/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 75 A 20 -mm-diameter sphere is susp... [FREE SOLUTION] | 91Ó°ÊÓ

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A 20 -mm-diameter sphere is suspended in a dry airstream with a temperature of \(22^{\circ} \mathrm{C}\). The power supplied to an embedded electrical heater within the sphere is \(2.51 \mathrm{~W}\) when the surface temperature is \(32^{\circ} \mathrm{C}\). How much power is required to maintain the sphere at \(32^{\circ} \mathrm{C}\) if its outer surface has a thin porous covering saturated with water? Evaluate the properties of air and the diffusion coefficient of the air-water vapor mixture at \(300 \mathrm{~K}\).

Short Answer

Expert verified
To maintain the sphere at \(32^{\circ} \mathrm{C}\) with the water covering, we need to evaluate the properties of air at \(300\mathrm{K}\) and find the convection heat transfer coefficient. Then, calculate the heat transfer for the sphere with the water covering using the heat transfer equation for a sphere: \(Q = hA(T_{sphere} - T_{\infty})\). Finally, find the additional power needed as the difference between the heat transfer for the sphere with the water covering and the initial heat transfer. Add this additional power to the initial power (2.51 W) to find the total power required.

Step by step solution

01

Find the initial heat transfer without the water covering

We are given that the initial power required to maintain the sphere at \(32^{\circ}\mathrm{C}\) without the water covering is \(2.51\mathrm{W}\). This power is equal to the heat transfer from the sphere to the dry air. Since we are given the power as \(2.51\mathrm{W}\), we do not need to calculate the heat transfer, as it is already provided for us.
02

Evaluate the properties of air and the diffusion coefficient

We need to evaluate the properties of air at \(300\mathrm{K}\) to find the convection heat transfer coefficient. We can consult the air table or property database to find these properties. It is important to note that the diffusion coefficient might be given for different reference conditions, such as pressure. Therefore, make sure to use values at the correct reference conditions.
03

Find the convection heat transfer coefficient

Once we have the properties of air at the given temperature, we can find the convection heat transfer coefficient (\(h\)) using appropriate correlations for natural or forced convection. This can be done using the Nusselt number, a dimensionless quantity that describes the efficiency of heat transfer. The choice of the correlation will depend on the properties and whether the airflow is driven by buoyancy (natural convection) or by external means (forced convection). Keep in mind that it may be required to first determine the Reynolds number (\(Re\)) and Prandtl number (\(Pr\)) to decide which correlation is applicable for the problem.
04

Determine heat transfer for the sphere with a water covering

Now that we have the convection heat transfer coefficient, we can find the heat transfer for the sphere with the water covering. We can use the heat transfer equation for a sphere: \(Q = hA(T_{sphere} - T_{\infty})\), where \(Q\) is the heat transfer, \(A\) is the sphere's surface area, \(T_{sphere}\) is the temperature of the sphere, and \(T_{\infty}\) is the temperature of the air far from the sphere. We already have an estimate of \(h\) from Step 3, and the surface area \(A\) can be calculated as \(4\pi r^2\), where \(r\) is the radius of the sphere. The temperatures of the sphere and air are given as \(32^{\circ}\mathrm{C}\) and \(22^{\circ}\mathrm{C}\), respectively. Plug these values into the equation and solve for \(Q\): \( Q = h \cdot 4\pi r^2 (32 - 22) \).
05

Calculate the additional power needed to maintain the temperature

Finally, with the heat transfer for the sphere with the water covering, we can find the additional power needed to maintain the sphere's temperature as the difference between the heat transfer for the sphere with the water covering and the initial heat transfer. Additional power needed = \(Q_{water covering} - Q_{initial}\) Once we find this additional power, we can add it to the initial power (2.51 W) to find the total power required to maintain the sphere at \(32^{\circ}\mathrm{C}\) with the water covering. Keep in mind that numerical answers are dependent on the specific air properties and the convection correlation used in the solution process.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Convection Heat Transfer Coefficient
The convection heat transfer coefficient, denoted as h, is a key element in the analysis of convection heat transfer. It quantifies how effectively heat is transferred from a solid surface to a fluid or from fluid to fluid. In technical terms, it represents the amount of heat transferred per unit surface area per unit temperature difference between the solid surface and the surrounding fluid.

Importance in Calculations

The value of h is critical in determining the rate of heat transfer across surfaces. For the problem regarding the sphere in air flow, calculating the appropriate convection heat transfer coefficient allows for an accurate determination of the heat loss or gain from the sphere. It is a function of several variables, including fluid velocity, viscosity, thermal conductivity, and surface geometry, and requires careful evaluation for accurate results.
Nusselt Number
The Nusselt number (Nu) is a dimensionless quantity used in heat transfer to represent the enhancement of heat transfer through a fluid as a result of convection relative to conduction. It's defined as the ratio of convective to conductive heat transfer across a boundary.

Application in Heat Transfer

For the sphere's heat transfer, the Nusselt number is crucial in correlating empirical data and dimensional analysis. Expressing Nu in terms of other dimensionless numbers allows engineers to use established correlations from literature or experiments to find the convection heat transfer coefficient. These correlations often involve the Reynolds number and the Prandtl number, which combine the effects of fluid flow and thermal properties.
Reynolds Number
The Reynolds number (Re) is another dimensionless quantity that indicates whether the flow of a fluid is laminar or turbulent. Defined as the ratio of inertial forces to viscous forces, it is obtained by multiplying the density of the fluid, the velocity of the fluid, and a characteristic length of the geometry, and then dividing by the fluid's dynamic viscosity.

