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Under conditions for which the same room temperature is maintained by a heating or cooling system, it is not uncommon for a person to feel chilled in the winter but comfortable in the summer. Provide a plausible explanation for this situation (with supporting calculations) by considering a room whose air temperature is maintained at \(20^{\circ} \mathrm{C}\) throughout the year, while the walls of the room are nominally at \(27^{\circ} \mathrm{C}\) and \(14^{\circ} \mathrm{C}\) in the summer and winter, respectively. The exposed surface of a person in the room may be assumed to be at a temperature of \(32^{\circ} \mathrm{C}\) throughout the year and to have an emissivity of \(0.90\). The coefficient associated with heat transfer by natural convection between the person and the room air is approximately \(2 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}\).

Short Answer

Expert verified
The person feels chilled in the winter and comfortable in the summer due to the difference in net heat loss or gain caused by radiation and natural convection. In winter, the person loses more heat due to radiation as the wall temperature is lower than in summer. This difference in heat loss between summer and winter, mainly due to radiation, accounts for the differing comfort levels experienced by the person.

Step by step solution

01

Identify the knowns and unknowns

We know: - Room air temperature: \(T_{air} = 20^\circ \mathrm{C}\) - Wall temperature in summer: \(T_{wall,s} = 27^\circ \mathrm{C}\) - Wall temperature in winter: \(T_{wall,w} = 14^\circ \mathrm{C}\) - Person's surface temperature: \(T_{body} = 32^\circ \mathrm{C}\) - Person's surface emissivity: \(\epsilon = 0.90\) - Heat transfer coefficient for natural convection: \(h = 2 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}\) Objective: - Analyze the heat loss or gain in summer and winter due to radiation and natural convection.
02

Heat exchange due to radiation

First, let's analyze the heat exchange due to radiation between the person's body and the walls. We use the Stefan-Boltzmann law. The formula for the rate of heat exchange due to radiation: \[Q_{rad} = A \epsilon \sigma (T_1^4 - T_2^4)\] where, - A: surface area of the person's body, - \(\epsilon\): emissivity of the person's body, - \(\sigma\): Stefan-Boltzmann constant \(\approx 5.67 \times 10^{-8} \mathrm{W} / \mathrm{m}^{2} \cdot \mathrm{K}^{4}\), - \(T_1\) is the temperature of the person's body, and - \(T_2\) is the temperature of the surrounding walls. In our case, the heat exchange due to radiation looks like: 1. For summer: \(Q_{rad,s} = A \epsilon \sigma (T_{body}^4 - T_{wall,s}^4)\) 2. For winter: \(Q_{rad,w} = A \epsilon \sigma (T_{body}^4 - T_{wall,w}^4)\) Let's calculate the values of \(Q_{rad,s}\) and \(Q_{rad,w}\).
03

Heat exchange due to natural convection

Now, let's analyze the heat exchange due to natural convection between the person's body and room air. We use the formula for the rate of heat exchange due to natural convection: \[Q_{conv} = A h (T_{body} - T_{air})\] In our case, the heat exchange due to natural convection looks like: \[Q_{conv} = A h (T_{body} - T_{air})\] Let's calculate the value of \(Q_{conv}\).
04

Net heat loss or gain

Finally, let's determine the net heat loss or gain in summer and winter. 1. For summer: \(Q_{net,s} = Q_{rad,s} + Q_{conv}\) 2. For winter: \(Q_{net,w} = Q_{rad,w} + Q_{conv}\) Compare the net heat loss or gain in summer and winter to understand why the person feels chilled in winter and comfortable in summer. By calculating these values and comparing the net heat loss or gain in summer and winter, the person feels chilled in the winter because they lose more heat in winter due to radiation and natural convection compared to summer. The difference in heat loss due to radiation caused by the differing wall temperatures in summer and winter mainly explains the situation.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Radiative Heat Exchange
When we talk about radiative heat exchange, we're discussing how heat energy moves in the form of electromagnetic waves, without needing a medium to travel through. This type of heat transfer can occur in a vacuum and is how the Sun's energy reaches the Earth.

Consider a person sitting in a room: their body, at a higher temperature, emits infrared radiation, which can be absorbed, reflected, or transmitted by the surrounding walls and objects. The amount of heat exchanged through this process depends on the temperature difference, the surface's emissivity (a measure of how well it emits infrared energy), and the Stefan-Boltzmann constant. In our exercise, the person's body has a constant emissivity, indicating its effectiveness at emitting thermal radiation relative to a perfect black body.

The feeling of being colder in winter despite a constant room air temperature is partly because the walls, at a lower winter temperature, absorb more of this radiative heat from the person compared to summer. The walls, being colder, also emit less radiative heat back to the person, resulting in a net heat loss from the person that is greater in winter.
Natural Convection
Natural convection is a type of heat transfer that occurs due to the movement of fluids (which can be gases or liquids) caused by temperature differences within the fluid itself. When part of a fluid is heated, it becomes less dense and rises, while cooler, denser fluid sinks, creating a natural circulation pattern.

