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A single-pass, cross-flow heat exchanger uses hot exhaust gases (mixed) to heat water (unmixed) from 30 to \(80^{\circ} \mathrm{C}\) at a rate of \(3 \mathrm{~kg} / \mathrm{s}\). The exhaust gases, having thermophysical properties similar to air, enter and exit the exchanger at 225 and \(100^{\circ} \mathrm{C}\), respectively. If the overall heat transfer coefficient is \(200 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}\), estimate the required surface area.

Short Answer

Expert verified
The required surface area for the given single-pass, cross-flow heat exchanger can be calculated by following these steps: 1) Calculate heat capacity rates for hot exhaust gases and water, 2) Calculate heat capacity rate ratio and effectiveness, 3) Determine the NTU value, and 4) Calculate the required surface area using overall heat transfer coefficient, NTU, and heat capacity rate ratio.

Step by step solution

01

Calculate Heat Capacity Rates (C_h and C_c)

We need to determine the heat capacity rates (\( C_h \) and \( C_c \)) for the hot exhaust gases (air) and the water. Assuming that exhaust gases has thermophysical properties similar to air: Heat capacity rate for air (\( C_h \)) = mass flow rate × specific heat capacity Specific heat capacity for air, \( C_{p,air} \) ≈ 1000 J/kg·K Heat capacity rate for water (\( C_c \)) = mass flow rate × specific heat capacity Specific heat capacity for water, \( C_{p,water} \) ≈ 4200 J/kg·K So, we can calculate: \( C_h = m_{air}\dot C_{p,air} \) \( C_c = 3 kg/s * 4200 J/kg·K \)
02

Calculate Heat Capacity Rate Ratio and Effectiveness

Using the values calculated in step 1, we can determine the heat capacity rate ratio (C*) and the effectiveness (ε) of the heat exchanger. The formulas are: \( C^* = \frac{C_{min}}{C_{max}} \quad \) and \( \epsilon = \frac{q}{q_{max}} = \frac{m_cC_{p,c}(T_{c2} - T_{c1})}{m_cC_{p,c}(T_{h1} - T_{c1})} \) where: - \( q \) is the actual heat transfer - \( q_{max} \) is the maximum possible heat transfer - \( T_{h1} \) is the inlet temperature of the hot fluid (225°C) - \( T_{c1} \) is the inlet temperature of the cold fluid (30°C) - \( T_{c2} \) is the outlet temperature of the cold fluid (80°C) - \( m_c \) is the mass flow rate of the cold fluid (3 kg/s) - \( C_{p,c} \) is the specific heat capacity of the cold fluid (4200 J/kg·K)
03

Determine the NTU value

To determine the NTU (number of transfer units) value, we will use the effectiveness (ε) found in step 2 and the C* value calculated in step 1, and the formula for single-pass, cross-flow heat exchanger with unmixed cold fluid: \( NTU = -\frac{1}{1 - C^*}\ln{(1 - \epsilon(1-C^*))} \)
04

