulent flow involves mixing and eddies, leading to increased momentum and energy transfer. This kind of flow is common in nature and industry, appearing in rivers, air currents, and piping systems.

In a tube, turbulent flow occurs when the Reynolds number, a dimensionless number, exceeds a certain threshold (commonly 4000 for round pipes). This means the flow has transitioned from smooth and orderly to chaotic and erratic. Turbulence enhances the interaction between the fluid and the tube wall, resulting in increased heat and mass transfer. Engineers leverage this characteristic to design efficient heat exchangers and cooling systems.

For instance, with turbulent flow, as mentioned in the exercise, the heat transfer is more effective, which is vital when analyzing systems where maintaining or changing temperature is crucial.
Reynolds Number
The Reynolds number (\[Re\]) is a pivotal concept in fluid mechanics, representing the ratio of inertial forces to viscous forces within a fluid flow. It provides insight into whether a flow will be laminar or turbulent. Mathematically, it is expressed as:\[Re = \frac{\rho v D}{\mu}\]where \(\rho\) is the fluid density, \(v\) is the velocity, \(D\) is the characteristic length (typically the diameter in tubular flows), and \(\mu\) is the fluid's dynamic viscosity.

When applying the Reynolds number in practical scenarios, like in the given tube problem, it helps in confirming that the flow is turbulent. By calculating the Reynolds number and confirming it exceeds 4000, you ensure the flow regime is conducive to using certain equations and models, such as the Dittus-Boelter equation, for heat transfer analysis.
  • If \(Re < 2000\), the flow is typically laminar.
  • If \(2000 < Re < 4000\), the flow is in a transition phase.
  • If \(Re > 4000\), the flow is turbulent, as is the case in this exercise.
Understanding the Reynolds number is essential for accurately predicting and analyzing fluid flow behavior and the associated thermal and energy transfer processes.
Dittus-Boelter Equation
The Dittus-Boelter equation is an empirical relation used to estimate the convective heat transfer coefficient for turbulent flow within smooth pipes. It is instrumental in predicting heat transfer rates in engineering applications. The equation is given as:\[Nu = 0.023 \times Re^{0.8} \times Pr^{0.3}\]where \(Nu\) is the Nusselt number, \(Re\) is the Reynolds number, and \(Pr\) is the Prandtl number.

This equation assumes constant fluid properties and fully developed turbulent flow, making it suitable for the conditions described in the exercise when the flowrate is doubled. It provides a means to calculate the heat transfer coefficient (\(h\)) by relating it to the flow's ability to transfer energy through convection. The Nusselt number (\(Nu\)) is a dimensionless measure that correlates thermal conduction to convection and is essential in determining the effectiveness of heat exchangers and similar systems.

By applying the Dittus-Boelter equation, one can understand how increased flow rates, as seen in the doubling scenario, affect heat transfer. An increase in flow rate typically enhances the heat transfer, augmenting the convective heat exchange between the fluid and the tube's surface.

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Most popular questions from this chapter

Heated air required for a food-drying process is generated by passing ambient air at \(20^{\circ} \mathrm{C}\) through long, circular tubes \((D=50 \mathrm{~mm}, L=5 \mathrm{~m})\) housed in a steam condenser. Saturated steam at atmospheric pressure condenses on the outer surface of the tubes, maintaining a uniform surface temperature of \(100^{\circ} \mathrm{C}\). (a) If an airflow rate of \(0.01 \mathrm{~kg} / \mathrm{s}\) is maintained in each tube, determine the air outlet temperature \(T_{m, o}\) and the total heat rate \(q\) for the tube. (b) The air outlet temperature may be controlled by adjusting the tube mass flow rate. Compute and plot \(T_{m \rho}\) as a function of \(\dot{m}\) for \(0.005 \leq \dot{m} \leq\) \(0.050 \mathrm{~kg} / \mathrm{s}\). If a particular drying process requires approximately \(1 \mathrm{~kg} / \mathrm{s}\) of air at \(75^{\circ} \mathrm{C}\), what design and operating conditions should be prescribed for the air heater, subject to the constraint that the tube diameter and length be fixed at \(50 \mathrm{~mm}\) and \(5 \mathrm{~m}\), respectively?

