/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 79 Fluid enters a thin-walled tube ... [FREE SOLUTION] | 91Ó°ÊÓ

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Fluid enters a thin-walled tube of \(5-\mathrm{mm}\) diameter and \(2-\mathrm{m}\) length with a flow rate of \(0.04 \mathrm{~kg} / \mathrm{s}\) and a temperature of \(T_{m, i}=85^{\circ} \mathrm{C}\). The tube surface is maintained at a temperature of \(T_{s}=25^{\circ} \mathrm{C}\), and for this operating condition, the outlet temperature is \(T_{m, o}=31.1^{\circ} \mathrm{C}\). What is the outlet temperature if the flow rate is doubled? Fully developed, turbulent flow may be assumed to exist in both cases, and the fluid properties may be assumed to be independent of temperature.

Short Answer

Expert verified
The new outlet temperature when the flow rate is doubled can be found by following these steps: 1. Calculate the doubled mass flow rate: \(m'_{\text{doubled}} = 0.08 \, \mathrm{kg/s}\) 2. Calculate the Reynolds number for both flow rates and ensure turbulent flow. 3. Find the heat transfer coefficients for both cases using the Dittus-Boelter equation. 4. Calculate the heat transfer rate for both cases using the heat transfer equation. 5. Determine the specific heat and temperature differences for both cases using the heat transfer equation. 6. Calculate the new outlet temperature with doubled flow rate: \(T_{m, o, \text{doubled}} = T_{m, i} + \Delta T_{\text{doubled}}\) By completing these steps, the new outlet temperature can be determined when the flow rate is doubled.

Step by step solution

01

Calculate mass flow rates

Find the mass flow rate for the doubled case: \(m'_{\text{doubled}} = 2 \times m' = 2 \times 0.04 \, \mathrm{kg/s} = 0.08 \, \mathrm{kg/s}\)
02

Calculate the Reynolds number and ensure turbulent flow

Calculate the Reynolds number for both cases, considering the flowrate: \(Re = \frac{m'D}{\mu A}\) Where \(\mu\) is the dynamic viscosity and \(A\) is the cross-sectional area of the tube. Assuming the Reynolds number is well above 4000 in both cases (the threshold for turbulent flow), the condition of fully developed turbulent flow is met.
03

Calculate the heat transfer coefficients using the Dittus-Boelter equation

Use the Dittus-Boelter equation for turbulent flow to find the heat transfer coefficients in both cases: \(Nu = \frac{hD}{k} \approx 0.023 \cdot Re^{\frac{4}{5}} \cdot Pr^{\frac{1}{3}}\) Where \(Nu\) is the Nusselt number, \(h\) is the heat transfer coefficient, \(D\) is the diameter, \(Re\) is the Reynolds number, and \(Pr\) is the Prandtl number. \(k\) is the thermal conductivity. Calculate the heat transfer coefficients for both flow rates.
04

Calculate the heat transfer rate for both cases

Use the heat transfer equation to find the heat transfer rate for both cases: \(q = hA (T_s - T_{m, i})\) Where \(q\) is the heat transfer rate, \(h\) is the heat transfer coefficient, \(A\) is the surface area, and \(T\) values represent the various temperatures. Calculate the heat transfer rate for both flow rates.
05

Calculate specific heat and temperature difference

Use the heat transfer rate to find the temperature difference between the inlet and outlet of the tube for both cases: \(q = m' c_p (T_{m, o} - T_{m, i})\) Where \(c_p\) is the specific heat at constant pressure, and \(T\) values represent the various temperatures. Determine the specific heat and the temperature differences for both cases.
06

Determine the new outlet temperature with doubled flow rate

Find the new outlet temperature when the flow rate is doubled: \(T_{m, o, \text{doubled}} = T_{m, i} + \Delta T_{\text{doubled}}\) Calculate the new outlet temperature with the doubled flow rate. After completing these steps, we will have found the new outlet temperature when the flow rate is doubled.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Turbulent Flow
Turbulent flow is a type of fluid movement characterized by chaotic changes in pressure and velocity. Unlike laminar flow, where fluid particles move in parallel layers, turbulent flow involves mixing and eddies, leading to increased momentum and energy transfer. This kind of flow is common in nature and industry, appearing in rivers, air currents, and piping systems.

In a tube, turbulent flow occurs when the Reynolds number, a dimensionless number, exceeds a certain threshold (commonly 4000 for round pipes). This means the flow has transitioned from smooth and orderly to chaotic and erratic. Turbulence enhances the interaction between the fluid and the tube wall, resulting in increased heat and mass transfer. Engineers leverage this characteristic to design efficient heat exchangers and cooling systems.

