/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 2 The inner surface of a plane wal... [FREE SOLUTION] | 91Ó°ÊÓ

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The inner surface of a plane wall is insulated while the cuter surface is exposed to an airstream at \(T_{\text {a }}\). The wall is af a uniform temperature corresponding to that of the ainstream, Sudilenly, a radiation heat source is switched cn applying a uniform fiux \(q_{e}^{*}\) to the outer surface. (a) Shetch and label, on \(T-x\) coordinates, the temperature distributions: initial, steady-state, and at two intermediate times. (b) Sketch the heat flux at the outer surface \(q_{,}^{\prime \prime}\left(L_{n} t\right)\) as a function of time.

Short Answer

Expert verified
Sketch temperature and heat flux curves: initial horizontal, steady linear, curves for intermediate states; heat flux starts at zero, rises to \( q_e^* \).

Step by step solution

01

Understanding the Problem

The problem involves a plane wall initially at a uniform temperature exposed to a radiation heat source that applies a heat flux \( q_e^* \) to the outer surface. We need to sketch the temperature distribution at various times, and the heat flux over time at the outer surface.
02

Initial Temperature Distribution

Initially, the wall is at a uniform temperature equal to the air stream temperature \( T_a \). Therefore, the initial temperature distribution is a horizontal line across the entire thickness of the wall when plotted on a \( T-x \) graph.
03

Steady-State Temperature Distribution

For the steady-state condition, the temperature will decrease linearly from a maximum at the insulated surface to a minimum at the exposed surface. This linear temperature profile results from the constant heat flux \( q_e^* \) applied and the perfect insulation on one side.
04

Intermediate Time Temperature Distribution

At intermediate times, the temperature distribution starts deviating from the initial horizontal line, as it begins curving to approach the steady-state linear distribution. Early on, the curve is close to flat near the insulation and sharper near the heat source. As time progresses, this becomes a smoother curve.
05

Sketching Temperature Distributions

On the \( T-x \) graph, sketch the following: a horizontal line for initial distribution at \( T_a \), a linear downward-sloping line for steady-state, and two curves for intermediate distributions showing gradual transition from the initial to the steady-state.
06

Sketching Heat Flux Over Time

The heat flux at the outer surface, \( q^{ ext{''}}(L,t) \), starts at zero immediately after the radiation source is switched on, then increases as the surface heats up. It eventually reaches \( q_e^* \) when a steady-state is achieved. Sketch a curve starting from zero, rising over time, and leveling off at \( q_e^* \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Transient Heat Conduction
Transient heat conduction occurs when the temperature within an object changes with time. In our problem, this is observed once the radiation source is switched on. Initially, the entire wall is at a uniform temperature corresponding to that of the air stream. As time progresses, and heat from the radiation source flows in, the temperature distribution evolves. This evolution can be visualized on a graph showing temperature vs. distance through the wall. Initially, the line is flat, indicating a uniform temperature. Over time, a curve begins to form as the temperature at the outer surface rises fastest due to direct exposure to the heat source. Meanwhile, the insulated inner surface changes temperature more slowly, creating a gradient. This transient phase is crucial for understanding how materials handle sudden changes in thermal environments, which is key in designing materials that face varying heat conditions. Tools like the lumped capacitance method or numerical simulations are often used to predict temperature profiles during these transient periods.
Steady-State Conduction
Steady-state conduction describes a condition where the temperature distribution no longer changes with time. In this exercise, after the radiation heat source has been on for some time, the wall reaches a steady temperature distribution. In steady-state, the temperature decreases linearly across the wall, from the insulated inner surface to the outer surface exposed to the airstream. This direct linear decrease reflects the constant heat flux imposed by the heat source on one side and the insulation on the other. Understanding steady-state conduction is essential because it defines the maximum thermal stress a material can withstand under continuous exposure to heat. Engineers often strive to achieve or approximate steady-state conditions when designing systems for sustainable long-term use.
Radiation Heat Transfer
Radiation heat transfer is the process by which heat is emitted as electromagnetic waves, often in the infrared spectrum. In our scenario, the radiation heat source starts to apply a uniform flux to the outer surface of the wall. This scenario showcases the efficiency and reach of radiation as a heat transfer method. Unlike conduction or convection, radiation does not require a medium—making it useful for applications like heating systems and solar panels. It’s important to note how the wall initially responds to this heat application. The surface directly exposed to the radiation heats up more quickly, highlighting the directional nature of radiation. Mastery of radiation heat transfer principles is crucial in industries like aerospace and electronics, where thermal management is critical.
Thermal Insulation
Thermal insulation is used to reduce heat transfer and maintain desired temperature levels within spaces or objects. In our problem, the wall's inner surface is perfectly insulated, preventing any heat loss or gain from this side. This insulation plays a crucial role throughout the transient and steady-state phases, ensuring that all heat transfer dynamics occur through the outer surface instead. This means, even as the outer surface temperature changes due to the radiation source, the inner side remains thermally isolated. Understanding insulation helps in designing efficient thermal management systems for buildings, appliances, and industrial processes. It ensures that energy is conserved, and desired temperatures are maintained, leading to energy savings and comfort.

