/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 54 Convection ovens operate on the ... [FREE SOLUTION] | 91Ó°ÊÓ

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Convection ovens operate on the principle of inducing forced convection inside the oven chamber with a fan. A small cake is to be baked in an oven when the convection feature is disabled. For this situation, the free convection coefficient associated with the cake and its pan is \(h_{\mathrm{fr}}=3 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}\). The oven air and wall are at temperatures \(T_{\infty}=T_{\text {sur }}=180^{\circ} \mathrm{C}\). Determine the heat flux delivered to the cake pan and cake batter when they are initially inserted into the oven and are at a temperature of \(T_{i}=24^{\circ} \mathrm{C}\). If the convection feature is activated, the forced convection heat transfer coefficient is \(h_{\mathrm{fo}}=27 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}\). What is the heat flux at the batter or pan surface when the oven is operated in the convection mode? Assume a value of \(0.97\) for the emissivity of the cake batter and pan.

Short Answer

Expert verified
In summary, the heat flux delivered to the cake pan and batter when operating in free convection mode is \(468\,\text{W}/\text{m}^{2}\) and in forced convection mode, it is \(4212\,\text{W}/\text{m}^{2}\).

Step by step solution

01

Calculate the heat flux in free convection mode

To find the heat flux in free convection mode, we'll need to use the free convection heat transfer coefficient, which is given as \(h_{fr} = 3\,\text{W}/\text{m}^{2}\cdot\text{K}\). The formula for heat flux, \(q\), in terms of the heat transfer coefficient, \(h\), is: \[q = h \cdot A \cdot (T_{sur} - T_{i})\] where \(A\) is the surface area of the cake pan and batter. We are not explicitly given the surface area in this problem, however, since we are asked to calculate the heat flux density, we can simplify the equation to: \[q' = h \cdot (T_{sur} - T_{i})\] We are given \(T_{sur} = 180^{\circ}\text{C}\) and \(T_i = 24^{\circ}\text{C}\). Now, we can plug in the known values and solve for \(q'\): \[q_{fr}' = h_{fr} \cdot (T_{sur} - T_i)\]
02

Calculate the heat flux in free convection mode

\[q_{fr}' = 3\,\text{W}/\text{m}^{2}\cdot\text{K} \cdot (180^{\circ}\text{C} - 24^{\circ}\text{C})\] \[q_{fr}' = 3\,\text{W}/\text{m}^{2}\cdot\text{K} \cdot (156\text{K})\] \[q_{fr}' = 468\,\text{W}/\text{m}^{2}\] So, the heat flux delivered to the cake pan and batter when operating in free convection mode is 468 W/m².
03

Calculate the heat flux in forced convection mode

To find the heat flux in forced convection mode, we'll need to use the forced convection heat transfer coefficient, which is given as \(h_{fo} = 27\,\text{W}/\text{m}^{2}\cdot\text{K}\). We can use the same formula for heat flux density as in Step 1. We have already calculated the temperature difference in the first step: \[q_{fo}' = h_{fo} \cdot (T_{sur} - T_i)\]
04

Calculate the heat flux in forced convection mode

\[q_{fo}' = 27\,\text{W}/\text{m}^{2}\cdot\text{K} \cdot (180^{\circ}\text{C} - 24^{\circ}\text{C})\] \[q_{fo}' = 27\,\text{W}/\text{m}^{2}\cdot\text{K} \cdot (156\text{K})\] \[q_{fo}' = 4212\,\text{W}/\text{m}^{2}\] So, the heat flux delivered to the cake pan and batter when operating in forced convection mode is 4212 W/m². In summary, the heat flux delivered to the cake pan and batter when operating in free convection mode is 468 W/m² and in forced convection mode, it is 4212 W/m².

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Convection Heat Transfer
Convection heat transfer is a fundamental mechanism by which thermal energy moves from one place to another through the movement of fluids, which can be liquids or gases. It is distinct from other forms of heat transfer like conduction, which involves direct contact between materials, and radiation, which involves heat transfer through electromagnetic waves.

Understanding convection is essential because it applies to various real-life scenarios, from industrial processes to everyday activities like heating a room or baking a cake. The basic idea is that warmer areas of a fluid will rise because they are less dense, while cooler, denser fluid will sink. This creates a circular motion known as a convection current.

In our context, the cake being baked is surrounded by air, which acts as the fluid transferring heat. The oven's air absorbs heat from the oven walls, rises, cools down after losing heat to the cake, and then sinks. In this way, thermal energy is transferred from the oven walls to the cake, heating it up.
Forced Convection
Forced convection occurs when an external force, such as a fan or a pump, propels the fluid, enhancing the heat transfer process. Unlike free convection, where the movement of the fluid relies on natural buoyancy forces, forced convection can significantly increase the efficiency of heat exchange by continually moving the fluid and introducing a fresh, warmer (or cooler) layer to the surface of the object being heated (or cooled).