For instance, with turbulent flow, as mentioned in the exercise, the heat transfer is more effective, which is vital when analyzing systems where maintaining or changing temperature is crucial.
Reynolds Number
The Reynolds number (\[Re\]) is a pivotal concept in fluid mechanics, representing the ratio of inertial forces to viscous forces within a fluid flow. It provides insight into whether a flow will be laminar or turbulent. Mathematically, it is expressed as:\[Re = \frac{\rho v D}{\mu}\]where \(\rho\) is the fluid density, \(v\) is the velocity, \(D\) is the characteristic length (typically the diameter in tubular flows), and \(\mu\) is the fluid's dynamic viscosity.

When applying the Reynolds number in practical scenarios, like in the given tube problem, it helps in confirming that the flow is turbulent. By calculating the Reynolds number and confirming it exceeds 4000, you ensure the flow regime is conducive to using certain equations and models, such as the Dittus-Boelter equation, for heat transfer analysis.
  • If \(Re < 2000\), the flow is typically laminar.
  • If \(2000 < Re < 4000\), the flow is in a transition phase.
  • If \(Re > 4000\), the flow is turbulent, as is the case in this exercise.
Understanding the Reynolds number is essential for accurately predicting and analyzing fluid flow behavior and the associated thermal and energy transfer processes.
Dittus-Boelter Equation
The Dittus-Boelter equation is an empirical relation used to estimate the convective heat transfer coefficient for turbulent flow within smooth pipes. It is instrumental in predicting heat transfer rates in engineering applications. The equation is given as:\[Nu = 0.023 \times Re^{0.8} \times Pr^{0.3}\]where \(Nu\) is the Nusselt number, \(Re\) is the Reynolds number, and \(Pr\) is the Prandtl number.

This equation assumes constant fluid properties and fully developed turbulent flow, making it suitable for the conditions described in the exercise when the flowrate is doubled. It provides a means to calculate the heat transfer coefficient (\(h\)) by relating it to the flow's ability to transfer energy through convection. The Nusselt number (\(Nu\)) is a dimensionless measure that correlates thermal conduction to convection and is essential in determining the effectiveness of heat exchangers and similar systems.

By applying the Dittus-Boelter equation, one can understand how increased flow rates, as seen in the doubling scenario, affect heat transfer. An increase in flow rate typically enhances the heat transfer, augmenting the convective heat exchange between the fluid and the tube's surface.

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Most popular questions from this chapter

Atmospheric air enters the heated section of a circular tube at a flow rate of \(0.005 \mathrm{~kg} / \mathrm{s}\) and a temperature of \(20^{\circ} \mathrm{C}\). The tube is of diameter \(D=50 \mathrm{~mm}\), and fully developed conditions with \(h=25 \mathrm{~W} / \mathrm{m}^{2}+\mathrm{K}\) exist over the entire length of \(L=3 \mathrm{~m}\). (a) For the case of uniform surface heat flux at \(q_{s}^{\prime \prime}=1000 \mathrm{~W} / \mathrm{m}^{2}\), determine the total heat transfer rate \(q\) and the mean temperature of the air leaving the tube \(T_{m \rho^{-}}\)What is the value of the surface temperature at the tube inlet \(T_{s, i}\) and outlet \(T_{s, \rho}\) ? Sketch the axial variation of \(T_{s}\) and \(T_{m}\). On the same figure, also sketch (qualitatively) the axial variation of \(T_{s}\) and \(T_{m}\) for the more realistic case in which the local convection coefficient varies with \(x\). (b) If the surface heat flux varies linearly with \(x\), such that \(q_{s}^{\prime \prime}\left(\mathrm{W} / \mathrm{m}^{2}\right)=500 x(\mathrm{~m})\), what are the values of \(q, T_{m, o}, T_{s, j}\), and \(T_{s, o}\) ? Sketch the axial variation of \(T_{s}\) and \(T_{m-}\) On the same figure, also sketch (qualitatively) the axial variation of \(T_{s}\) and \(T_{m}\) for the more realistic case in which the local convection coefficient varies with \(x\). (c) For the two heating conditions of parts (a) and (b), plot the mean fluid and surface temperatures, \(T_{m}(x)\) and \(T_{s}(x)\), respectively, as functions of distance along the tube. What effect will a fourfold increase in the convection coefficient have on the temperature distributions? (d) For each type of heating process, what heat fluxes are required to achieve an air outlet temperature of \(125^{\circ} \mathrm{C}\) ? Plot the temperature distributions.

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