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It is well known that, although two materials are at the same temperature, one may feel cooler to the touch than the other. Consider thick plates of copper and glass, each at an initial temperature of \(300 \mathrm{~K}\). Assuming your finger to be at an initial temperature of \(310 \mathrm{~K}\) and to have thermophysical properties of \(\rho=1000 \mathrm{~kg} / \mathrm{m}^{3}, c=4180 \mathrm{~J} / \mathrm{kg} \cdot \mathrm{K}\), and \(k=0.625 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K}\), determine whether the copper or the glass will feel cooler to the touch.

Short Answer

Expert verified
Copper will feel cooler due to its higher thermal conductivity.

Step by step solution

01

Understand the Problem

We have two materials, copper and glass, both initially at 300 K, and we want to determine which one feels cooler when touched. Your finger initially is at 310 K with given thermophysical properties, and the difference in sensation is based on how fast each material conducts heat away from the finger.
02

Recall Heat Transfer Concepts

To determine which material feels cooler, consider each material's thermal conductivity: copper has higher thermal conductivity than glass, so it conducts heat away from the finger faster. The sensation of coolness is related to the rate of heat transfer: higher rate means feeling cooler.
03

Calculate Thermal Conductivity Impact

Copper's thermal conductivity is approximately 400 W/m·K, while glass has around 1 W/m·K. Given the stark difference, copper will remove heat more quickly due to its higher thermal conductivity.
04

Analyze Finger's Heat Loss

Calculate and compare the rate of heat transfer from the finger to each material: The rate, or H (heat transfer per unit area), is modeled by Fourier's law: \[ H = k \cdot \frac{T_{finger} - T_{material}}{d} \]For this comparison, direct calculation isn't needed since relative k (thermal conductivity) comparison should suffice given identical thicknesses (d) for both materials.
05

Conclusion from Theoretical Analysis

As thermal conductivity chiefly determines the initial heat transfer rate, copper will cool the finger faster than glass, resulting in a cooler sensation. While the specific heat and density of the glass and copper may contribute to longer-term heat transfer, the initial sensation of coolness is dominated by thermal conductivity.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Thermal Conductivity
Thermal conductivity is a fundamental property of materials that indicates how easily heat can flow through them. It is denoted by the symbol \( k \) and measured in units of Watts per meter per Kelvin (W/m·K). Materials with high thermal conductivity, such as metals like copper, can transfer heat very efficiently.
Copper, for instance, has a thermal conductivity around 400 W/m·K. This means that it can quickly transport heat away from a warmer object, like your finger in this exercise, resulting in a cooler touch sensation. On the other hand, glass, with a thermal conductivity of about 1 W/m·K, is much less effective at conducting heat.
This is why, even though two objects are initially at the same temperature, they can feel different to the touch. High thermal conductivity materials remove heat rapidly, giving us the sensation of coolness, while low thermal conductivity materials retain heat near their surface. Thus, understanding thermal conductivity helps us predict how different materials will feel when touched.
Fourier's Law
Fourier's Law is a cornerstone in the study of heat transfer. It provides a formula to quantify the rate of heat transfer through a material. The law states that the heat transfer rate (\( H \)) depends directly on the thermal conductivity \( k \), the temperature difference between the touching surfaces, and inversely on the thickness of the material.
The mathematical expression for Fourier's Law is given by:
  • \( H = k \cdot \frac{T_{finger} - T_{material}}{d} \)
where \( H \) is the heat transfer per unit area, \( T_{finger} \) and \( T_{material} \) are the temperatures of your finger and the material, respectively, and \( d \) is the thickness of the material.
In our exercise, this law helps explain why copper feels cooler than glass. The higher thermal conductivity of copper means that it can quickly transfer heat away from your finger, causing a more pronounced cooling effect. Essentially, Fourier's Law helps us understand how quickly and efficiently different materials can exchange heat.
Thermophysical Properties
Thermophysical properties refer to characteristics of materials that define their behavior in response to changes in temperature. These include properties like density \( \rho \), specific heat capacity \( c \), and indeed, thermal conductivity \( k \).
  • Density (\( \rho \)) is the mass per unit volume of a material.
  • Specific heat capacity (\( c \)) is the amount of heat required to change the temperature of a unit mass of a substance by one degree Celsius.
  • Thermal conductivity (\( k \)) measures a material's ability to conduct heat.
In the context of our exercise, these properties of your finger (\( \rho=1000 \text{ kg/m}^3 \), \( c=4180 \text{ J/kg·K} \), and \( k=0.625 \text{ W/m·K} \)) interact with those of copper and glass to determine the sensation experienced upon touch.
The thermophysical properties can influence how heat moves through a material. For instance, the specific heat capacity affects how much energy the material can absorb before its temperature changes. While these properties are crucial for understanding the full picture of heat transfer, the initial cool touch sensation, as described in this exercise, is more directly influenced by the thermal conductivity of the materials involved.

