/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 49 A shell-and-tube heat exchanger ... [FREE SOLUTION] | 91Ó°ÊÓ

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A shell-and-tube heat exchanger is to heat \(10,000 \mathrm{~kg} / \mathrm{h}\) of water from 16 to \(84^{\circ} \mathrm{C}\) by hot engine oil flowing through the shell. The oil makes a single shell pass, entering at \(160^{\circ} \mathrm{C}\) and leaving at \(94^{\circ} \mathrm{C}\), with an average heat transfer coefficient of \(400 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}\). The water flows through 11 brass tubes of \(22.9-\mathrm{mm}\) inside diameter and 25.4-mm outside diameter, with each tube making four passes through the shell. (a) Assuming fully developed flow for the water, determine the required tube length per pass. (b) For the tube length found in part (a), plot the effectiveness, fluid outlet temperatures, and water-side convection coefficient as a function of the water flow rate for \(5000 \leq m_{c} \leq 15,000 \mathrm{~kg} / \mathrm{h}\), with all other conditions remaining the same.

Short Answer

Expert verified
To determine the required tube length per pass for the shell-and-tube heat exchanger and analyze its effectiveness and other properties, follow these steps: 1. Calculate the heat transfer rate, \(Q\), using the formula: \(Q = m_c c_{p,c} (T_{c,out} - T_{c,in})\) 2. Find the heat transfer area, \(A\), from the given data using: \(Q = U \cdot A \cdot \Delta T_{lm}\). 3. Calculate the length per pass, \(L\), using the formula: \(L = \frac{A}{N \cdot \pi \cdot D_o}\). 4. Plot the effectiveness, fluid outlet temperatures, and water-side convection coefficient as a function of the water flow rate for \(5000 \leq m_{c} \leq 15,000 \mathrm{~kg} / \mathrm{h}\), using a software package or programming language like MATLAB or Python. After completing these steps, you will have determined the required tube length per pass and analyzed the effectiveness and other properties of the heat exchanger.

Step by step solution

01

Firstly, we need to find the heat transfer rate, \(Q\), from the given information. We can use the formula: \(Q = m_c c_{p,c} (T_{c,out} - T_{c,in})\) where \(m_c\) = mass flow rate of the cold fluid (water), \(10000 \frac{kg}{h}\) \(c_{p,c}\) = specific heat capacity of the cold fluid (water), \(4186 \frac{J}{kg \cdot K}\) \(T_{c,out}\) = outlet temperature of the cold fluid (water), \(84^{\circ}C\) \(T_{c,in}\) = inlet temperature of the cold fluid (water), \(16^{\circ}C\) By plugging in the values, we can calculate \(Q\). #Step 2: Calculate the heat transfer area, A#

Next, we need to find the heat transfer area, A, from the given data. The total area can be calculated using the formula: \(A = N \cdot \pi \cdot D_o \cdot L\) where \(N\) = 11 (Since there are 11 tubes) \(D_o\) = outside diameter of the tubes, \(25.4 \mathrm{~mm}\) \(L\) = Length per pass (which we want to calculate) Since we know the average heat transfer coefficient, \(U\), we can find the required area, A, for the given heat transfer rate, \(Q\) by: \(Q = U \cdot A \cdot \Delta T_{lm}\) where \(\Delta T_{lm}\) = log-mean temperature difference, which can be calculated as: \(\Delta T_{lm} = \frac{T_{h,in} - T_{c,out} - (T_{h,out} - T_{c,in})}{\ln{\frac{T_{h,in} - T_{c,out}}{T_{h,out} - T_{c,in}}}}\) By plugging in the known values and solving for A, we can get the required heat transfer area. #Step 3: Calculate the length per pass, L#
02

Now that we have found the heat transfer area, A, we can solve for the length per pass, L, using the formula from Step 2: \(L = \frac{A}{N \cdot \pi \cdot D_o}\) Plug in the values and calculate the length per pass, L. #Step 4: Plot the effectiveness, fluid outlet temperatures, and water-side convection coefficient#

For the tube length found in part (a), plot the effectiveness, fluid outlet temperatures, and water-side convection coefficient as a function of the water flow rate for \(5000 \leq m_{c} \leq 15,000 \mathrm{~kg} / \mathrm{h}\), with all other conditions remaining the same. To do this, we would typically use a software package or programming language like MATLAB or Python, with a numerical solver library to analyze and plot the results. By following these steps, you should be able to determine the required tube length per pass for the shell-and-tube heat exchanger and analyze its effectiveness and other properties.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Shell-and-Tube Heat Exchanger
A shell-and-tube heat exchanger is a type of heat exchanger design that is widely used in industries to transfer heat between two fluids. It consists of a series of tubes, known as the tube bundle, which is enclosed within a larger cylindrical shell. One fluid flows through the tubes, while the other fluid flows around them within the shell. This setup allows for efficient heat transfer between the fluids.

