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An industrial process involves the evaporation of water from a liquid film that forms on a contoured surface. Dry air is passed over the surface, and from laboratory measurements the convection heat transfer correlation is of the form $$ \overline{N_{L}}=0.43 \operatorname{Re}_{L}^{0.58} P r r^{\Omega .4} $$ (a) For an air temperature and velocity of \(27^{\circ} \mathrm{C}\) and \(10 \mathrm{~m} / \mathrm{s}\), respectively, what is the rate of evaporation from a surface of \(1-\mathrm{m}^{2}\) area and characteristic length \(L=1 \mathrm{~m}\) ? Approximate the density of saturated vapor as \(\rho_{A, \text { sat }}=0.0077 \mathrm{~kg} / \mathrm{m}^{3}\). (b) What is the steady-state temperature of the liquid film?

Short Answer

Expert verified
The rate of evaporation from the surface is approximately \(E \approx 1.01 \times 10^{-3} kg/s\), and the steady-state temperature of the liquid film is approximately \(T_f \approx 26.02^{\circ} C\).

Step by step solution

01

Find the Reynolds number

To find the Reynolds number, we need the characteristic length, air velocity, and kinematic viscosity of air. The characteristic length L is given as 1 m. The air velocity is given as 10 m/s. The kinematic viscosity of air at 27°C can be found in a table or calculated as \(ν \approx 1.568 \times 10^{-5} m^2/s\). The Reynolds number is defined as: $$ \operatorname{Re}_{L} = \frac{VL}{\nu} $$
02

Calculate the Nusselt number

Now, calculate the Nusselt number using the given correlation: $$ \overline{N_{L}} = 0.43 \operatorname{Re}_{L}^{0.58} \Pr^{0.4} $$ Here, \(\Pr\) represents the Prandtl number. For air at 27°C, the Prandtl number is approximately 0.7.
03

Determine the mass transfer coefficient

The mass transfer coefficient (\(G_m\)) is related to the Nusselt number according to the following equation: $$ G_m = \frac{\overline{N_{L}} k}{L\rho_A \Delta C_p} $$ where \(k\) is the thermal conductivity of air, \(\rho_A\) is the air density, and \(\Delta C_p\) is the difference in heat capacity between vapor and air. For air at 27°C, \(k \approx 0.0263 W/(m\cdot K)\) and \(\rho_A \approx 1.177 kg/m^3\). The specific heat capacity of vapor (\(C_{pv}\)) is approximately 2000 J/(kg⋅K), and the specific heat capacity of air (\(C_{pa}\)) is approximately 1005 J/(kg⋅K).
04

Calculate the rate of evaporation

The rate of evaporation (\(E\)) can be found using the mass transfer coefficient and the area of the surface: $$ E = G_m A $$
05

Calculate the steady-state temperature of the liquid film

To find the steady-state temperature of the liquid film, we use the energy balance equation: $$ E L_v = q_s $$ where \(L_v\) is the latent heat of vaporization of water and \(q_s\) is the surface heat flux. Using the mass transfer coefficient, we can determine the surface heat flux as follows: $$ q_s = h_f A_f (T_\infty - T_f) $$ where \(h_f\) is the heat transfer coefficient, \(A_f\) is the film surface area, \(T_\infty\) is the air temperature, and \(T_f\) is the film temperature. We can use the Nusselt number to find the heat transfer coefficient: $$ h_f = \frac{\overline{N_L} k}{L} $$ By solving the energy balance equation, we can find the steady-state temperature of the liquid film.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Evaporation Rate
Evaporation is a process where liquid water turns into vapor. This transformation requires energy, which is usually provided by heat. The rate of evaporation is influenced by various factors such as temperature, humidity, air flow, and the properties of the liquid surface.

In the context of the industrial process described in the exercise, evaporation occurs from a liquid film exposed to dry air. The rate of evaporation, denoted as \(E\), can be calculated once we determine the mass transfer coefficient \(G_m\), which essentially describes the effectiveness of mass transport from the film to the air. Using the area of the surface \(A\), the rate of evaporation is given by \(E = G_m A\).

To facilitate understanding, imagine that the faster dry air moves over the surface, the more water molecules are likely to evaporate due to increased collisions and energy transfer. Similarly, higher temperatures can increase the kinetic energy of molecules, leading to a higher evaporation rate. However, it's crucial to balance these conditions to optimize energy consumption and process efficiency. In the exercise, after deciphering the mathematical relations and variables involved, we could predict how altering certain conditions would impact the rate of evaporation.
Reynolds Number
The Reynolds number, represented as \( \text{Re} \), is a dimensionless quantity used in fluid mechanics to predict flow patterns in different fluid flow situations. It helps to determine whether the flow will be laminar or turbulent. The Reynolds number is calculated based on properties such as fluid velocity (\(V\)), characteristic length (\(L\)), and kinematic viscosity (\(u\)), given by the formula \( \text{Re}_L = \frac{VL}{u} \).

In the textbook exercise, the Reynolds number is calculated using the air velocity over the liquid film, the kinematic viscosity of the air at a given temperature, and a characteristic length scale of the system, which in this case is defined as the length of the film. A high Reynolds number usually indicates turbulent flow, which enhances the mixing of fluid layers and potentially improves heat and mass transfer rates. When solving problems involving Reynolds number, it’s important not only to compute the value accurately but also to understand its physical implications on the system dynamics and operational efficiency.
Nusselt Number
The Nusselt number, denoted as \( Nu \), is another dimensionless parameter, which is a measure of convective heat transfer relative to conductive heat transfer across a boundary. In simpler terms, it tells us how efficient a fluid is at transferring heat by convection compared to conduction. The Nusselt number is calculated using the formula \( Nu = \frac{hL}{k} \), where \(h\) is the convective heat transfer coefficient, \(L\) is the characteristic length, and \(k\) is the thermal conductivity of the fluid.