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Most popular questions from this chapter

The inner surface of a plane wall is insulated while the cuter surface is exposed to an airstream at \(T_{\text {a }}\). The wall is af a uniform temperature corresponding to that of the ainstream, Sudilenly, a radiation heat source is switched cn applying a uniform fiux \(q_{e}^{*}\) to the outer surface. (a) Shetch and label, on \(T-x\) coordinates, the temperature distributions: initial, steady-state, and at two intermediate times. (b) Sketch the heat flux at the outer surface \(q_{,}^{\prime \prime}\left(L_{n} t\right)\) as a function of time.

A thick steel slab \(\left(\rho=7800 \mathrm{~kg} / \mathrm{m}^{3}, c=480 \mathrm{~J} / \mathrm{kg} \cdot \mathrm{K}\right.\), \(k=50 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K})\) is initially at \(300^{\circ} \mathrm{C}\) and is cooled by water jets impinging on one of its surfaces. The temperature of the water is \(25^{\circ} \mathrm{C}\), and the jets maintain an extremely large, approximately uniform convection coefficient at the surface. Assuming that the surface is maintained at the temperature of the water throughout the cooling. how long will it take for the temperature to reich \(50^{\circ} \mathrm{C}\) at a distance of \(25 \mathrm{~mm}\) from the surface?

Copper-coated, epoxy-filled fiberglass circuit boards are treated by heating a stack of them under high pressare as sown in the sketch. The perpose of the pressing-heuting operation is to cure the eposy that bonds the fiberglass sheets, imparting siffness to the boards. The stack. riferted to as a book, is comprised of 10 boards and 11 pressing plates, which prevent epoxy from flowing between the boards and impar a-smooth finish to the cured boards. In order to perform simplified thermal analyses, it is reasonable to approximule the book as having an effective themal conductivity \((k)\) and an effective thermal capacitance \(\left(\rho c_{p}\right)\). Calculate the effective propertics if each of the boards and plates has a tickness of \(2.36 \mathrm{~mm}\) and the following thermophysical properties: board (b) \(\rho_{b}=1000 \mathrm{~kg} / \mathrm{m}^{\prime}, c_{p,}=1500\) \(\mathrm{W} / \mathrm{Kg} \cdot \mathrm{K}, k_{p}=0.30 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K}_{;}\)plate \((p) \rho_{p}=8\left(000 \mathrm{~kg} / \mathrm{m}^{3}\right.\). \(c_{v}=480 \mathrm{~J} / \mathrm{kg} \cdot \mathrm{K}, k_{p}=12 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K}\).

A molded plastic product \(\left(\rho=1200 \mathrm{~kg} / \mathrm{m}^{3} . c=\right.\) \(1500 \mathrm{~J} / \mathrm{kg} \cdot \mathrm{K}, k=0.30 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K})\) is cooled by exposing one surface to an array of air jets, while the opposite surface is well insulated. The product may be approximated as a slab of thickness \(L=60 \mathrm{~mm}\). which is initially at a uniform temperature of \(T_{i}=\) \(80 \% \mathrm{C}\). The air jets are at a temperature of \(T_{2}=20^{\circ} \mathrm{C}\) and provide a uniform convection coefficient of \(h=\) \(100 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}\) at the cooled surface. Using a finite-difference solution with a space increment of \(\Delta x=6 \mathrm{~mm}\), determine temperatures at the cooled and insulated surfaces after 1 hour of exposure to the gas jets.

A long wire of diameter \(D=1 \mathrm{~mm}\) is submerged it an oil bath of temperature \(T_{s}=25^{\circ} \mathrm{C}\). The wire has at electrical resistance per unit length of \(R_{e}^{2}=0.01 \mathrm{f} \mathrm{Nm}\) If a current of \(I=100 \mathrm{~A}\) flows throegh the wirt and the convection coefficient is \(h=500 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}\). what is the steady-state temperature of the wire? From the time the current is applied, how long does it take for the wire to reach a temperature that is within \(1^{\circ} \mathrm{C}\) of the steady-state value? The properties of the wire are \(\rho\) a \(8000 \mathrm{~kg} / \mathrm{m}^{3}, c=500 \mathrm{~J} / \mathrm{kg} \cdot \mathrm{K}\), and \(\mathrm{k}=20 \mathrm{~W} / \mathrm{m}-\mathrm{K}\).

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