The advantage of using a shell-and-tube design includes its versatility and robustness. This type of exchanger can handle high-pressure fluids and operate under extreme temperature conditions. The design is highly adaptable with possibilities for multiple tube passes, which means the tubes can be configured in various ways to enhance the heat transfer process.

  • It is particularly effective for large-scale operations.
  • Maintenance and cleaning are more accessible with this design.
  • It offers a flexible choice of materials to suit various fluid properties.
This makes the shell-and-tube heat exchanger a preferred choice for heating and cooling applications in chemical processing, power plants, and HVAC systems.
Log-Mean Temperature Difference
The log-mean temperature difference (LMTD) is a crucial factor in determining the efficiency of a heat exchanger. It provides a measure of the mean temperature driving force for heat transfer between the hot and cold fluids. Calculating LMTD helps in designing and assessing heat exchangers' performance based on the temperature differences from inlet to outlet points of the fluids.

LMTD is mathematically expressed as \[ \Delta T_{lm} = \frac{(T_{h,in} - T_{c,out}) - (T_{h,out} - T_{c,in})}{\ln{\frac{T_{h,in} - T_{c,out}}{T_{h,out} - T_{c,in}}}} \]where:

  • \(T_{h,in}\) is the inlet temperature of the hot fluid.
  • \(T_{c,out}\) is the outlet temperature of the cold fluid.
  • \(T_{h,out}\) is the outlet temperature of the hot fluid.
  • \(T_{c,in}\) is the inlet temperature of the cold fluid.
By considering the logarithmic mean of the temperature differences, LMTD offers a more accurate representation compared to simple arithmetic means, especially when temperature difference varies along the length of the heat exchanger. This is critical for optimizing design and ensuring enough heat is transferred to meet process requirements.
Specific Heat Capacity
Specific heat capacity, denoted as \(c_p\), is a property of a material that represents the amount of heat required to raise the temperature of a unit mass of the substance by one degree Celsius (or Kelvin). It plays a significant role in calculating the total heat transfer in processes like heating or cooling.

For example, in the context of a heat exchanger, understanding the specific heat capacities of the fluids involved is essential in determining how much energy transfer will occur between the fluids.

The formula to calculate the heat transfer rate \(Q\) involves specific heat capacity:\[ Q = m \cdot c_p \cdot \Delta T \]where:

  • \(m\) is the mass flow rate of the fluid.
  • \(c_p\) is the specific heat capacity of the fluid.
  • \(\Delta T\) is the change in temperature of the fluid.
Specific heat capacity values are crucial in designing and operating heat exchangers, as they influence the exchange's effectiveness and efficiency. Different materials have different \(c_p\) values, thus affecting how they respond to heating or cooling.
Convection Coefficient
The convection coefficient, often denoted as \(h\), is a measure of the heat transfer rate between a fluid and a solid surface per unit surface area per degree of temperature difference. It is an essential parameter in the heat transfer process, particularly in convection, where energy is transmitted through fluid motion.

In a shell-and-tube heat exchanger, the convection coefficient affects how heat is transferred between the tube walls and the fluid inside them. A higher convection coefficient indicates improved heat transfer efficiency. Several factors affect the value of \(h\):

  • The properties of the fluid, such as viscosity and thermal conductivity.
  • The flow regime, whether it's laminar or turbulent.
  • The surface material and roughness.
The average convection coefficient provides a comprehensive view that considers these factors, helping in evaluating the performance of heat exchanger designs. It is critical for ensuring that the shell-and-tube heat exchanger meets the specific thermal requirements of any application.