In the context of our exercise, the person's body warms the air around it, causing it to rise and be replaced by cooler air from other parts of the room. This circulation leads to heat being transferred away from the body. The rate of heat transfer depends on the temperature difference between the body and the surrounding air and a value called the heat transfer coefficient, which considers how easily heat is transferred from the surface to the fluid. A higher heat transfer coefficient indicates more effective convection.

In both the summer and winter scenarios, despite the constant temperature of the room air, the overall sensation of warmth or chilliness can also be influenced by the rate at which this convective heat loss occurs.
Stefan-Boltzmann Law
The Stefan-Boltzmann Law is fundamental in understanding radiant heat exchange. It states that the energy radiated per unit surface area of a black body is directly proportional to the fourth power of its absolute temperature.

The law is represented mathematically as: \[ Q_{rad} = A \epsilon \sigma (T^4) \] where \( Q_{rad} \) is the radiative heat transfer, \( A \) is the area of the emitting surface, \( \epsilon \) is the emissivity of the material, \( \sigma \) is the Stefan-Boltzmann constant, and \( T \) is the absolute temperature of the body in kelvins.

In the problem we're examining, the Stefan-Boltzmann Law helps explain why a person loses more heat by radiation during winter. The fourth power dependency on temperature means that as the wall temperature drops in winter, the radiation heat loss from the person to the walls increases significantly. This increased loss of heat makes the person feel chilled even though the air temperature remains the same.

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Most popular questions from this chapter

An internally reversible refrigerator has a modified coefficient of performance accounting for realistic heat transfer processes of $$ \mathrm{COP}_{m}=\frac{q_{\text {in }}}{\dot{W}}=\frac{q_{\text {in }}}{q_{\text {out }}-q_{\text {in }}}=\frac{T_{c, i}}{T_{h, i}-T_{c, i}} $$ where \(q_{\text {in }}\) is the refrigerator cooling rate, \(q_{\text {out }}\) is the heat rejection rate, and \(\dot{W}\) is the power input. Show that \(\mathrm{COP}_{m}\) can be expressed in terms of the reservoir temperatures \(T_{c}\) and \(T_{h}\), the cold and hot thermal resistances \(R_{L, c}\) and \(R_{t, h}\), and \(q_{\text {in }}\), as $$ \mathrm{COP}_{m}=\frac{T_{c}-q_{\mathrm{in}} R_{\mathrm{tot}}}{T_{h}-T_{c}+q_{\mathrm{in}} R_{\mathrm{tot}}} $$ where \(R_{\mathrm{tot}}=R_{t, c}+R_{t, h}\). Also, show that the power input may be expressed as $$ \dot{W}=q_{\mathrm{in}} \frac{T_{h}-T_{c}+q_{\mathrm{in}} R_{\mathrm{id \textrm {t }}}}{T_{c}-q_{\mathrm{in}} R_{\mathrm{tot}}} $$

An instrumentation package has a spherical outer surface of diameter \(D=100 \mathrm{~mm}\) and emissivity \(\varepsilon=0.25\). The package is placed in a large space simulation chamber whose walls are maintained at \(77 \mathrm{~K}\). If operation of the electronic components is restricted to the temperature range \(40 \leq T \leq 85^{\circ} \mathrm{C}\), what is the range of acceptable power dissipation for the package? Display your results graphically, showing also the effect of variations in the emissivity by considering values of \(0.20\) and \(0.30\).

An overhead 25-m-long, uninsulated industrial steam pipe of \(100-\mathrm{mm}\) diameter is routed through a building whose walls and air are at \(25^{\circ} \mathrm{C}\). Pressurized steam maintains a pipe surface temperature of \(150^{\circ} \mathrm{C}\), and the coefficient associated with natural convection is \(h=10\) \(\mathrm{W} / \mathrm{m}^{2} \cdot \mathrm{K}\). The surface emissivity is \(\varepsilon=0.8\). (a) What is the rate of heat loss from the steam line? (b) If the steam is generated in a gas-fired boiler operating at an efficiency of \(\eta_{f}=0.90\) and natural gas is priced at \(C_{g}=\$ 0.02\) per \(\mathrm{MJ}\), what is the annual cost of heat loss from the line?

The temperature controller for a clothes dryer consists of a bimetallic switch mounted on an electrical heater attached to a wall-mounted insulation pad. The switch is set to open at \(70^{\circ} \mathrm{C}\), the maximum dryer air temperature. To operate the dryer at a lower air temperature, sufficient power is supplied to the heater such that the switch reaches \(70^{\circ} \mathrm{C}\left(T_{\text {set }}\right)\) when the air temperature \(T\) is less than \(T_{\text {set. }}\). If the convection heat transfer coefficient between the air and the exposed switch surface of \(30 \mathrm{~mm}^{2}\) is \(25 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}\), how much heater power \(P_{e}\) is required when the desired dryer air temperature is \(T_{\infty}=50^{\circ} \mathrm{C}\) ?

A wall is made from an inhomogeneous (nonuniform) material for which the thermal conductivity varies through the thickness according to \(k=a x+b\), where \(a\) and \(b\) are constants. The heat flux is known to be constant. Determine expressions for the temperature gradient and the temperature distribution when the surface at \(x=0\) is at temperature \(T_{1}\).

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