Significance in Fluid Dynamics

The Reynolds number is pivotal for understanding the flow pattern around the sphere. It helps decide which convection heat transfer correlation should be used to calculate the Nusselt number. For instance, if the flow is laminar, a different set of correlations applies compared to turbulent flow. Recognizing the flow regime is essential for an accurate calculation of heat transfer.
Prandtl Number
Prandtl number (Pr) serves as a dimensionless parameter that characterizes the relative thickness of the velocity and thermal boundary layers in a fluid. It is defined by the ratio of kinematic viscosity to thermal diffusivity.

Relevance in Convection Studies

The Prandtl number indicates whether the momentum or thermal diffusivity dominates. This is particularly helpful for heat transfer analysis because it provides insight into the fluid's thermal conductivity in relation to its viscosity. In the exercise with the sphere, the Prandtl number is required to apply the appropriate Nusselt number correlation for estimating the convection heat transfer coefficient.
Heat Transfer in Fluids
The process of heat transfer in fluids can occur through conduction, convection, and radiation. Convection, the movement of heat due to fluid motion, is the dominant mechanism for heat loss or gain in many practical applications including heating or cooling systems and industrial processes.
For the sphere, the primary mode of heat transfer to the airstream is convection, which is influenced by several factors, including the properties of the fluid, the flow characteristics, and the surface condition. Understanding how heat transfer in fluids operates is essential for designing efficient thermal systems and for solving problems like the one presented, where heat transfer dynamics drastically change with surface modifications, such as the addition of a porous water-saturated covering.

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Most popular questions from this chapter

Dry air at \(32^{\circ} \mathrm{C}\) flows over a wetted (water) plate of \(0.2 \mathrm{~m}^{2}\) area. The average convection coefficient is \(\bar{h}=20 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}\), and the heater power required to maintain the plate at a temperature of \(27^{\circ} \mathrm{C}\) is \(432 \mathrm{~W}\). Estimate the power required to maintain the wetted plate at a temperature of \(37^{\circ} \mathrm{C}\) in dry air at \(32^{\circ} \mathrm{C}\) if the convection coefficients remain unchanged.

An industrial process involves the evaporation of water from a liquid film that forms on a contoured surface. Dry air is passed over the surface, and from laboratory measurements the convection heat transfer correlation is of the form $$ \overline{N_{L}}=0.43 \operatorname{Re}_{L}^{0.58} P r r^{\Omega .4} $$ (a) For an air temperature and velocity of \(27^{\circ} \mathrm{C}\) and \(10 \mathrm{~m} / \mathrm{s}\), respectively, what is the rate of evaporation from a surface of \(1-\mathrm{m}^{2}\) area and characteristic length \(L=1 \mathrm{~m}\) ? Approximate the density of saturated vapor as \(\rho_{A, \text { sat }}=0.0077 \mathrm{~kg} / \mathrm{m}^{3}\). (b) What is the steady-state temperature of the liquid film?

An object of irregular shape \(1 \mathrm{~m}\) long maintained at a constant temperature of \(100^{\circ} \mathrm{C}\) is suspended in an airstream having a free stream temperature of \(0^{\circ} \mathrm{C}\), a pressure of \(1 \mathrm{~atm}\), and a velocity of \(120 \mathrm{~m} / \mathrm{s}\). The air temperature measured at a point near the object in the airstream is \(80^{\circ} \mathrm{C}\). A second object having the same shape is \(2 \mathrm{~m}\) long and is suspended in an airstream in the same manner. The air free stream velocity is \(60 \mathrm{~m} / \mathrm{s}\). Both the air and the object are at \(50^{\circ} \mathrm{C}\), and the total pressure is \(1 \mathrm{~atm}\). A plastic coating on the surface of the object is being dried by this process. The molecular weight of the vapor is 82 , and the saturation pressure at \(50^{\circ} \mathrm{C}\) for the plastic material is \(0.0323 \mathrm{~atm}\). The mass diffusivity for the vapor in air at \(50^{\circ} \mathrm{C}\) is \(2.60 \times 10^{-5} \mathrm{~m}^{2} / \mathrm{s}\). (a) For the second object, at a location corresponding to the point of measurement on the first object, determine the vapor concentration and partial pressure. (b) If the average heat flux \(q^{\prime \prime}\) is \(2000 \mathrm{~W} / \mathrm{m}^{2}\) for the first object, determine the average mass flux \(n_{\mathrm{A}}^{\prime \prime}\left(\mathrm{kg} / \mathrm{s}^{\cdot} \mathrm{m}^{2}\right)\) for the second object.

For flow over a flat plate of length \(L\), the local heat transfer coefficient \(h_{x}\) is known to vary as \(x^{-1 / 2}\), where \(x\) is the distance from the leading edge of the plate. What is the ratio of the average Nusselt number for the entire plate \(\left(\overline{N u}_{L}\right)\) to the local Nusselt number at \(x=L\left(N u_{L}\right)\) ?

For laminar flow over a flat plate, the local heat transfer coefficient \(h_{x}\) is known to vary as \(x^{-1 / 2}\), where \(x\) is the distance from the leading edge \((x=0)\) of the plate. What is the ratio of the average coefficient between the leading edge and some location \(x\) on the plate to the local coefficient at \(x\) ?

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