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Most popular questions from this chapter

For health reasons, public spaces require the continuous exchange of a specified mass of stale indoor air with fresh outdoor air. To conserve energy during the heating season, it is expedient to recover the thermal energy in the exhausted, warm indoor air and transfer it to the incoming, cold fresh air. A coupled singlepass, cross-flow heat exchanger with both fluids unmixed is installed in the intake and return ducts of a heating system as shown in the schematic. Water containing an anti-freeze agent is used as the working fluid in the coupled heat exchange device, which is composed of individual heat exchangers \(A\) and B. Hence, heat is transferred from the warm stale air to the cold fresh air by way of the pumped water. Consider a specified air mass flow rate (in each duct) of \(m=1.50 \mathrm{~kg} / \mathrm{s}\), an overall heat transfer coefficient-area product of \(U A=2500 \mathrm{~W} / \mathrm{K}\) (for each heat exchanger), an outdoor temperature of \(T_{c, i, A}=-4^{\circ} \mathrm{C}\) and an indoor temperature of \(T_{h, i, B}=\) \(23^{\circ} \mathrm{C}\). Since the warm air has been humidified, excessive heat transfer can result in unwanted condensation in the ductwork. What water flow rate is necessary to maximize heat transfer while ensuring the outlet temperature associated with heat exchanger \(\mathrm{B}\) does not fall below the dew point temperature, \(T_{h, 0, B}=T_{\mathrm{dp}}=\) \(13^{\circ} \mathrm{C}\) ? Hint: Assume the maximum heat capacity rate is associated with the air.

An ocean thermal energy conversion system is being proposed for electric power generation. Such a system is based on the standard power cycle for which the working fluid is evaporated, passed through a turbine, and subsequently condensed. The system is to be used in very special locations for which the oceanic water temperature near the surface is approximately \(300 \mathrm{~K}\), while the temperature at reasonable depths is approximately \(280 \mathrm{~K}\). The warmer water is used as a heat source to evaporate the working fluid, while the colder water is used as a heat sink for condensation of the fluid. Consider a power plant that is to generate \(2 \mathrm{MW}\) of electricity at an efficiency (electric power output per heat input) of \(3 \%\). The evaporator is a heat exchanger consisting of a single shell with many tubes executing two passes. If the working fluid is evaporated at its phase change temperature of \(290 \mathrm{~K}\), with ocean water entering at \(300 \mathrm{~K}\) and leaving at \(292 \mathrm{~K}\), what is the heat exchanger area required for the evaporator? What flow rate must be maintained for the water passing through the evaporator? The overall heat transfer coefficient may be approximated as \(1200 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}\).

The human brain is especially sensitive to elevated temperatures. The cool blood in the veins leaving the face and neck and returning to the heart may contribute to thermal regulation of the brain by cooling the arterial blood flowing to the brain. Consider a vein and artery running between the chest and the base of the skull for a distance \(L=250 \mathrm{~mm}\), with mass flow rates of \(3 \times 10^{-3} \mathrm{~kg} / \mathrm{s}\) in opposite directions in the two vessels. The vessels are of diameter \(D=5 \mathrm{~mm}\) and are separated by a distance \(w=7 \mathrm{~mm}\). The thermal conductivity of the surrounding tissue is \(k_{\mathrm{r}}=0.5 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K}\). If the arterial blood enters at \(37^{\circ} \mathrm{C}\) and the venous blood enters at \(27^{\circ} \mathrm{C}\), at what temperature will the arterial blood exit? If the arterial blood becomes overheated, and the body responds by halving the blood flow rate, how much hotter can the entering arterial blood be and still maintain its exit temperature below \(37^{\circ} \mathrm{C}\) ? Hint: If we assume that all the heat leaving the artery enters the vein, then heat transfer between the two vessels can be modeled using a relationship found in Table 4.1. Approximate the blood properties as those of water.

A single-pass, cross-flow heat exchanger uses hot exhaust gases (mixed) to heat water (unmixed) from 30 to \(80^{\circ} \mathrm{C}\) at a rate of \(3 \mathrm{~kg} / \mathrm{s}\). The exhaust gases, having thermophysical properties similar to air, enter and exit the exchanger at 225 and \(100^{\circ} \mathrm{C}\), respectively. If the overall heat transfer coefficient is \(200 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}\), estimate the required surface area.

A two-fluid heat exchanger has inlet and outlet temperatures of 65 and \(40^{\circ} \mathrm{C}\) for the hot fluid and 15 and \(30^{\circ} \mathrm{C}\) for the cold fluid. Can you tell whether this exchanger is operating under counterflow or parallelflow conditions? Determine the effectiveness of the heat exchanger.

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