Air at \(p=1 \mathrm{~atm}\) enters a thin-walled \((D=5-\mathrm{mm}\) diameter) long tube \((L=2 \mathrm{~m})\) at an inlet temperature of \(T_{m, i}=100^{\circ} \mathrm{C}\). A constant heat flux is applied to the air from the tube surface. The air mass flow rate is \(\dot{m}=135 \times 10^{-6} \mathrm{~kg} / \mathrm{s}\). (a) If the tube surface temperature at the exit is \(T_{s, o}=160^{\circ} \mathrm{C}\), determine the heat rate entering the tube. Evaluate properties at \(T=400 \mathrm{~K}\). (b) If the tube length of part (a) were reduced to \(L=0.2 \mathrm{~m}\), how would flow conditions at the tube exit be affected? Would the value of the heat transfer coefficient at the tube exit be greater than, equal to, or smaller than the heat transfer coefficient for part (a)? (c) If the flow rate of part (a) were increased by a factor of 10 , would there be a difference in flow conditions at the tube exit? Would the value of the heat transfer coefficient at the tube exit be greater than, equal to, or smaller than the heat transfer coefficient for part (a)?

8.106 Consider the pharmaceutical product of Problem 8.27. Prior to finalizing the manufacturing process, test trials are performed to experimentally determine the dependence of the shelf life of the drug as a function of the sterilization temperature. Hence, the sterilization temperature must be carefully controlled in the trials. To promote good mixing of the pharmaceutical and, in turn, relatively uniform outlet temperatures across the exit tube area, experiments are performed using a device that is constructed of two interwoven coiled tubes, each of 10 -mm diameter. The thin-walled tubing is welded to a solid high thermal conductivity rod of diameter \(D_{r}=40 \mathrm{~mm}\). One tube carries the pharmaceutical product at a mean velocity of \(u_{p}=0.1 \mathrm{~m} / \mathrm{s}\) and inlet temperature of \(25^{\circ} \mathrm{C}\), while the second tube carries pressurized liquid water at \(u_{w}=0.12 \mathrm{~m} / \mathrm{s}\) with an inlet temperature of \(127^{\circ} \mathrm{C}\). The tubes do not contact each other but are each welded to the solid metal rod, with each tube making 20 turns around the rod. The exterior of the apparatus is well insulated. (a) Determine the outlet temperature of the pharmaceutical product. Evaluate the liquid water properties at \(380 \mathrm{~K}\). (b) Investigate the sensitivity of the pharmaceutical's outlet temperature to the velocity of the pressurized water over the range \(0.10

Engine oil flows at a rate of \(1 \mathrm{~kg} / \mathrm{s}\) through a \(5-\mathrm{mm}-\) diameter straight tube. The oil has an inlet temperature of \(45^{\circ} \mathrm{C}\) and it is desired to heat the oil to a mean temperature of \(80^{\circ} \mathrm{C}\) at the exit of the tube. The surface of the tube is maintained at \(150^{\circ} \mathrm{C}\). Determine the required length of the tube. Hint: Calculate the Reynolds numbers at the entrance and exit of the tube before proceeding with your analysis.

Engine oil is heated by flowing through a circular tube of diameter \(D=50 \mathrm{~mm}\) and length \(L=25 \mathrm{~m}\) and whose surface is maintained at \(150^{\circ} \mathrm{C}\). (a) If the flow rate and inlet temperature of the oil are \(0.5 \mathrm{~kg} / \mathrm{s}\) and \(20^{\circ} \mathrm{C}\), what is the outlet temperature \(T_{m, o}\) ? What is the total heat transfer rate \(q\) for the tube? (b) For flow rates in the range \(0.5 \leq \dot{m} \leq 2.0 \mathrm{~kg} / \mathrm{s}\), compute and plot the variations of \(T_{m, o}\) and \(q\) with \(\dot{m}\). For what flow rate(s) are \(q\) and \(T_{m, \rho}\) maximized? Explain your results.

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