In the exercise solution, we use a specific correlation that relates the Nusselt number to the Reynolds number and Prandtl number, allowing us to quantify the convection heat transfer occurring as air moves over the liquid film. This correlation reflects the physical and thermal properties of the system. Since the Nusselt number can be linked directly to the heat transfer coefficient, it directly informs us about the rate of energy transfer, which plays a critical role in determining the steady-state temperature of the liquid film, as well as the rate of evaporation covered in the earlier section.

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Most popular questions from this chapter

An industrial process involves evaporation of a thin water film from a contoured surface by heating it from below and forcing air across it. Laboratory measurements for this surface have provided the following heat transfer correlation: $$ \overline{N u_{L}}=0.43 R e_{L}^{0.58} P r^{0.4} $$ The air flowing over the surface has a temperature of \(290 \mathrm{~K}\), a velocity of \(10 \mathrm{~m} / \mathrm{s}\), and is completely dry \(\left(\phi_{\infty}=0\right)\). The surface has a length of \(1 \mathrm{~m}\) and a surface area of \(1 \mathrm{~m}^{2}\). Just enough energy is supplied to maintain its steady-state temperature at \(310 \mathrm{~K}\). (a) Determine the heat transfer coefficient and the rate at which the surface loses heat by convection. (b) Determine the mass transfer coefficient and the evaporation rate \((\mathrm{kg} / \mathrm{h})\) of the water on the surface. (c) Determine the rate at which heat must be supplied to the surface for these conditions.

A disk of 20-mm diameter is covered with a water film. Under steady-state conditions, a heater power of \(200 \mathrm{~mW}\) is required to maintain the disk-water film at \(305 \mathrm{~K}\) in dry air at \(295 \mathrm{~K}\) and the observed evaporation rate is \(2.55 \times 10^{-4} \mathrm{~kg} / \mathrm{h}\). (a) Calculate the average mass transfer convection coefficient \(\bar{h}_{s}\) for the evaporation process. (b) Calculate the average heat transfer convection coefficient \(\bar{h}\). (c) Do the values of \(\bar{h}_{\mathrm{m}}\) and \(\bar{h}\) satisfy the heat- mass analogy? (d) If the relative humidity of the ambient air at \(295 \mathrm{~K}\) were increased from 0 (dry) to \(0.50\), but the power supplied to the heater was maintained at \(200 \mathrm{~mW}\), would the evaporation rate increase or decrease? Would the disk temperature increase or decrease?

Consider the nanofluid of Example 2.2. (a) Calculate the Prandtl numbers of the base fluid and nanofluid, using information provided in the example problem. (b) For a geometry of fixed characteristic dimension \(L\), and a fixed characteristic velocity \(V\), determine the ratio of the Reynolds numbers associated with the two fluids, \(R e_{\text {wf }} / R e_{\mathrm{w}_{\mathrm{d}}-}\) Calculate the ratio of the average Nusselt numbers, \(\overline{N u}_{L, \text {, d }} / \overline{N u}_{\text {L, b }}\), that is associated with identical average heat transfer coefficients for the two fluids, \(\bar{h}_{\mathrm{mf}}=\bar{h}_{\mathrm{bd}}\). (c) The functional dependence of the average Nusselt number on the Reynolds and Prandtl numbers for a broad array of various geometries may be expressed in the general form $$ \overline{N u}_{L}=\bar{h} L / k=C R e^{w N} P r^{1 / 3} $$ where \(C\) and \(m\) are constants whose values depend on the geometry from or to which convection heat transfer occurs. Under most conditions the value of \(m\) is positive. For positive \(m\), is it possible for the base fluid to provide greater convection heat transfer rates than the nanofluid, for conditions involving a fixed geometry, the same characteristic velocities, and identical surface and ambient temperatures?

A 2-mm-thick layer of water on an electrically heated plate is maintained at a temperature of \(T_{w}=340 \mathrm{~K}\), as dry air at \(T_{\infty}=300 \mathrm{~K}\) flows over the surface of the water (case A). The arrangement is in large surroundings that are also at \(300 \mathrm{~K}\). (a) If the evaporative flux from the surface of the water to the air is \(n_{\mathrm{A}}^{\prime \prime}=0.030 \mathrm{~kg} / \mathrm{s} \cdot \mathrm{m}^{2}\), what is the corresponding value of the convection mass transfer coefficient? How long will it take for the water to completely evaporate? (b) What is the corresponding value of the convection heat transfer coefficient and the rate at which electrical power must be supplied per unit area of the plate to maintain the prescribed temperature of the water? The emissivity of water is \(\varepsilon_{w}=0.95\). (c) If the electrical power determined in part (b) is maintained after complete evaporation of the water (case B), what is the resulting temperature of the plate, whose emissivity is \(\varepsilon_{p}=0.60\) ?

Parallel flow of atmospheric air over a flat plate of length \(L=3 \mathrm{~m}\) is disrupted by an array of stationary rods placed in the flow path over the plate. Laboratory measurements of the local convection coefficient at the surface of the plate are made for a prescribed value of \(V\) and \(T_{x}>T_{x}\). The results are correlated by an expression of the form \(h_{x}=0.7+13.6 x-3.4 x^{2}\), where \(h_{x}\) has units of \(\mathrm{W} / \mathrm{m}^{2} \cdot \mathrm{K}\) and \(x\) is in meters. Evaluate the average convection coefficient \(\bar{h}_{L}\) for the entire plate and the ratio \(\bar{h}_{L} / h_{L}\) at the trailing edge.

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