/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 32 A single-pass, cross-flow heat e... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

A single-pass, cross-flow heat exchanger uses hot exhaust gases (mixed) to heat water (unmixed) from 30 to \(80^{\circ} \mathrm{C}\) at a rate of \(3 \mathrm{~kg} / \mathrm{s}\). The exhaust gases, having thermophysical properties similar to air, enter and exit the exchanger at 225 and \(100^{\circ} \mathrm{C}\), respectively. If the overall heat transfer coefficient is \(200 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}\), estimate the required surface area.

Short Answer

Expert verified
The required surface area for the given single-pass, cross-flow heat exchanger can be calculated by following these steps: 1) Calculate heat capacity rates for hot exhaust gases and water, 2) Calculate heat capacity rate ratio and effectiveness, 3) Determine the NTU value, and 4) Calculate the required surface area using overall heat transfer coefficient, NTU, and heat capacity rate ratio.

Step by step solution

01

Calculate Heat Capacity Rates (C_h and C_c)

We need to determine the heat capacity rates (\( C_h \) and \( C_c \)) for the hot exhaust gases (air) and the water. Assuming that exhaust gases has thermophysical properties similar to air: Heat capacity rate for air (\( C_h \)) = mass flow rate × specific heat capacity Specific heat capacity for air, \( C_{p,air} \) ≈ 1000 J/kg·K Heat capacity rate for water (\( C_c \)) = mass flow rate × specific heat capacity Specific heat capacity for water, \( C_{p,water} \) ≈ 4200 J/kg·K So, we can calculate: \( C_h = m_{air}\dot C_{p,air} \) \( C_c = 3 kg/s * 4200 J/kg·K \)
02

Calculate Heat Capacity Rate Ratio and Effectiveness

Using the values calculated in step 1, we can determine the heat capacity rate ratio (C*) and the effectiveness (ε) of the heat exchanger. The formulas are: \( C^* = \frac{C_{min}}{C_{max}} \quad \) and \( \epsilon = \frac{q}{q_{max}} = \frac{m_cC_{p,c}(T_{c2} - T_{c1})}{m_cC_{p,c}(T_{h1} - T_{c1})} \) where: - \( q \) is the actual heat transfer - \( q_{max} \) is the maximum possible heat transfer - \( T_{h1} \) is the inlet temperature of the hot fluid (225°C) - \( T_{c1} \) is the inlet temperature of the cold fluid (30°C) - \( T_{c2} \) is the outlet temperature of the cold fluid (80°C) - \( m_c \) is the mass flow rate of the cold fluid (3 kg/s) - \( C_{p,c} \) is the specific heat capacity of the cold fluid (4200 J/kg·K)
03

Determine the NTU value

To determine the NTU (number of transfer units) value, we will use the effectiveness (ε) found in step 2 and the C* value calculated in step 1, and the formula for single-pass, cross-flow heat exchanger with unmixed cold fluid: \( NTU = -\frac{1}{1 - C^*}\ln{(1 - \epsilon(1-C^*))} \)
04

Calculate the Required Surface Area

Finally, we will use the overall heat transfer coefficient (U) and NTU value found in step 3 to calculate the required surface area (A): \( A = \frac{NTU*C_{min}}{U} \) Using the given overall heat transfer coefficient of 200 W/m²·K and the values calculated in previous steps, we can find the required surface area (A). By following these steps, you will be able to estimate the required surface area for this single-pass, cross-flow heat exchanger.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Cross-flow heat exchanger
A cross-flow heat exchanger is a widely used device for transferring heat between two fluids. In this type, the two fluids move perpendicular to each other. This design promotes effective heat transfer across the medium and is common in various engineering applications. The cross-flow arrangement allows for one fluid to be mixed while the other remains unmixed.
In our example, hot exhaust gases (mixed) heat water (unmixed). This design is beneficial as it offers a compact structure and improves heat transfer efficiency. The perpendicular movement helps achieve a greater temperature difference, which boosts the heat transfer rate. Cross-flow heat exchangers are ideal for situations where space is limited, and efficiency is essential.
Heat transfer coefficient
The heat transfer coefficient is a crucial parameter in determining a heat exchanger's efficiency. It measures the ability of the heat exchanger to transfer heat between the fluids. This coefficient depends on factors such as fluid flow properties, fluid types, and the surface area for heat exchange.
In our scenario, the overall heat transfer coefficient is given as 200 W/m²·K. This value is used in the calculation of the required surface area for the heat exchanger. A higher coefficient indicates a more efficient heat transfer process, minimizing energy losses, and optimizing the exchanger's performance. Understanding this value helps in designing an efficient heat exchanger setup, ensuring all energy transfer requirements are met effectively.
Effectiveness
Effectiveness ( ε ) is a measurement of how well a heat exchanger performs its function compared to the maximum possible heat transfer. The effectiveness of a heat exchanger gauges the ability to utilize the temperature difference driving the heat exchange process. For our case, it relates the actual heat transfer ( q ) to the maximum possible heat transfer ( q_{max} ).
The formula \( \epsilon = \frac{q}{q_{max}} \) gives insight into the energy efficiency of the process. A higher effectiveness value indicates a more efficient heat exchanger, closely approaching the maximum heat transfer potential. Calculating effectiveness is essential in assessing and improving the design and operation of heat exchangers, ensuring they meet practical and theoretical heating or cooling demands.
Number of transfer units (NTU)
The number of transfer units (NTU) is essential for understanding the heat exchanger's performance. It is a dimensionless measure that quantifies the heat exchanger size relative to the required heat transfer.
In cross-flow heat exchangers, the NTU value is important for evaluating the exchanger's ability to achieve the desired thermal performance. The equation \( NTU = -\frac{1}{1 - C^*}\ln{(1 - \epsilon(1-C^*))} \) connects NTU with the exchanger's effectiveness and capacity rate ratio. This relation helps engineers assess whether a given heat exchanger can achieve the intended temperature change.
NTU provides a way to compare different heat exchangers and optimize designs for improved efficiency. It is a crucial metric when considering adjustments or upgrades in heat exchanger systems.
Surface area calculation
The surface area is a critical factor in a heat exchanger's design, influencing its ability to transfer heat efficiently. Larger surface areas promote greater heat exchange between fluids. The necessary surface area calculation accounts for various parameters such as heat transfer coefficient and NTU.
The formula \( A = \frac{NTU*C_{min}}{U} \) allows determining the required surface area. Here, U represents the overall heat transfer coefficient, and C_{min} stands for the minimum heat capacity rate.
Accurate surface area estimation ensures that the heat exchanger operates efficiently without excessive costs or material usage. Proper calculation prevents oversizing, which could lead to unnecessary material expenditure, or undersizing, which would result in inadequate heat transfer, affecting the system's overall efficiency.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A process fluid having a specific heat of \(3500 \mathrm{~J} / \mathrm{kg} \cdot \mathrm{K}\) and flowing at \(2 \mathrm{~kg} / \mathrm{s}\) is to be cooled from \(80^{\circ} \mathrm{C}\) to \(50^{\circ} \mathrm{C}\) with chilled water, which is supplied at a temperature of \(15^{\circ} \mathrm{C}\) and a flow rate of \(2.5 \mathrm{~kg} / \mathrm{s}\). Assuming an overall heat transfer coefficient of \(2000 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}\), calculate the required heat transfer areas for the following exchanger configurations: (a) parallel flow, (b) counterflow, (c) shell-and-tube, one shell pass and two tube passes, and (d) cross-flow, single pass, both fluids unmixed. Compare the results of your analysis. Your work can be reduced by using IHT.