Calculate the Required Surface Area

Finally, we will use the overall heat transfer coefficient (U) and NTU value found in step 3 to calculate the required surface area (A): \( A = \frac{NTU*C_{min}}{U} \) Using the given overall heat transfer coefficient of 200 W/m²·K and the values calculated in previous steps, we can find the required surface area (A). By following these steps, you will be able to estimate the required surface area for this single-pass, cross-flow heat exchanger.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Cross-flow heat exchanger
A cross-flow heat exchanger is a widely used device for transferring heat between two fluids. In this type, the two fluids move perpendicular to each other. This design promotes effective heat transfer across the medium and is common in various engineering applications. The cross-flow arrangement allows for one fluid to be mixed while the other remains unmixed.
In our example, hot exhaust gases (mixed) heat water (unmixed). This design is beneficial as it offers a compact structure and improves heat transfer efficiency. The perpendicular movement helps achieve a greater temperature difference, which boosts the heat transfer rate. Cross-flow heat exchangers are ideal for situations where space is limited, and efficiency is essential.
Heat transfer coefficient
The heat transfer coefficient is a crucial parameter in determining a heat exchanger's efficiency. It measures the ability of the heat exchanger to transfer heat between the fluids. This coefficient depends on factors such as fluid flow properties, fluid types, and the surface area for heat exchange.
In our scenario, the overall heat transfer coefficient is given as 200 W/m²·K. This value is used in the calculation of the required surface area for the heat exchanger. A higher coefficient indicates a more efficient heat transfer process, minimizing energy losses, and optimizing the exchanger's performance. Understanding this value helps in designing an efficient heat exchanger setup, ensuring all energy transfer requirements are met effectively.
Effectiveness
Effectiveness ( ε ) is a measurement of how well a heat exchanger performs its function compared to the maximum possible heat transfer. The effectiveness of a heat exchanger gauges the ability to utilize the temperature difference driving the heat exchange process. For our case, it relates the actual heat transfer ( q ) to the maximum possible heat transfer ( q_{max} ).
The formula \( \epsilon = \frac{q}{q_{max}} \) gives insight into the energy efficiency of the process. A higher effectiveness value indicates a more efficient heat exchanger, closely approaching the maximum heat transfer potential. Calculating effectiveness is essential in assessing and improving the design and operation of heat exchangers, ensuring they meet practical and theoretical heating or cooling demands.
Number of transfer units (NTU)
The number of transfer units (NTU) is essential for understanding the heat exchanger's performance. It is a dimensionless measure that quantifies the heat exchanger size relative to the required heat transfer.
In cross-flow heat exchangers, the NTU value is important for evaluating the exchanger's ability to achieve the desired thermal performance. The equation \( NTU = -\frac{1}{1 - C^*}\ln{(1 - \epsilon(1-C^*))} \) connects NTU with the exchanger's effectiveness and capacity rate ratio. This relation helps engineers assess whether a given heat exchanger can achieve the intended temperature change.
NTU provides a way to compare different heat exchangers and optimize designs for improved efficiency. It is a crucial metric when considering adjustments or upgrades in heat exchanger systems.
Surface area calculation
The surface area is a critical factor in a heat exchanger's design, influencing its ability to transfer heat efficiently. Larger surface areas promote greater heat exchange between fluids. The necessary surface area calculation accounts for various parameters such as heat transfer coefficient and NTU.
The formula \( A = \frac{NTU*C_{min}}{U} \) allows determining the required surface area. Here, U represents the overall heat transfer coefficient, and C_{min} stands for the minimum heat capacity rate.
Accurate surface area estimation ensures that the heat exchanger operates efficiently without excessive costs or material usage. Proper calculation prevents oversizing, which could lead to unnecessary material expenditure, or undersizing, which would result in inadequate heat transfer, affecting the system's overall efficiency.

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Most popular questions from this chapter

In open heart surgery under hypothermic conditions, the patient's blood is cooled before the surgery and rewarmed afterward. It is proposed that a concentric tube, counterflow heat exchanger of length \(0.5 \mathrm{~m}\) be used for this purpose, with the thin-walled inner tube having a diameter of \(55 \mathrm{~mm}\). The specific heat of the blood is \(3500 \mathrm{~J} / \mathrm{kg} \cdot \mathrm{K}\). (a) If water at \(T_{h j}=60^{\circ} \mathrm{C}\) and \(\dot{m}_{h}=0.10 \mathrm{~kg} / \mathrm{s}\) is used to heat blood entering the exchanger at \(T_{c A}=18^{\circ} \mathrm{C}\) and \(\dot{m}_{c}=0.05 \mathrm{~kg} / \mathrm{s}\), what is the temperature of the blood leaving the exchanger? The overall heat transfer coefficient is \(500 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}\). (b) The surgeon may wish to control the heat rate \(q\) and the outlet temperature \(T_{c, 0}\) of the blood by altering the flow rate and/or inlet temperature of the water during the rewarming process. To assist in the development of an appropriate controller for the prescribed values of \(\hat{m}_{c}\) and \(T_{c \jmath}\), compute and plot \(q\) and \(T_{c, \rho}\) as a function of \(\dot{m}_{h}\) for \(0.05 \leq \dot{m}_{\mathrm{h}} \leq 0.20 \mathrm{~kg} / \mathrm{s}\) and values of \(T_{h, l}=50,60\), and \(70^{\circ} \mathrm{C}\). Since the dominant influence on the overall heat transfer coefficient is associated with the blood flow conditions, the value of \(U\) may be assumed to remain at \(500 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}\). Should certain operating conditions be excluded?