An everyday example of forced convection is a convection oven, which uses a fan to circulate hot air and cook food more evenly and quickly. In the exercise we're examining, activating the convection feature in the oven increases the heat transfer coefficient to a higher value because the forced movement of air over the batter's surface leads to more efficient heat transfer.

Advantages of Forced Convection

  • Enhances heat transfer rate.
  • Provides uniform heating or cooling.
  • Can be controlled and maintained with the help of mechanical equipment.
The exercise demonstrates that with forced convection, the cake pan and batter experience a much higher heat flux, thus allowing the cake to bake faster.
Free Convection
Free convection, or natural convection, occurs when fluid motion is caused by buoyancy forces that result from density variations due to temperature differences within the fluid. There's no mechanical aid, and the movement of heat depends on the temperature gradients and the physical properties of the fluid.

In the baking scenario, when the convection feature of the oven is disabled, the air inside the oven moves solely due to the heat-induced density changes. This movement is inherently less efficient than forced convection because there is no external mechanism to enhance the heat transfer. The coefficient of heat transfer (\(h_{fr}\) in the exercise) is significantly lower in free convection, which results in a lower heat flux. This means it will take a longer time for the cake to receive the same amount of heat as in forced convection.

Characteristics of Free Convection

  • Occurs without external assistance.
  • Depends heavily on the geometry and orientation of the heated surface.
  • Typically a slower process compared to forced convection.
This distinction clearly shows why the cake would bake more slowly without the fan, with the heat flux calculated to be much lower in free convection mode.

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Most popular questions from this chapter

The heat flux through a wood slab \(50 \mathrm{~mm}\) thick, whose inner and outer surface temperatures are 40 and \(20^{\circ} \mathrm{C}\), respectively, has been determined to be \(40 \mathrm{~W} / \mathrm{m}^{2}\). What is the thermal conductivity of the wood?

Pressurized water \(\left(p_{\text {in }}=10\right.\) bar, \(\left.T_{\text {in }}=110^{\circ} \mathrm{C}\right)\) enters the bottom of an \(L=10\)-m-long vertical tube of diameter \(D=100 \mathrm{~mm}\) at a mass flow rate of \(\dot{m}=1.5 \mathrm{~kg} / \mathrm{s}\). The tube is located inside a combustion chamber, resulting in heat transfer to the tube. Superheated steam exits the top of the tube at \(p_{\text {out }}=7\) bar, \(T_{\text {out }}=600^{\circ} \mathrm{C}\). Determine the change in the rate at which the following quantities enter and exit the tube: (a) the combined thermal and flow work, (b) the mechanical energy, and (c) the total energy of the water. Also, (d) determine the heat transfer rate, \(q\). Hint: Relevant properties may be obtained from a thermodynamics text.

An inexpensive food and beverage container is fabricated from 25 -mm-thick polystyrene \((k=0.023 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K})\) and has interior dimensions of \(0.8 \mathrm{~m} \times 0.6 \mathrm{~m} \times 0.6 \mathrm{~m}\). Under conditions for which an inner surface temperature of approximately \(2^{\circ} \mathrm{C}\) is maintained by an ice-water mixture and an outer surface temperature of \(20^{\circ} \mathrm{C}\) is maintained by the ambient, what is the heat flux through the container wall? Assuming negligible heat gain through the \(0.8 \mathrm{~m} \times\) \(0.6 \mathrm{~m}\) base of the cooler, what is the total heat load for the prescribed conditions?

A \(50 \mathrm{~mm} \times 45 \mathrm{~mm} \times 20 \mathrm{~mm}\) cell phone charger has a surface temperature of \(T_{s}=33^{\circ} \mathrm{C}\) when plugged into an electrical wall outlet but not in use. The surface of the charger is of emissivity \(\varepsilon=0.92\) and is subject to a free convection heat transfer coefficient of \(h=4.5 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}\). The room air and wall temperatures are \(T_{\infty}=22^{\circ} \mathrm{C}\) and \(T_{\text {sur }}=20^{\circ} \mathrm{C}\), respectively. If electricity costs \(C=\$ 0.18 / \mathrm{kW} \cdot \mathrm{h}\), determine the daily cost of leaving the charger plugged in when not in use.

The diameter and surface emissivity of an electrically heated plate are \(D=300 \mathrm{~mm}\) and \(\varepsilon=0.80\), respectively. (a) Estimate the power needed to maintain a surface temperature of \(200^{\circ} \mathrm{C}\) in a room for which the air and the walls are at \(25^{\circ} \mathrm{C}\). The coefficient characterizing heat transfer by natural convection depends on the surface temperature and, in units of \(\mathrm{W} / \mathrm{m}^{2} \cdot \mathrm{K}\), may be approximated by an expression of the form \(h=0.80\left(T_{s}-T_{\infty}\right)^{1 / 3}\). (b) Assess the effect of surface temperature on the power requirement, as well as on the relative contributions of convection and radiation to heat transfer from the surface.

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