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Most popular questions from this chapter

A chip that is of length \(L=5 \mathrm{~mm}\) on a side and thick. ness \(t=I \mathrm{~mm}\) is encased in a ceramic substrate, and its exposed surface is convectively cooled by a diefectric liquid for which \(h=150 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}\) and \(T_{\mathrm{z}}=20^{\circ} \mathrm{C}\). In the off-mode the chip is in thermal equilibrium with the coolant \(\left(T_{i}=T_{*}\right)\). When the chip is energized, however, its Icmperafure increases until a new steady-state is established. For purpeises of analysis, the cnergized chip is characterized by uniform volumetric heating with \(q=9 \times 10^{6} \mathrm{~W} / \mathrm{m}^{3}\). Assuming an infinite contacl resistance between the chip and substrate and negligible conduction resistance within the chip. determine the steady-state chip temperature \(T_{f}\). Following activation of the chip, how long does it take to come within \(1^{-1} C\) of this temperature? The chip density and specific heat are \(\rho=2000 \mathrm{~kg} / \mathrm{m}^{3}\) and \(c=700 \mathrm{~J} / \mathrm{kg} \cdot \mathrm{K}\), respectively.

A very thick slab with thermal diffusivity \(5.6 \mathrm{x}\) \(10^{-6} \mathrm{~m}^{2} / \mathrm{s}\) and thermal conductivity \(20 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K}\) is ini tially at a uniform temperature of \(325^{\circ} \mathrm{C}\). Sudklenly, tte surface is exposed to a ccolant at \(15^{\circ} \mathrm{C}\) for which the convection heat transfer coefficient is \(100 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}\). (a) Determine temperatures at the surface and at a depth of \(45 \mathrm{~mm}\) after 3 min have elapsed. (b) Compute and plot temperature histories \((0 \leq t \leq\) \(3(x)\) s) at \(x=0)\) and \(x=45 \mathrm{~mm}\) for the following parametric variations: (i) \(\alpha=5.6 \times 10^{-7} .5 .6 \times\) \(10^{-6}\), and \(5.6 \times 10^{-3} \mathrm{~m}^{2} / \mathrm{s}\); and (ii) \(k=2,20\), and \(200 \mathrm{~W} / \mathrm{m}-\mathrm{K}\).

A long wire of diameter \(D=1 \mathrm{~mm}\) is submerged it an oil bath of temperature \(T_{s}=25^{\circ} \mathrm{C}\). The wire has at electrical resistance per unit length of \(R_{e}^{2}=0.01 \mathrm{f} \mathrm{Nm}\) If a current of \(I=100 \mathrm{~A}\) flows throegh the wirt and the convection coefficient is \(h=500 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}\). what is the steady-state temperature of the wire? From the time the current is applied, how long does it take for the wire to reach a temperature that is within \(1^{\circ} \mathrm{C}\) of the steady-state value? The properties of the wire are \(\rho\) a \(8000 \mathrm{~kg} / \mathrm{m}^{3}, c=500 \mathrm{~J} / \mathrm{kg} \cdot \mathrm{K}\), and \(\mathrm{k}=20 \mathrm{~W} / \mathrm{m}-\mathrm{K}\).

Batch processes are often used in chemical and pharmaceutical operations to achicve a desired chemical composition for the final product and typically involve a transient heating operation to take the product from room temperature to the desired process temperature. Consider a situation for which a chemical of density \(\rho=\) \(1200 \mathrm{~kg} / \mathrm{m}^{3}\) and specific heat \(c=2200 \mathrm{~J} / \mathrm{kg}-\mathrm{K}\) occupies a volume of \(V=2.25 \mathrm{~m}^{3}\) in an insulated vessel. The chemical is to be heated from room temperature, \(T_{f}=\) \(300 \mathrm{~K}\), to a process temperature of \(T=450 \mathrm{~K}\) by passing saturated steam at \(T_{h}=500 \mathrm{~K}\) through a coiled, thinwalled, 20 -mm-diameter tube in the vessel. Steam condensation within the tube maintains an interior convection cocfficient of \(h_{y}=10,000 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}\), while the highly agitated liquid in the stirned vessel maintains an outside convection coefficient of \(h_{e}=2000 \mathrm{~W} / \mathrm{m}^{2}-\mathrm{K}\). If the chemical is to be heated from 300 to \(450 \mathrm{~K}\) in 60 minutes, what is the required length \(L\) of the submerged tubing?

A molded plastic product \(\left(\rho=1200 \mathrm{~kg} / \mathrm{m}^{3} . c=\right.\) \(1500 \mathrm{~J} / \mathrm{kg} \cdot \mathrm{K}, k=0.30 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K})\) is cooled by exposing one surface to an array of air jets, while the opposite surface is well insulated. The product may be approximated as a slab of thickness \(L=60 \mathrm{~mm}\). which is initially at a uniform temperature of \(T_{i}=\) \(80 \% \mathrm{C}\). The air jets are at a temperature of \(T_{2}=20^{\circ} \mathrm{C}\) and provide a uniform convection coefficient of \(h=\) \(100 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}\) at the cooled surface. Using a finite-difference solution with a space increment of \(\Delta x=6 \mathrm{~mm}\), determine temperatures at the cooled and insulated surfaces after 1 hour of exposure to the gas jets.

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