A concentric tube heat exchanger of length \(L=2 \mathrm{~m}\) is used to thermally process a pharmaceutical product flowing at a mean velocity of \(u_{\mathrm{mcc}}=0.1 \mathrm{~m} / \mathrm{s}\) with an inlet temperature of \(T_{c, i}=20^{\circ} \mathrm{C}\). The inner tube of diameter \(D_{i}=10 \mathrm{~mm}\) is thin walled, and the exterior of the outer tube \(\left(D_{o}=20 \mathrm{~mm}\right)\) is well insulated. Water flows in the annular region between the tubes at a mean velocity of \(u_{\mathrm{mhh}}=0.2 \mathrm{~m} / \mathrm{s}\) with an inlet temperature of \(T_{h, i}=60^{\circ} \mathrm{C}\). Properties of the pharmaceutical product are \(\nu=10 \times 10^{-6} \mathrm{~m}^{2} / \mathrm{s}, \quad k=0.25 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K}\), \(\rho=1100 \mathrm{~kg} / \mathrm{m}^{3}\), and \(c_{p}=2460 \mathrm{~J} / \mathrm{kg} \cdot \mathrm{K}\). Evaluate water properties at \(\bar{T}_{\mathrm{h}}=50^{\circ} \mathrm{C}\). (a) Determine the value of the overall heat transfer coefficient \(U\). (b) Determine the mean outlet temperature of the pharmaceutical product when the exchanger operates in the counterflow mode. (c) Determine the mean outlet temperature of the pharmaceutical product when the exchanger operates in the parallel-flow mode.

An ocean thermal energy conversion system is being proposed for electric power generation. Such a system is based on the standard power cycle for which the working fluid is evaporated, passed through a turbine, and subsequently condensed. The system is to be used in very special locations for which the oceanic water temperature near the surface is approximately \(300 \mathrm{~K}\), while the temperature at reasonable depths is approximately \(280 \mathrm{~K}\). The warmer water is used as a heat source to evaporate the working fluid, while the colder water is used as a heat sink for condensation of the fluid. Consider a power plant that is to generate \(2 \mathrm{MW}\) of electricity at an efficiency (electric power output per heat input) of \(3 \%\). The evaporator is a heat exchanger consisting of a single shell with many tubes executing two passes. If the working fluid is evaporated at its phase change temperature of \(290 \mathrm{~K}\), with ocean water entering at \(300 \mathrm{~K}\) and leaving at \(292 \mathrm{~K}\), what is the heat exchanger area required for the evaporator? What flow rate must be maintained for the water passing through the evaporator? The overall heat transfer coefficient may be approximated as \(1200 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}\).

It is proposed that the exhaust gas from a natural gas-powered electric generation plant be used to generate steam in a shell-and-tube heat exchanger with one shell and one tube pass. The steel tubes have a thermal conductivity of \(40 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K}\), an inner diameter of \(50 \mathrm{~mm}\), and a wall thickness of \(4 \mathrm{~mm}\). The exhaust gas, whose flow rate is \(2 \mathrm{~kg} / \mathrm{s}\), enters the heat exchanger at \(400^{\circ} \mathrm{C}\) and must leave at \(215^{\circ} \mathrm{C}\). To limit the pressure drop within the tubes, the tube gas velocity should not exceed \(25 \mathrm{~m} / \mathrm{s}\). If saturated water at \(11.7\) bar is supplied to the shell side of the exchanger, determine the required number of tubes

In a dairy operation, milk at a flow rate of \(250 \mathrm{~L} / \mathrm{h}\) and a cow-body temperature of \(38.6^{\circ} \mathrm{C}\) must be chilled to a safe-to-store temperature of \(13^{\circ} \mathrm{C}\) or less. Ground water at \(10^{\circ} \mathrm{C}\) is available at a flow rate of \(0.72 \mathrm{~m}^{3} / \mathrm{h}\). The density and specific heat of milk are \(1030 \mathrm{~kg} / \mathrm{m}^{3}\) and \(3860 \mathrm{~J} / \mathrm{kg} \cdot \mathrm{K}\), respectively. (a) Determine the UA product of a counterflow heat exchanger required for the chilling process. Determine the length of the exchanger if the inner pipe has a 50 -mm diameter and the overall heat transfer coefficient is \(U=1000 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}\). (b) Determine the outlet temperature of the water. (c) Using the value of \(U A\) found in part (a), determine the milk outlet temperature if the water flow rate is doubled. What is the outlet temperature if the flow rate is halved?

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