A novel design for a condenser consists of a tube of thermal conductivity \(200 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K}\) with longitudinal fins snugly fitted into a larger tube. Condensing refrigerant at \(45^{\circ} \mathrm{C}\) flows axially through the inner tube, while water at a flow rate of \(0.012 \mathrm{~kg} / \mathrm{s}\) passes through the six channels around the inner tube. The pertinent diameters are \(D_{1}=10 \mathrm{~mm}, D_{2}=14 \mathrm{~mm}\), and \(D_{3}=50 \mathrm{~mm}\), while the fin thickness is \(t=2 \mathrm{~mm}\). Assume that the convection coefficient associated with the condensing refrigerant is extremely large. Determine the heat removal rate per unit tube length in a section of the tube for which the water is at \(15^{\circ} \mathrm{C}\).

A counterflow, concentric tube heat exchanger is designed to heat water from 20 to \(80^{\circ} \mathrm{C}\) using hot oil, which is supplied to the annulus at \(160^{\circ} \mathrm{C}\) and discharged at \(140^{\circ} \mathrm{C}\). The thin-walled inner tube has a diameter of \(D_{i}=20 \mathrm{~mm}\), and the overall heat transfer coefficient is \(500 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}\). The design condition calls for a total heat transfer rate of \(3000 \mathrm{~W}\). (a) What is the length of the heat exchanger? (b) After 3 years of operation, performance is degraded by fouling on the water side of the exchanger, and the water outlet temperature is only \(65^{\circ} \mathrm{C}\) for the same fluid flow rates and inlet temperatures. What are the corresponding values of the heat transfer rate, the outlet temperature of the oil, the overall heat transfer coefficient, and the water- side fouling factor, \(R_{f,}^{n}\) ?

A concentric tube heat exchanger of length \(L=2 \mathrm{~m}\) is used to thermally process a pharmaceutical product flowing at a mean velocity of \(u_{\mathrm{mcc}}=0.1 \mathrm{~m} / \mathrm{s}\) with an inlet temperature of \(T_{c, i}=20^{\circ} \mathrm{C}\). The inner tube of diameter \(D_{i}=10 \mathrm{~mm}\) is thin walled, and the exterior of the outer tube \(\left(D_{o}=20 \mathrm{~mm}\right)\) is well insulated. Water flows in the annular region between the tubes at a mean velocity of \(u_{\mathrm{mhh}}=0.2 \mathrm{~m} / \mathrm{s}\) with an inlet temperature of \(T_{h, i}=60^{\circ} \mathrm{C}\). Properties of the pharmaceutical product are \(\nu=10 \times 10^{-6} \mathrm{~m}^{2} / \mathrm{s}, \quad k=0.25 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K}\), \(\rho=1100 \mathrm{~kg} / \mathrm{m}^{3}\), and \(c_{p}=2460 \mathrm{~J} / \mathrm{kg} \cdot \mathrm{K}\). Evaluate water properties at \(\bar{T}_{\mathrm{h}}=50^{\circ} \mathrm{C}\). (a) Determine the value of the overall heat transfer coefficient \(U\). (b) Determine the mean outlet temperature of the pharmaceutical product when the exchanger operates in the counterflow mode. (c) Determine the mean outlet temperature of the pharmaceutical product when the exchanger operates in the parallel-flow mode.

In a fire-tube boiler, hot products of combustion flowing through an array of thin-walled tubes are used to boil water flowing over the tubes. At the time of installation, the overall heat transfer coefficient was \(400 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}\). After 1 year of use, the inner and outer tube surfaces are fouled, with corresponding fouling factors of \(R_{f, i}^{N}=0.0015\) and \(R_{f, w}^{*}=0.0005 \mathrm{~m}^{2} \cdot \mathrm{K} / \mathrm{W}\), respectively. Should the boiler be scheduled for cleaning of the tube surfaces?

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.